Problem 100 Solve each problem. Sheila's a... [FREE SOLUTION]

Chapter 5: Problem 100

Solve each problem. Sheila's annual bonus in dollars for selling $n$ life insurance policies is given by the function $$B(n)=0.1 n^{2}+3 n+50 .$$ Find $B(20)$, her bonus for selling 20 policies.

Short Answer

Expert verified

Sheila's bonus for selling 20 policies is $150.

Step by step solution

- Understand the Function

The function provided is Sheila's bonus formula in terms of the number of policies sold, which is given as \[ B(n) = 0.1n^2 + 3n + 50 \].

- Substitute Value for n

To find Sheila's bonus for selling 20 policies, substitute $ n = 20 $ into the function: \[ B(20) = 0.1(20)^2 + 3(20) + 50 \].

- Calculate the Square Term

Calculate $ 0.1(20)^2 $: \[ 0.1 \times 400 = 40 \].

- Calculate the Linear Term

Calculate $ 3(20) $: \[ 3 \times 20 = 60 \].

- Add All Terms

Add the results from steps 3 and 4 along with the constant term: \[ B(20) = 40 + 60 + 50 = 150 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions

A quadratic function is a type of polynomial function characterized by its highest exponent being a square term. These functions look like this:

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91影视

Solve each problem. Sheila's annual bonus in dollars for selling \(n\) life insurance policies is given by the function $$B(n)=0.1 n^{2}+3 n+50 .$$ Find \(B(20)\), her bonus for selling 20 policies.

Short Answer

Step by step solution

- Understand the Function

- Substitute Value for n

- Calculate the Square Term

- Calculate the Linear Term

- Add All Terms

Key Concepts

Quadratic Functions

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