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Exer. 5-40: Find the amplitude, the period, and the phase shift and sketch the graph of the equation. $$ y=\cos \left(x+\frac{\pi}{2}\right) $$

Short Answer

Expert verified
Amplitude: 1, Period: \(2\pi\), Phase Shift: \(-\frac{\pi}{2}\).

Step by step solution

01

Identify the Amplitude

The amplitude of the cosine function is determined by the coefficient in front of the cosine term. In this equation, the coefficient is 1, so the amplitude is:\[\text{Amplitude} = |1| = 1\]
02

Determine the Period

The period of a cosine function is given by the formula \( \frac{2\pi}{b} \), where \( b \) is the coefficient of \( x \) inside the cosine function. Here, since there is no coefficient given besides 1, the period is:\[\text{Period} = \frac{2\pi}{1} = 2\pi\]
03

Calculate the Phase Shift

The phase shift is calculated using the form \( x + c \), where \( c \) is added inside the cosine function. By comparing this equation to the standard form \( y = a\cos(bx + c) \), we find \( c = \frac{\pi}{2} \). Thus, the phase shift is:\[\text{Phase Shift} = -\frac{c}{b} = -\frac{\frac{\pi}{2}}{1} = -\frac{\pi}{2}\]This indicates a shift to the left by \( \frac{\pi}{2} \).
04

Sketch the Graph

To sketch the graph of \( y = \cos \left(x+\frac{\pi}{2}\right) \), start with the basic cosine curve, considering: - Amplitude = 1 (the curve will oscillate between 1 and -1)- Period = \( 2\pi \) (the wave completes one cycle every \( 2\pi \))- A leftward phase shift of \( \frac{\pi}{2} \).Plotting these adjustments should give you a wave that starts at the lowest point at \( x = -\frac{\pi}{2} \), peaks at \( x = \pi \), and completes the cycle at \( 3\pi \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Amplitude
Amplitude is a key concept when studying trigonometric functions like sine and cosine. It refers to the height of the wave, specifically how far the function's value travels above and below its average value. In simpler terms, amplitude is the maximum distance from the horizontal axis to the peak or trough of the wave.

In the equation given, which is in the form of \( y = a\cos(bx + c) \), the amplitude \( a \) is represented by the coefficient in front of the cosine function. For the equation \( y = \cos(x + \frac{\pi}{2}) \), the coefficient is 1. Therefore, the amplitude is absolute value of 1, which is:
  • Amplitude = |1| = 1
This means the wave reaches 1 unit above and 1 unit below the horizontal axis. Remember, the amplitude tells us nothing about the position along the x-axis or the rate at which the wave moves. It's purely about vertical stretch or compression.
Understanding Period
The period of a trigonometric function describes how long it takes for the function to repeat its cycle. For the cosine function, the period reflects the distance along the x-axis before the function starts to repeat. The period formula for the function \( y = a\cos(bx + c) \) is \( \frac{2\pi}{b} \).

In our equation, \( y = \cos(x + \frac{\pi}{2}) \), the coefficient \( b \) of \( x \) is 1. This makes the calculation straightforward:
  • Period = \( \frac{2\pi}{1} = 2\pi \)
This period means that after every \( 2\pi \) units along the x-axis, the same wave pattern repeats. It's like drawing the wave, knowing it will look the exact same every \( 2\pi \) interval. Understanding the period helps us know how "stretched out" a cycle is compared to the basic cosine function.
Understanding Phase Shift
Phase shift involves figuring out where the wave starts along the x-axis. It refers to a horizontal shift that causes the wave to start at a different point than usual. Phase shift is rooted in the "inside" value added or subtracted in the function, represented as \( c \) in \( y = a\cos(bx + c) \).

To determine the phase shift, use the formula \( -\frac{c}{b} \). For \( y = \cos(x + \frac{\pi}{2}) \), \( c \) is \( \frac{\pi}{2} \) and \( b \) is 1, leading to:
  • Phase Shift = \(-\frac{\frac{\pi}{2}}{1} = -\frac{\pi}{2}\)
The negative sign reveals the wave shifts to the left by \( \frac{\pi}{2} \) units. Essentially, understanding phase shift helps us reposition the starting point of the wave, adjusting where it begins its cycle along the x-axis. This alteration aligns the graph with any phase changes, crucial for accurately sketching trigonometric graphs.

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