Chapter 2: Problem 83
Solve each inequality. Write the solution set using interval notation. $$1<|x+2|$$
Short Answer
Expert verified
The solution set is \( (-\infty, -3) \cup (-1, \infty) \).
Step by step solution
01
- Understand the Absolute Value Inequality
Given the inequality is: \( 1 < |x + 2| \). In absolute value inequalities, \( |A| > c \) means that either \( A > c \) or \( A < -c \).
02
- Set Up Two Inequalities
For \( |x + 2| > 1 \), we set up two inequalities: 1. \( x + 2 > 1 \) 2. \( x + 2 < -1 \)
03
- Solve the First Inequality
Solve \( x + 2 > 1 \): Subtract 2 from both sides: \( x > 1 - 2 \). Thus, \( x > -1 \).
04
- Solve the Second Inequality
Solve \( x + 2 < -1 \): Subtract 2 from both sides: \( x < -1 - 2 \). Thus, \( x < -3 \).
05
- Combine the Solution Sets
Combine the results from steps 3 and 4. The solution set is: \( x < -3 \) or \( x > -1 \).
06
- Write the Solution in Interval Notation
In interval notation, the solution set is: \( (-\infty, -3) \cup (-1, \infty) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value Inequalities
Absolute value inequalities are a bit different from regular inequalities. The absolute value of a number is its distance from zero on the number line, regardless of direction. In math, it's represented as \(|A|\) where \(|A|\) is always positive or zero.
When we have an inequality like \( |x+2| > 1 \), it means that the value inside the absolute value brackets (\( x+2 \)) is more than 1 unit away from zero, in either direction.
This gives us two possibilities: either \( x+2 \) is greater than 1 (meaning it's more than 1 unit to the right of zero), or \( x+2 \) is less than -1 (meaning it's more than 1 unit to the left of zero).
So, we translate \( |x+2| > 1 \) into two separate inequalities: \( x + 2 > 1 \) and \( x + 2 < -1 \). Solving these inequalities separately will give us the solution set for the original problem.
When we have an inequality like \( |x+2| > 1 \), it means that the value inside the absolute value brackets (\( x+2 \)) is more than 1 unit away from zero, in either direction.
This gives us two possibilities: either \( x+2 \) is greater than 1 (meaning it's more than 1 unit to the right of zero), or \( x+2 \) is less than -1 (meaning it's more than 1 unit to the left of zero).
So, we translate \( |x+2| > 1 \) into two separate inequalities: \( x + 2 > 1 \) and \( x + 2 < -1 \). Solving these inequalities separately will give us the solution set for the original problem.
Interval Notation
After solving inequalities, it's important to represent the solution set clearly. Interval notation is a method used to denote a range or set of numbers along the number line. This form of notation is compact and easy to understand.
For this exercise, we found two conditions for \( x \: \).
For \( x < -3 \), the interval is \( (-\backslash \backslash infty, -3) \).
For \( x > -1 \), the interval is \( (-1, \backslash \backslash infty) \).
Since these are two separate intervals (i.e., there are two non-overlapping ranges), we use the union operator (\( \backslash \backslash cup \)) to combine them. Therefore, the final answer in interval notation is \( (-\backslash \backslash infty, -3) \backslash \backslash cup (-1, \backslash \backslash infty) \).
For this exercise, we found two conditions for \( x \: \).
- First inequality: \( x > -1 \)
- Second inequality: \( x < -3 \)
For \( x < -3 \), the interval is \( (-\backslash \backslash infty, -3) \).
For \( x > -1 \), the interval is \( (-1, \backslash \backslash infty) \).
Since these are two separate intervals (i.e., there are two non-overlapping ranges), we use the union operator (\( \backslash \backslash cup \)) to combine them. Therefore, the final answer in interval notation is \( (-\backslash \backslash infty, -3) \backslash \backslash cup (-1, \backslash \backslash infty) \).
Compound Inequalities
Compound inequalities occur when two separate inequalities are joined by the word 'and' or 'or'. They describe a range of values for the variable that satisfy both inequalities.
There are two main types of compound inequalities:
There are two main types of compound inequalities:
- 'And' compound inequalities, which represent values that satisfy both conditions. For example, \(-3 < x < 1\) translates to \(-3 < x \) 'and' \( x < 1\).
- 'Or' compound inequalities, which represent values that satisfy at least one of the conditions. For example, \(x < -3 \) 'or' \( x > -1 \) in our exercise means any value less than -3 or greater than -1 is part of the solution set.