Chapter 11: Problem 76
Solve each problem by using a system of equations. One solution contains \(30 \%\) alcohol and a second solution contains \(70 \%\) alcohol. How many liters of each solution should be mixed to make 10 liters containing \(40 \%\) alcohol?
Short Answer
Expert verified
Mix 7.5 liters of 30% alcohol solution with 2.5 liters of 70% alcohol solution.
Step by step solution
01
Define the Variables
Let's define our variables: let \( x \) be the liters of the 30\% alcohol solution, and \( y \) be the liters of the 70\% alcohol solution. These are the unknowns we want to determine.
02
Set Up the Equations
We have two conditions to use: the volume and the concentration.1. The total volume must be 10 liters: \( x + y = 10 \).2. The alcohol concentration requirement: \( 0.3x + 0.7y = 0.4 \times 10 \). This equation accounts for the amount of alcohol from both solutions totaling to 40\% of 10 liters.
03
Simplify the System
We have the system:\( x + y = 10 \) \( 0.3x + 0.7y = 4 \).The second equation is derived from \( 0.3x + 0.7y = 4 \) because 40\% of 10 is 4 liters of pure alcohol.
04
Substitute to Solve for One Variable
Solve the first equation for one variable, say \( x \):\( x = 10 - y \).Substitute \( x = 10 - y \) into the second equation: \( 0.3(10 - y) + 0.7y = 4 \).
05
Simplify and Solve for y
Expand and simplify: \( 3 - 0.3y + 0.7y = 4 \) Combine like terms: \( 0.4y = 1 \) Solve for \( y \):\( y = \frac{1}{0.4} = 2.5 \).
06
Find the Value of x
Substitute \( y = 2.5 \) into \( x = 10 - y \): \( x = 10 - 2.5 = 7.5 \).
07
Solution Verification
Check: - Total liters: \( 7.5 + 2.5 = 10 \), correct.- Alcohol content: \( 0.3 \times 7.5 + 0.7 \times 2.5 = 2.25 + 1.75 = 4 \), which is 40\% of 10 liters. This confirms that the solution is accurate.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Algebraic Solutions
Algebraic solutions are a powerful way to solve problems involving unknowns. They allow us to translate real-world situations into mathematical equations that we can work with. In the problem we're discussing, we need to determine how much of two different alcohol solutions are required to create a final solution with a specific alcohol concentration.
To do this, we defined two variables:
To do this, we defined two variables:
- \( x \): the number of liters of the 30% alcohol solution
- \( y \): the number of liters of the 70% alcohol solution
Concentration Problems
Concentration problems involve mixing different substances with known concentrations to achieve a desired concentration. They are common in chemistry and other sciences. The key is understanding that each component contributes a specific amount of the concentrated substance to the final mixture.
In our exercise, the goal was to mix two solutions with different alcohol concentrations to achieve a final mixture with 40% alcohol. Each solution contributes to the final concentration based on its own concentration and volume.
In our exercise, the goal was to mix two solutions with different alcohol concentrations to achieve a final mixture with 40% alcohol. Each solution contributes to the final concentration based on its own concentration and volume.
- The 30% solution contributes \( 0.3x \) liters of alcohol.
- The 70% solution contributes \( 0.7y \) liters of alcohol.
Percentage Calculations
Percentage calculations are vital in solving concentration problems. They help in determining how much of a particular component is present in a mixture compared to the whole.
In the problem, converting percentages to decimals (e.g., 30% as 0.3, 70% as 0.7) allows us to use them in equations more effectively. The calculation of 40% of 10 liters to find 4 liters is also crucial. We use percentage calculations to ensure that each part contributes correctly to the whole.
When mixing solutions to obtain a desired percentage, it's important to remember:
In the problem, converting percentages to decimals (e.g., 30% as 0.3, 70% as 0.7) allows us to use them in equations more effectively. The calculation of 40% of 10 liters to find 4 liters is also crucial. We use percentage calculations to ensure that each part contributes correctly to the whole.
When mixing solutions to obtain a desired percentage, it's important to remember:
- The total percentage translates to the fraction of the pure substance within the mixture.
- Each component's contribution must total the final desired percentage.