/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 88 Determine whether each equation ... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether each equation is true or false. $$ \frac{\log _{2}(16)}{\log _{2}(4)}=\log _{2}(4) $$

Short Answer

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Step by step solution

01

- Understand the Logarithmic Terms

Identify the terms in the equation. We have \(\frac{\text{log}_{2}(16)}{\text{log}_{2}(4)} = \text{log}_{2}(4)\).
02

- Simplify the Logarithm in the Numerator

Calculate \(\text{log}_{2}(16)\). Since \16 = 2^4\, we rewrite this as \(\text{log}_{2}(2^4)\). Using the property \(\text{log}_{b}(a^c) = c \text{log}_{b}(a)\), we get \(\text{log}_{2}(16) = 4 \text{log}_{2}(2)\). Since \(\text{log}_{2}(2) = 1\), we have \(\text{log}_{2}(16) = 4\).
03

- Simplify the Logarithm in the Denominator

Calculate \(\text{log}_{2}(4)\). Since \4 = 2^2\, we can rewrite it as \(\text{log}_{2}(2^2)\). Using the property \(\text{log}_{b}(a^c) = c \text{log}_{b}(a)\), we get \(\text{log}_{2}(4) = 2 \text{log}_{2}(2)\). Since \(\text{log}_{2}(2) = 1\), we have \(\text{log}_{2}(4) = 2\).
04

- Divide the Simplified Terms

Now divide the simplified terms: \(\frac{\text{log}_{2}(16)}{\text{log}_{2}(4)} = \frac{4}{2} = 2\).
05

- Compare the Result to the Right Side

Compare the division result \2\ to \(\text{log}_{2}(4) \). As calculated earlier, \(\text{log}_{2}(4) = 2\). Therefore, \2 = 2\, the equation is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Properties
Logarithms are a unique way to represent exponents. They have special properties that help simplify complex equations. Here are some important properties:
- **Product Property**: \(\text{log}_b(x \times y) = \text{log}_b(x) + \text{log}_b(y)\)
- **Quotient Property**: \(\text{log}_b(\frac{x}{y}) = \text{log}_b(x) - \text{log}_b(y)\)
- **Power Property**: \(\text{log}_b(x^y) = y \times \text{log}_b(x)\)
In our exercise, we used the Power Property repeatedly to simplify the terms. This helped in breaking down complex logarithmic terms into simpler numbers.
Simplifying Logarithms
When working with logarithms, you often need to simplify expressions. Simplifying makes solving equations easier. In the exercise: \(\frac{\text{log}_{2}(16)}{\text{log}_{2}(4)} = \text{log}_{2}(4)\)
We simplified each term separately.
1. **Numerator**: \(\text{log}_{2}(16)\)
- Recognized that \16 = 2^4\
- Used Power Property: \(\text{log}_{2}(2^4) = 4 \text{log}_{2}(2)\)
- Since \(\text{log}_{2}(2) = 1\), it became \4\
2. **Denominator**: \(\text{log}_{2}(4)\)
- Recognized that \4 = 2^2\
- Used Power Property: \(\text{log}_{2}(2^2) = 2 \text{log}_{2}(2)\)
- Since \(\text{log}_{2}(2) = 1\), it became \2\
Simplifying logarithms this way makes crossing out terms and solving the equations straightforward.
Base-2 Logarithms
Base-2 logarithms (\text{log}_2()) are commonly used in computer science. They're handy for understanding binary systems, data storage, and algorithms.
In our exercise, we used \(\text{log}_{2}\) to represent logarithms with base 2.
Here's a quick breakdown:
- \(\text{log}_{2}(16) = 4\) because \16 = 2^4\
- \(\text{log}_{2}(4) = 2\) because \4 = 2^2\
These base-2 logarithms converted complex term shows into simple integers. For example, understanding that \( \text{log}_{2}(2) = 1 \) was pivotal in correctly simplifying the terms. This exercise helps you grasp the simplicity and utility of base-2 logarithms in real-world contexts.

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Most popular questions from this chapter

Solve each problem. Logistic growth. If a rancher has one cow with a contagious disease in a herd of \(1000,\) then the time in days \(t\) for \(n\) of the cows to become infected is modeled by $$t=-5 \cdot \ln \left(\frac{1000-n}{999 n}\right)$$ Find the number of days that it takes for the disease to spread to \(100,200,998,\) and 999 cows. This model, called a logistic growth model, describes how a disease can spread very rapidly at first and then very slowly as nearly all of the population has become infected. See the accompanying figure. (Figure cannot copy)

Solve each problem. Graph the functions \(y_{1}=\log _{2}(x)\) and \(y_{2}=3^{x-4}\) on the same coordinate system and use the intersect feature to find the points of intersection of the curves. Round to two decimal places. [ Hint: To graph \(y=\log _{2}(x),\) use the base-change formula to write the function as \(y=\ln (x) / \ln (2) .]\)

The U.S.G.S. measures the quality of a water sample by using the diversity index \(d\), given by \(d=-\left[p_{1} \cdot \log _{2}\left(p_{1}\right)+p_{2} \cdot \log _{2}\left(p_{2}\right)+\cdots+p_{n} \cdot \log _{2}\left(p_{n}\right)\right]\), where \(n\) is the number of different taxons (biological classifications) represented in the sample and \(p_{1}\) through \(p_{n}\) are the percentages of organisms in each of the \(n\) taxons. The value of \(d\) ranges from 0 when all organisms in the water sample are the same to some positive number when all organisms in the sample are different. If two- thirds of the organisms in a water sample are in one taxon and one-third of the organisms are in a second taxon, then \(n=2\) and $$ d=-\left[\frac{2}{3} \log _{2}\left(\frac{2}{3}\right)+\frac{1}{3} \log _{2}\left(\frac{1}{3}\right)\right] $$ Use the properties of logarithms to write the expression on the right-hand side as \(\log _{2}\left(\frac{3 \sqrt{2}}{2}\right) .\) (In Section 11.4 you will learn how to evaluate a base-2 logarithm using a calculator.)

Solve each equation. $$3^{x}=7$$

Graph \(y_{1}=3^{x}, y_{2}=3^{x-1},\) and \(y_{3}=3^{x-2}\) on the same coordinate system. What can you say about the graph of \(y=3^{x-h}\) for any real number \(h ?\)

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