Chapter 9: Problem 40
\(\left|\begin{array}{rrr}i & j & k \\ 1 & -2 & 3 \\ 2 & 1 & -4\end{array}\right|\)
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Chapter 9: Problem 40
\(\left|\begin{array}{rrr}i & j & k \\ 1 & -2 & 3 \\ 2 & 1 & -4\end{array}\right|\)
These are the key concepts you need to understand to accurately answer the question.
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Find the inverse of the matrix if it exists. $$ \left[\begin{array}{lll} 2 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 6 \end{array}\right] $$
Exer. 17-20: Solve the system using the inverse method. Refer to Exercises 3-4 and 9-10. $$ \left\\{\begin{array}{r} 2 x-4 y=c \\ x+3 y=d \end{array}\right. $$ (a) \(\left[\begin{array}{l}c \\ d\end{array}\right]=\left[\begin{array}{l}3 \\\ 1\end{array}\right]\) (b) \(\left[\begin{array}{l}c \\ d\end{array}\right]=\left[\begin{array}{r}-2 \\\ 5\end{array}\right]\)
If \(f(x)=a x^{3}+b x+c\), determine \(a, b\), and \(c\) such that the graph of \(f\) passes through the points \(P(-3,-12)\), \(Q(-1,22)\), and \(R(2,13)\)
Find the inverse of the matrix if it exists. $$ \left[\begin{array}{lll} 1 & 1 & 1 \\ 2 & 2 & 2 \\ 3 & 3 & 3 \end{array}\right] $$
Particle acceleration If a particle moves along a coordinate line with a constant acceleration \(a\) (in cm \(/ \mathrm{sec}^{2}\) ), then at time \(t\) (in seconds) its distance \(s(t)\) (in centimeters) from the origin is $$ s(t)=\frac{1}{2} a t^{2}+v_{0} t+s_{0} $$ for velocity \(v_{0}\) and distance \(s_{0}\) from the origin at \(t=0\). If the distances of the particle from the origin at \(t=\frac{1}{2}, t=1\), and \(t=\frac{3}{2}\) are 7,11 , and 17 , respectively, find \(a, v_{0}\), and \(s_{0}\).
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