/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Free solutions & answers for Algebra for College Students Chapter 11 - (Page 7) [step by step] | 91Ó°ÊÓ

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Problem 65

For each equation, find the exact solution and an approximate solution when appropriate. Round approximate answers to three decimal places. See the Strategy for Solving Exponential and Logarithmic $$\ln (2 x-1)-\ln (x+1)=\ln (5)$$

Problem 66

For each equation, find the exact solution and an approximate solution when appropriate. Round approximate answers to three decimal places. See the Strategy for Solving Exponential and Logarithmic $$\log (x-4)-\log (x+5)=1$$

Problem 71

For each equation, find the exact solution and an approximate solution when appropriate. Round approximate answers to three decimal places. See the Strategy for Solving Exponential and Logarithmic $$2 \cdot \ln (x)=\ln (2)+\ln (5 x-12)$$

Problem 75

Use a calculator to solve each equation. Round answers to four decimal places. $$3=10^{x}$$

Problem 76

Use a calculator to solve each equation. Round answers to four decimal places. $$10^{x}=0.03$$

Problem 77

Use a calculator to solve each equation. Round answers to four decimal places. $$10^{x}=\frac{1}{2}$$

Problem 77

For each equation, find the exact solution and an approximate solution when appropriate. Round approximate answers to three decimal places. See the Strategy for Solving Exponential and Logarithmic $$\log _{7}\left(x^{2}+6 x+8\right)-\log _{7}(x+2)=\log _{7}(3)$$

Problem 78

Use a calculator to solve each equation. Round answers to four decimal places. $$75=10^{x}$$

Problem 79

Use a calculator to solve each equation. Round answers to four decimal places. $$e^{x}=7.2$$

Problem 80

Use a calculator to solve each equation. Round answers to four decimal places. $$e^{3 x}=0.4$$

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