Chapter 7: Problem 54
Exer. 51-60: Show that the equation is not an identity. (Hint: Find one number for which the equation is false.) $$ \sec t=\sqrt{\tan ^{2} t+1} $$
Short Answer
Expert verified
The equation fails for \( t = \frac{3\pi}{4} \), so it is not an identity.
Step by step solution
01
Understand the given equation
The equation given is \( \sec t = \sqrt{\tan^2 t + 1} \). We need to determine if this equation is an identity, meaning it should hold true for all values of \( t \) within its domain.
02
Review trigonometric identities
Recall that \( \sec t = \frac{1}{\cos t} \) and from the Pythagorean identity, \( \tan^2 t + 1 = \sec^2 t \). Thus, the right-hand side of the equation simplifies to \( \sqrt{\sec^2 t} \), which equals \( |\sec t| \). Hence, \( |\sec t| = \sec t \).
03
Analyze the solution
For the given equation \( \sec t = \sqrt{\tan^2 t + 1} \) to be true for all \( t \), \( \sec t \) must always equal \(|\sec t|\). However, this is not true if \( \sec t \) is negative, i.e., when \( \cos t < 0 \).
04
Find a specific value of t where the equation fails
Consider \( t = \frac{3\pi}{4} \). At this angle, \( \sec t = -\sqrt{2} \) because \( \cos t = -\frac{1}{\sqrt{2}} \). The right side becomes \( \sqrt{\tan^2 t + 1} = \sqrt{\sec^2 t} = \sqrt{(-\sqrt{2})^2} = \sqrt{2} \). Thus, \(-\sqrt{2} eq \sqrt{2}\).
05
Conclusion
Since there is at least one value of \( t = \frac{3\pi}{4} \) where \( \sec t eq \sqrt{\tan^2 t + 1} \), the equation is not an identity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, denoted as \( \sec t \), is a fundamental trigonometric function. It is defined as the reciprocal of the cosine function, which means \( \sec t = \frac{1}{\cos t} \). This implies that the secant function is undefined for values of \( t \) where \( \cos t = 0 \), because division by zero is not possible.
The secant function can take on positive or negative values depending on the quadrant in which the angle \( t \) lies. In the first and fourth quadrants, where \( \cos t \) is positive, \( \sec t \) is also positive. However, in the second and third quadrants, \( \cos t \) is negative, making \( \sec t \) negative.
Key properties of the secant function include:
The secant function can take on positive or negative values depending on the quadrant in which the angle \( t \) lies. In the first and fourth quadrants, where \( \cos t \) is positive, \( \sec t \) is also positive. However, in the second and third quadrants, \( \cos t \) is negative, making \( \sec t \) negative.
Key properties of the secant function include:
- Periodicity: Like all trigonometric functions, the secant function repeats its values over regular intervals. Specifically, \( \sec t \) has a period of \( 2\pi \).
- Even Function: The property \( \sec(-t) = \sec t \) reflects the symmetry of the secant function about the \( y \)-axis.
- Amplitude: Secant does not have a maximum or minimum value, but it grows indefinitely as \( t \) approaches values that make \( \cos t = 0 \).
Pythagorean Identity
One of the most important tools in trigonometry is the Pythagorean identity, which provides a fundamental relationship between sine, cosine, and tangent functions. The identity is given by:
\[ \sin^2 t + \cos^2 t = 1 \]
This identity can be manipulated to express the relationship between tangent and secant:
\[ \tan^2 t + 1 = \sec^2 t \]
This reformulation is particularly useful in solving trigonometric equations where tangent and secant functions are involved.
This identity helps understand why the original problem's right side, \( \sqrt{\tan^2 t + 1} \), simplifies to \( \sqrt{\sec^2 t} \), which is \( |\sec t| \). Since square root operations always yield positive values or zero, it contrasts with the possible negative values of \( \sec t \) when \( \cos t \) is negative.
Important points about this identity include:
\[ \sin^2 t + \cos^2 t = 1 \]
This identity can be manipulated to express the relationship between tangent and secant:
\[ \tan^2 t + 1 = \sec^2 t \]
This reformulation is particularly useful in solving trigonometric equations where tangent and secant functions are involved.
This identity helps understand why the original problem's right side, \( \sqrt{\tan^2 t + 1} \), simplifies to \( \sqrt{\sec^2 t} \), which is \( |\sec t| \). Since square root operations always yield positive values or zero, it contrasts with the possible negative values of \( \sec t \) when \( \cos t \) is negative.
Important points about this identity include:
- It always holds true for all real numbers \( t \), as long as the involved trigonometric functions are defined.
- It serves as the basis for deriving other trigonometric identities and solving equations.
Trigonometric Equations
Solving trigonometric equations involves finding the values of angles that satisfy the equation. A crucial aspect of these equations is determining whether they are identities or not.
An equation is considered a trigonometric identity if it is true for all values of the variable within the domain of the trigonometric functions involved. Otherwise, it is simply a trigonometric equation that has solutions at specific values.
The exercise explored demonstrates a method for testing if an equation is an identity by finding values that might not satisfy the equation. Specifically, we determined the equation \( \sec t = \sqrt{\tan^2 t + 1} \) is not universally valid for all \( t \), because \( \sec t \) can be negative when \( \cos t < 0 \).
To solve such equations, keep these points in mind:
An equation is considered a trigonometric identity if it is true for all values of the variable within the domain of the trigonometric functions involved. Otherwise, it is simply a trigonometric equation that has solutions at specific values.
The exercise explored demonstrates a method for testing if an equation is an identity by finding values that might not satisfy the equation. Specifically, we determined the equation \( \sec t = \sqrt{\tan^2 t + 1} \) is not universally valid for all \( t \), because \( \sec t \) can be negative when \( \cos t < 0 \).
To solve such equations, keep these points in mind:
- Check the domain of the equation — certain values where the functions are undefined should be excluded.
- Consider the periodicity of trigonometric functions; solutions can often exist at regular intervals.
- Test the equation with specific angles to explore potential false values. If a single angle disproves it, the equation is not an identity.