Chapter 5: Problem 68
Expand each binomial. $$(b-5)^{4}$$
Short Answer
Expert verified
(b - 5)^4 = b^4 - 20b^3 + 150b^2 - 500b + 625
Step by step solution
01
- Understand the Binomial Theorem
To expand \( (b - 5)^4 \), we'll use the binomial theorem, which states: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k}a^{n-k}b^k \]. Here, a = b, and b = -5, and n = 4.
02
- Identify the Binomial Coefficients
The binomial coefficients for \( n = 4 \), can be found using \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\), where k ranges from 0 to 4. Here are the calculations: \[ \binom{4}{0} = 1, \ \binom{4}{1} = 4, \ \binom{4}{2} = 6, \ \binom{4}{3} = 4, \ \binom{4}{4} = 1 \].
03
- Expand Using the Binomial Theorem
Using these coefficients, expand \( (b - 5)^4 \): \[(b - 5)^4 = \binom{4}{0}b^{4}(−5)^0 + \binom{4}{1}b^{3}(−5)^1 + \binom{4}{2}b^{2}(−5)^2 + \binom{4}{3}b^{1}(−5)^3 + \binom{4}{4}b^{0}(−5)^4 \].
04
- Calculate Each Term
Now calculate each term: \[ \binom{4}{0}b^{4}(−5)^0 = 1 \times b^4 \times 1 = b^4 \] \[ \binom{4}{1}b^{3}(−5)^1 = 4 \times b^3 \times (-5) = -20b^3 \] \[ \binom{4}{2}b^{2}(−5)^2 = 6 \times b^2 \times 25 = 150b^2 \] \[ \binom{4}{3}b^{1}(−5)^3 = 4 \times b \times (-125) = -500b \] \[ \binom{4}{4}b^{0}(−5)^4 = 1 \times 1 \times 625 = 625 \].
05
- Combine All Terms
Combine all calculated terms together to get the final expanded form: \[ (b - 5)^4 = b^4 - 20b^3 + 150b^2 - 500b + 625 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Theorem
The Binomial Theorem is a powerful tool in algebra that allows us to expand expressions that are raised to a power. The theorem states: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k}a^{n-k}b^k \]. Here, \(a\) and \(b\) are any numbers, and \(n\) is a non-negative integer. This formula gives us a way to calculate each term in the expansion. It uses binomial coefficients \( \binom{n}{k} \), which we will cover in the next section. The Binomial Theorem can simplify complex polynomial expansions. For instance, expanding \((b - 5)^4\) utilizes the same principles, where \(a = b\), \(b = -5\), and \(n = 4\). It breaks down complex multiplication into manageable terms.
Binomial Coefficients
Binomial coefficients \( \binom{n}{k} \) are key components in the Binomial Theorem. They are calculated using the formula: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]. The exclamation mark denotes factorial, which is the product of all positive integers up to that number. For example, \(4! = 4 \times 3 \times 2 \times 1 = 24\). For \((b - 5)^4\), we compute the coefficients as follows:
- \( \binom{4}{0} = 1 \)
- \( \binom{4}{1} = 4 \)
- \( \binom{4}{2} = 6 \)
- \( \binom{4}{3} = 4 \)
- \( \binom{4}{4} = 1 \)
Polynomial Expansion
Polynomial expansion is the process of expressing a polynomial that is raised to a power as a sum of simpler terms. The Binomial Theorem provides a systematic method to achieve this. To expand \((b - 5)^4\), follow these steps:
Second term: \( 4 \times b^3 \times (-5) = -20b^3 \)
Third term: \( 6 \times b^2 \times 25 = 150b^2 \)
Fourth term: \( 4 \times b \times (-125) = -500b \)
Fifth term: \( 1 \times 1 \times 625 = 625 \) This step-by-step approach simplifies the polynomial expansion process, making it easier to understand and apply in other problems.
- Identify \(a = b\), \(b = -5\), and \(n = 4\).
- Use the binomial coefficients \( \binom{4}{k} \) for \(k = 0, 1, 2, 3, 4\).
- Calculate each term using \( \binom{4}{k} b^{4-k} (-5)^k \).
- Combine the terms.
Second term: \( 4 \times b^3 \times (-5) = -20b^3 \)
Third term: \( 6 \times b^2 \times 25 = 150b^2 \)
Fourth term: \( 4 \times b \times (-125) = -500b \)
Fifth term: \( 1 \times 1 \times 625 = 625 \) This step-by-step approach simplifies the polynomial expansion process, making it easier to understand and apply in other problems.