Chapter 5: Problem 44
Express each of the following in simplest radical form. All variables represent positive real numbers. \(\frac{\sqrt{5 y}}{\sqrt{18 x^{3}}}\)
Short Answer
Expert verified
\(\frac{\sqrt{10y}}{6x^{3/2}}\)
Step by step solution
01
Simplify Each Square Root
Begin by simplifying the expression under each square root separately. For the numerator \(\sqrt{5y}\), \(5y\) is already in simplest form since 5 and y are not perfect squares. For the denominator \(\sqrt{18x^3}\), we simplify it to \(\sqrt{9 \cdot 2 \cdot x^3} = \sqrt{9} \cdot \sqrt{2} \cdot \sqrt{x^3}\). Since \(\sqrt{9} = 3\) and \(\sqrt{x^3} = x^{3/2}\), the denominator becomes \(3\sqrt{2}x^{3/2}\).
02
Rewrite the Expression
Substitute the simplified forms back into the original fraction. The expression becomes \(\frac{\sqrt{5y}}{3\sqrt{2}x^{3/2}}\).
03
Rationalize the Denominator
To simplify the fraction further, rationalize the denominator. Multiply both the numerator and the denominator by \(\sqrt{2}x^{3/2}\) to eliminate the square root in the denominator. This gives us: \(\frac{\sqrt{5y} \cdot \sqrt{2}x^{3/2}}{3\sqrt{2}x^{3/2} \cdot \sqrt{2}x^{3/2}} = \frac{\sqrt{10yx^{3}}}{6x^3}\).
04
Simplify the Expression
Since the expression \(\frac{\sqrt{10yx^{3}}}{6x^3}\) has \(x^3\) inside the square root and \(x^3\) in the denominator, we can simplify by reducing \(x^3\) under the square root with \(x^3\) in the denominator. This simplifies the expression to \(\frac{\sqrt{10y}}{6x^{1.5}}\), which simplifies to \(\frac{\sqrt{10y}}{6x^{3/2}}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Roots
Square roots are mathematical operations that help us find a number which, when multiplied by itself, gives the original number. For instance, the square root of 16 is 4 because
For example, \(5\) and \(y\) are not perfect squares, while \(9\) is a perfect square since \(3 \times 3 = 9\). That's why simplifying \(\sqrt{9x^3}\) becomes \(3x^{3/2}\) because \(\sqrt{9} = 3\) and \(\sqrt{x^3} = x^{3/2}\). Working through these simplifications lets us work with cleaner, more manageable expressions that are easier to work with in equations.
- 4 multiplied by 4 gives 16.
For example, \(5\) and \(y\) are not perfect squares, while \(9\) is a perfect square since \(3 \times 3 = 9\). That's why simplifying \(\sqrt{9x^3}\) becomes \(3x^{3/2}\) because \(\sqrt{9} = 3\) and \(\sqrt{x^3} = x^{3/2}\). Working through these simplifications lets us work with cleaner, more manageable expressions that are easier to work with in equations.
Rationalizing Denominators
Rationalizing the denominator is a technique used to eliminate the square root found in the denominator of a fraction. This process involves multiplying both the numerator and the denominator by a value which will make the square root in the denominator disappear, thus making the calculation easier and the expression prettier.
For instance, take the expression \(\frac{\sqrt{5y}}{3\sqrt{2}x^{3/2}}\). To rationalize, we multiply both parts of the fraction by \(\sqrt{2}x^{3/2}\), effectively getting rid of the square root from the denominator. The result is a new, rational expression:
For instance, take the expression \(\frac{\sqrt{5y}}{3\sqrt{2}x^{3/2}}\). To rationalize, we multiply both parts of the fraction by \(\sqrt{2}x^{3/2}\), effectively getting rid of the square root from the denominator. The result is a new, rational expression:
- \(\frac{\sqrt{10yx^{3}}}{6x^3}\).
Simplified Radical Form
When an expression is in its simplest form, it means it cannot be further reduced or made simpler. For instance, the expression \(\frac{\sqrt{10yx^{3}}}{6x^3}\) needed further simplification. We noticed \(x^3\) appears both in the denominator and under the radical, enabling us to cancel them out.
- This leaves us with: \(\frac{\sqrt{10y}}{6x^{3/2}}\).
- Recognizing perfect squares or cubes in the numbers and variables.
- Eliminating any radicals in the denominator to achieve a true "fraction" form.