Chapter 4: Problem 28
Solve each equation. $$ \frac{x}{2 x^{2}+5 x}-\frac{x}{2 x^{2}+7 x+5}=\frac{2}{x^{2}+x} $$
Short Answer
Expert verified
The solutions are \( x = -4 + \sqrt{6} \) and \( x = -4 - \sqrt{6} \).
Step by step solution
01
Factorize Denominators
Factorize all the denominators. For \( 2x^2 + 5x \), factor out common factor:\[ 2x^2 + 5x = x(2x + 5) \]For \( 2x^2 + 7x + 5 \), factor by grouping: \[ 2x^2 + 7x + 5 = (2x + 5)(x + 1) \]For \( x^2 + x \), factor out common factor:\[ x^2 + x = x(x + 1) \]
02
Find Common Denominator
The common denominator is the combination of all distinct factors from each expression:\[ x(2x + 5)(x + 1) \]
03
Rewrite Each Term with Common Denominator
Rewrite each fraction with the common denominator:- \( \frac{x}{2x^2 + 5x} = \frac{x(x + 1)}{x(2x + 5)(x + 1)} \)- \( \frac{x}{2x^2 + 7x + 5} = \frac{x(2x + 5)}{x(2x + 5)(x + 1)} \)- \( \frac{2}{x^2 + x} = \frac{2(2x + 5)}{x(2x + 5)(x + 1)} \)
04
Combine the Left Side
Combine the fractions on the left side:\[ \frac{x(x + 1) - x(2x + 5)}{x(2x + 5)(x + 1)} = \frac{x^2 + x - (2x^2 + 5x)}{x(2x + 5)(x + 1)} \]Simplify the numerator:\[ = \frac{x^2 + x - 2x^2 - 5x}{x(2x + 5)(x + 1)} = \frac{-x^2 - 4x}{x(2x + 5)(x + 1)} \]
05
Set Equal to Right Side and Simplify
Set the simplified left side equal to the right side:\[ \frac{-x^2 - 4x}{x(2x + 5)(x + 1)} = \frac{2(2x + 5)}{x(2x + 5)(x + 1)} \]Cross multiply and simplify:\[ -x^2 - 4x = 2(2x + 5) \]Expand the right side:\[ -x^2 - 4x = 4x + 10 \]Rearrange the terms to solve for \( x \): \[ -x^2 - 8x - 10 = 0 \]
06
Solve the Quadratic Equation
Use the quadratic formula to solve \( -x^2 - 8x - 10 = 0 \):\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Here, \( a = -1, b = -8, c = -10 \).Calculate discriminant:\[ b^2 - 4ac = (-8)^2 - 4(-1)(-10) = 64 - 40 = 24 \]\[ x = \frac{-(-8) \pm \sqrt{24}}{2(-1)} = \frac{8 \pm 2\sqrt{6}}{-2} \]\[ x = -4 \pm \sqrt{6} \]
07
Check for Valid Solutions
Check if both solutions are valid by ensuring the original denominators remain non-zero:For \( x = -4 + \sqrt{6} \) and \( x = -4 - \sqrt{6} \), check each term in the original equation. Since none of the denominators become zero, both are valid solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Polynomials
Factoring polynomials is the process of breaking down a polynomial into simpler components called factors, which when multiplied together give the original polynomial. It simplifies problems and helps solve equations. For instance, in our equation, the polynomial \( 2x^2 + 5x \) is factored by taking out the common factor \( x \):
- \( 2x^2 + 5x = x(2x + 5) \)
- Split into parts: \( (2x^2 + 5x) + (2x + 5) \)
- Factor the pairs: \( (2x + 5)(x + 1) \)
Quadratic Formula
The quadratic formula is a powerful tool used to find the solutions of quadratic equations that take the standard form \( ax^2 + bx + c = 0 \). The formula
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- \( -x^2 - 8x - 10 = 0 \)
- \( a = -1, b = -8, c = -10 \)
- Discriminant \( = 64 - 40 = 24 \)
- \( x = -4 \pm \sqrt{6} \)
Common Denominators
In solving rational equations, rewriting each fraction with a common denominator is a crucial step. This allows us to combine or compare fractions more easily. For our problem, we saw different expressions with varying denominators:
- \( x(2x + 5) \)
- \( (2x + 5)(x + 1) \)
- \( x(x + 1) \)
- \( x(2x + 5)(x + 1) \)
Cross Multiplication
Cross multiplication is a technique used to solve equations involving two fractions set to each other. It simplifies finding \( x \) by eliminating the denominators through
- multiplication across the equal sign.
- \( \frac{-x^2 - 4x}{x(2x + 5)(x + 1)} = \frac{2(2x + 5)}{x(2x + 5)(x + 1)} \)
- \( -x^2 - 4x = 2(2x + 5) \)