/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Find the slope of the line that ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the slope of the line that contains each of the following pairs of points. \(\left(\frac{3}{4},-1\right),\left(-\frac{1}{2},-\frac{1}{2}\right)\)

Short Answer

Expert verified
The slope is \(-\frac{2}{5}\).

Step by step solution

01

Identify the points

The given points are \(\frac{3}{4}, -1\) and \(-\frac{1}{2}, -\frac{1}{2}\). Label them as \(x_1, y_1\) and \(x_2, y_2\). So, \(x_1 = \frac{3}{4}\), \(y_1 = -1\), \(x_2 = -\frac{1}{2}\), and \(y_2 = -\frac{1}{2}\).
02

Recall the slope formula

The formula to find the slope \(m\) of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) is \[m = \frac{y_2 - y_1}{x_2 - x_1} \].
03

Calculate the differences

Calculate \(y_2 - y_1\) and \(x_2 - x_1\).\(y_2 - y_1 = -\frac{1}{2} - (-1) = -\frac{1}{2} + 1 = \frac{1}{2}\) and \(x_2 - x_1 = -\frac{1}{2} - \frac{3}{4} = -\frac{1}{2} - \frac{3}{4} = -\frac{5}{4}\).
04

Calculate the slope

Substitute \(y_2 - y_1 = \frac{1}{2}\) and \(x_2 - x_1 = -\frac{5}{4}\) into the slope formula \[m = \frac{\frac{1}{2}}{-\frac{5}{4}} = \frac{1}{2} * \frac{4}{-5} = \frac{4}{-10} = -\frac{2}{5} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordinate Geometry
Coordinat‪e geometry, also known as analytic geometry, is the study of geometry using a coordinate system. With this, we can describe geometric shapes such as lines and polygons using algebraic equations. In this context, we use ordered pairs \((x, y)\) to represent points on a plane. Each point is defined by its distance from two perpendicular lines called axes—the x-axis and the y-axis.
In our problem, the points given are (\(\frac{3}{4}\), -1) and (\(\frac{-1}{2}\), \(\frac{-1}{2}\)). By plotting these points on a Cartesian plane, we can visualize the line that connects them and better understand their relationship. Coordinate geometry forms the foundation upon which we can calculate other important measurements, like the slope of the line between two points.
The x and y coordinates tell us exactly where the points lie on the grid, making it crucial for slope calculation.
Slope Formula
The slope formula is a fundamental concept in coordinate geometry and is used to measure the steepness, incline, or grade of a line. It is expressed as:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Where \(m\) is the slope, \(x_1, y_1 \) are the coordinates of the first point, and \(x_2, y_2\) are the coordinates of the second point. That means it defines how much the y-coordinate changes for a unit change in the x-coordinate.
In our problem:
  • \(x_1 = \frac{3}{4}\)
  • \(y_1 = -1\)
  • \(x_2 = -\frac{1}{2}\)
  • \(y_2 = -\frac{1}{2}\)
We substitute these values into the slope formula to find the gradient of the line.
Difference of Coordinates
The difference of coordinates is another vital concept, which involves subtracting the corresponding coordinates of the two points.
First, calculate the difference in y-coordinates (\(y_2 - y_1\)):
\[ y_2 - y_1 = -\frac{1}{2} - (-1) = -\frac{1}{2} + 1 = \frac{1}{2} \]
Next, calculate the difference in x-coordinates (\(x_2 - x_1\)):
\[ x_2 - x_1 = -\frac{1}{2} - \frac{3}{4} = -\frac{1}{2} - \frac{3}{4} = -\frac{5}{4} \]
These differences are then used in the slope formula to find the slope between the two points. It's important to carefully handle signs and fractions in these calculations.
Fraction Operations
To find the slope, we often deal with fractions, so understanding fraction operations is crucial.
  • Addition/Subtraction: To add or subtract fractions, make sure the denominators are the same. Otherwise, find a common denominator and adjust the fractions accordingly.
  • Multiplication: Multiply the numerators together and the denominators together.
  • Division: Multiply by the reciprocal of the divisor.

In our problem, after finding the differences in coordinates, we get:
\[ m = \frac{\frac{1}{2}}{-\frac{5}{4}} \]
To divide fractions, we multiply by the reciprocal of the second fraction:
\[ m = \frac{1}{2} \times \frac{4}{-5} = \frac{4}{-10} = -\frac{2}{5} \]
Through this step-by-step process, you can confidently handle fractions and accurately determine the slope.

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Most popular questions from this chapter

Let \(f(x)=3 x-2, g(x)=-x^{2}+3 x-2,\) and \(h(x)=|x+2|\). Evaluate each expression. See Example 9. $$ \frac{h(-10)}{f(2)} $$

Find \(k\) so that the line through \((k, 3)\) and \((-2,0)\) has slope 3

Solve each problem. See Example 9. Heating water. The temperature of a cup of water is a linear function of the time that it is in the microwave. The temperature at 0 seconds is \(60^{\circ} \mathrm{F}\) and the temperature at 120 seconds is \(200^{\circ} \mathrm{F}\) a) Express the linear function in the form \(t=m s+b\) where \(t\) is the Fahrenheit temperature and \(s\) is the time in seconds. [Hint: Write the equation of the line through \((0,60) \text { and }(120,200) .]\) b) Use the linear function to determine the temperature at 30 seconds. c) Graph the linear function.

Find an equation of the line that goes through the given point and has the given slope. Give the answer in slope-intercept form. See Example 5 (-3, -1) with slope 6

Solve each problem. See Example 9. Depth and flow. When the depth of the water in the Tangipahoa River at Robert, Louisiana, is 9.14 feet, the flow is 1230 cubic feet per second ( \(\mathrm{ft}^{3} / \mathrm{sec}\) ). When the depth is 7.84 feet, the flow is \(826 \mathrm{ft}^{3} / \mathrm{sec} .\) (U.S. Geological Survey, www.usgs.gov). Let \(w\) represent the flow in cubic feet per second and \(d\) represent the depth in feet. a) Write the equation of the line through \((9.14,1230)\) and \((7.84,826)\) and express \(w\) in terms of \(d .\) Round to two decimal places. b) What is the flow when the depth is \(8.25 \mathrm{ft} ?\) c) Is the flow increasing or decreasing as the depth increases?

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