Chapter 6: Problem 36
Approximate, to the nearest \(0.1^{\circ}\), all angles \(\theta\) in the interval \(\left[0^{\circ}, 360^{\circ}\right)\) that satisfy the equation. (a) \(\sin \theta=0.8225\) (b) \(\cos \theta=-0.6604\) (c) \(\tan \theta=-1.5214\) (d) \(\cot \theta=1.3752\) (e) \(\sec \theta=1.4291\) (f) \(\csc \theta=-2.3179\)
Short Answer
Step by step solution
Solving (a) for \( \sin \theta = 0.8225 \)
Solving (b) for \( \cos \theta = -0.6604 \)
Solving (c) for \( \tan \theta = -1.5214 \)
Solving (d) for \( \cot \theta = 1.3752 \)
Solving (e) for \( \sec \theta = 1.4291 \)
Solving (f) for \( \csc \theta = -2.3179 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sine Function
The value of the sine function oscillates between -1 and 1 as the angle \( \theta \) varies within the interval \( [0^{\circ}, 360^{\circ}) \).
- In the first quadrant, \( \sin(\theta) \) is positive.
- Similarly, in the second quadrant, \( \sin(\theta) \) is also positive.
- However, in the third and fourth quadrants, \( \sin(\theta) \) becomes negative.
Since sine is positive in both the first and second quadrants, we also consider the angle \( 180^{\circ} - 55.0^{\circ} = 125.0^{\circ} \).
Thus, the solutions are \( \theta = 55.0^{\circ} \) and \( \theta = 125.0^{\circ} \).
Cosine Function
The cosine function ranges from -1 to 1 as the angle moves through various quadrants.
- In the first quadrant, \( \cos(\theta) \) is positive.
- It's negative in the second quadrant and remains negative in the third quadrant.
- In the fourth quadrant, \( \cos(\theta) \) becomes positive again.
As the cosine is negative in the second and third quadrants, we deduce another angle as \( 360^{\circ} - 131.5^{\circ} = 228.5^{\circ} \).
Therefore, the answers are \( \theta = 131.5^{\circ} \) and \( \theta = 228.5^{\circ} \).
Tangent Function
Unlike the sine and cosine functions, the tangent function does not have a maximum or minimum value but rather extends from negative to positive infinity within its periodic intervals.
- Tangent is positive in the first quadrant and negative in the second.
- It's positive again in the third quadrant and negative in the fourth.
Adjusting it to the given interval, \( \theta = 360^{\circ} - 56.4^{\circ} = 303.6^{\circ} \).
Since tangent is negative in the second quadrant, another angle is \( 180^{\circ} - 56.4^{\circ} = 123.6^{\circ} \).
The angles that satisfy are \( 123.6^{\circ} \) and \( 303.6^{\circ} \).
Cotangent Function
- In right-angled triangles, it pairs the lengths of the adjacent side to the opposite side.
- The cotangent curve shares some resemblance with the tangent but reflects the inverse relationship.
Using the inverse tangent to find \( \theta \), we obtain about \( 36.0^{\circ} \).
As tangent is positive in the first and third quadrants, the additional angle is \( 180^{\circ} + 36.0^{\circ} = 216.0^{\circ} \).
Thus, the solutions are \( 36.0^{\circ} \) and \( 216.0^{\circ} \).
Secant Function
It measures the ratio of the hypotenuse to the adjacent side in a right triangle.
Like the tangent and cotangent functions, secant doesn’t have a specific range but has vertical asymptotes where cosine equals zero.
- Secant is positive in the first and fourth quadrants.
- It becomes negative in the second and third quadrants due to the cosine values.
Using the inverse cosine function, we get \( \theta = 45.5^{\circ} \).
Since cosine remains positive in the first and fourth quadrants, another angle would be \( 360^{\circ} - 45.5^{\circ} = 314.5^{\circ} \).
Thus, \( \theta \) can be \( 45.5^{\circ} \) or \( 314.5^{\circ} \).
Cosecant Function
It calculates the ratio of the hypotenuse to the opposite side in a triangle.
Like the secant, the cosecant function has no maximum or minimum value, possessing asymptotes where sine equals zero.
- Cosecant is positive in the first and second quadrants because it mirrors the sine.
- Thus, it turns negative in the third and fourth quadrants.
Applying the inverse sine equation yields \( \theta \approx -25.6^{\circ} \).
Adjust to the interval by taking \( 360^{\circ} - 25.6^{\circ} = 334.4^{\circ} \).
Since sine is negative in the third quadrant, another solution is \( 180^{\circ} + 25.6^{\circ} = 205.6^{\circ} \).
Thus, \( \theta \) is \( 205.6^{\circ} \) and \( 334.4^{\circ} \).