/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Solve each system. $$\begin{arr... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system. $$\begin{array}{l}2 x-4 y+6 z=12 \\\6 x-12 y+18 z=36 \\\\-x+2 y-3 z=-6\end{array}$$

Short Answer

Expert verified
The system has infinite solutions in parametric form: \(x = 2t - 3s + 6\), \(y = t\), \(z = s\)

Step by step solution

01

Identify the System of Equations

The system of equations to solve is given as: 1) \(2x - 4y + 6z = 12\) 2) \(6x - 12y + 18z = 36\) 3) \(-x + 2y - 3z = -6\)
02

Simplify the Equations

Note that equation 2 is just 3 times equation 1, thus it does not provide new information. Hence, we can ignore equation 2. We now have: 1) \(2x - 4y + 6z = 12\) 2) \(-x + 2y - 3z = -6\)
03

Solve for One Variable

From equation 2, solve for \(x\): \(-x + 2y - 3z = -6 => x = 2y - 3z + 6\)
04

Substitute x into Equation 1

Substitute \(x = 2y - 3z + 6\) into \(2x - 4y + 6z = 12\): \[2(2y - 3z + 6) - 4y + 6z = 12\] \[4y - 6z + 12 - 4y + 6z = 12\] This simplifies to 12 = 12, which is true for all \(y\) and \(z\), so there are infinite solutions.
05

Solution in Parametric Form

Use parameters to express the solution. Let \(y = t\), then: \(z = s\) \(x = 2t - 3s + 6\) So the solution in parametric form is: \(x = 2t - 3s + 6\), \(y = t\), \(z = s\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

linear algebra
Linear algebra is a branch of mathematics that focuses on solving equations involving linear relationships.
In the context of systems of linear equations, we're dealing with equations that can be written in the form of lines in multidimensional space. These can be represented in matrix form, making it easier to apply methods for finding solutions.
The given problem is a system of linear equations:
1) \(2x - 4y + 6z = 12\)
2) \(6x - 12y + 18z = 36\)
3) \(-x + 2y - 3z = -6\)
Notice that linear algebra helps us to understand and solve these equations systematically. Let's explore some basic concepts that are related to solving such systems:
  • Linear Equations: An equation that makes a straight line when it is graphed. In our case, each equation represents a plane in three-dimensional space.
  • System of Linear Equations: A set of linear equations with the same variables. Here, we have three equations involving the variables \(x, y,\) and \(z\).
  • Matrix Representation: These equations can also be represented in matrix form, which often simplifies the process of solving them.
By using linear algebra, we simplify our work and make it more systematic through well-defined methods and tools.
parametric solutions
A parametric solution expresses the variables of a system as functions of one or more parameters.
In our problem, we ended up with the following system after simplification:
1) \(2x - 4y + 6z = 12\)
2) \(-x + 2y - 3z = -6\)
We used these steps:
  • Identify Dependent Variables: We consider some variables as dependent and express them in terms of others. For example, solve for \(x\) from one equation.
  • Introduce Parameters: We introduce parameters, \(t\) and \(s\), to represent \(y\) and \(z\).
  • Express in Terms of Parameters: Substituting the parameterized values back in, we get the general solution.
In our example, let \(y = t\) and \(z = s\). Then, using \(x = 2y - 3z + 6\), we can write:
  • \(x = 2t - 3s + 6\)
  • \(y = t\)
  • \(z = s\)
Therefore, the parametric form of the solution is:
\(x = 2t - 3s + 6\), \(y = t\), \(z = s\)
This gives us a clear, flexible way to represent all possible solutions of the system.
infinite solutions
A system of linear equations can have infinite solutions when the equations are dependent.
That means they represent the same plane or line in space. In our case, we saw that:
1) \(2x - 4y + 6z = 12\)
2) \(6x - 12y + 18z = 36\)
Here, equation 2 is simply a multiple of equation 1. Hence, these two equations describe the same plane and do not add new information. This dependency suggests that the solutions are not unique; rather, there are infinitely many solutions.
To identify the infinite set of solutions, we use parameters (as shown earlier), to express each variable.
To summarize:
  • Dependent Equations: Two or more equations that do not provide new information about the system.
  • Consistent System: A system where all equations represent the same geometric entity.
  • Infinite Solutions: There are countless solutions to the system, expressed in a parametric form.
This infinite nature is significant because it shows the flexibility in satisfying all equations in the system simultaneously. Through this method, students can get a deeper understanding of the relationships between variables in dependent systems.

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Most popular questions from this chapter

Solve each system using the Gauss-Jordan elimination method. $$ \begin{array}{r} x+y=6 \\ -x+y=8 \end{array} $$

Fill in the blanks in the augmented matrices using the indicated row operations. $$ \left[\begin{array}{ll|l} 0 & 3 & 6 \\ 1 & 2 & 5 \end{array}\right] $$ $$ \left[\begin{array}{ll|l} 0 & 3 & 6 \end{array}\right] \quad R_{1} \leftrightarrow R_{2} $$

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