/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 The Ehrenberg relation $$ \l... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Ehrenberg relation $$ \ln W=\ln 2.4+(1.84) h $$ is an empirically based formula relating the height \(h\) (in meters) to the average weight \(W\) (in kilograms) for children 5 through 13 years old. (a) Express \(W\) as a function of \(h\) that does not contain \(\ln\). (b) Estimate the average weight of an 8-year-old child who is \(1.5\) meters tall.

Short Answer

Expert verified
The average weight of a 1.5 meter tall 8-year-old is approximately 37.85 kg.

Step by step solution

01

Isolate W in the Equation

The given equation is \( \ln W = \ln 2.4 + 1.84h \). To express \( W \) as a function of \( h \), we need to get rid of the natural logarithm. We can do this by exponentiating both sides of the equation to solve for \( W \). This leads to \( W = e^{\ln 2.4 + 1.84h} \).
02

Simplify the Exponentiation

Using the properties of exponents: \( e^{a+b} = e^a \cdot e^b \), we rewrite the equation as \( W = e^{\ln 2.4} \cdot e^{1.84h} \). Since \( e^{\ln 2.4} = 2.4 \), the expression simplifies to \( W = 2.4 \cdot e^{1.84h} \). Thus, \( W(h) = 2.4 \cdot e^{1.84h} \).
03

Substitute h = 1.5 to Estimate W

Now we will estimate the average weight of an 8-year-old child who is 1.5 meters tall by substituting \( h = 1.5 \) into the function \( W(h) = 2.4 \cdot e^{1.84h} \). This gives us \( W(1.5) = 2.4 \cdot e^{1.84 \times 1.5} \).
04

Calculate the Exponential Term

Calculate \( 1.84 \times 1.5 = 2.76 \). Therefore, \( W(1.5) = 2.4 \cdot e^{2.76} \). Use a calculator to find \( e^{2.76} \).
05

Final Calculation and Result

Using a calculator, \( e^{2.76} \approx 15.77 \). Therefore, \( W = 2.4 \times 15.77 \approx 37.85 \). The estimated average weight of an 8-year-old child who is 1.5 meters tall is approximately 37.85 kilograms.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponentiation
Exponentiation is a mathematical operation that raises a number, known as the base, to the power of an exponent. In the Ehrenberg relation, exponentiation is crucial for transforming expressions involving logarithms. When working with the equation \( \ln W = \ln 2.4 + 1.84h \), exponentiating each side helps remove the natural logarithm, simplifying our work.
  • Exponentiation essentially "undoes" logarithms. This principle transforms log equations into more manageable forms.
  • The formula \( e^{a+b} = e^a \cdot e^b \) is an essential property that allows decomposition of exponents, as used in this problem.
  • Knowing that \( e^{\ln x} = x \), helps simplify expressions by canceling the logarithm with the exponential function.
Using these properties, the Ehrenberg relation becomes \( W = 2.4 \cdot e^{1.84h} \). This expression links height directly to an average weight, free from logarithmic terms.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a logarithm to the base \( e \), where \( e \approx 2.71828 \). It often arises in natural growth patterns and exponential decay.
  • The natural logarithm allows for the expression of relationships, like those in the Ehrenberg relation, in a linear form before converting.
  • Logarithms provide a powerful way to simplify multiplication into addition, which was the initial form of the relation: \( \ln W = \ln 2.4 + 1.84h \).
  • In many scientific formulas, logarithms are used to linearize exponential dynamics, which makes them easier to manipulate mathematically.
Understanding the properties of \( \ln \), like how it interacts with exponentials (\( e^{\ln x} = x \)), is critical for interpreting and transforming equations such as the Ehrenberg relation.
Function Notation
Function notation is a method to denote a function's output concerning its input variables, often written as \( f(x) \) or in this case, \( W(h) \). It’s a concise way to represent the relationship between dependent and independent variables.
  • Here, \( W(h) = 2.4 \cdot e^{1.84h} \) denotes the weight \( W \) as a function of height \( h \), clearly showing we derive \( W\) from \( h \).
  • Function notation conveys the dependency and relationship inside our equation, making it explicitly clear what value depends on what variable.
  • This notation is convenient for substituting numeric values to calculate specific results, such as predicting the weight for given heights, like the 1.5-meter child example.
So, when using \( W(h) \), it's all about clarity. Function notation tells you instantly what the variable of interest is and how it influences the result.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Minimum wage In 1971 the minimum wage in the United States was \(\$ 1.60\) per hour. Assuming that the rate of inflation is \(5 \%\) per year, find the equivalent minimum wage in the year 2010 .

Urban population density An urban density model is a formula that relates the population density \(D\) (in thousands/ \(\mathrm{mi}^{2}\) ) to the distance \(x\) (in miles) from the center of the city. The formula \(D=a e^{-b x}\) for the central density \(a\) and coefficient of decay \(b\) has been found to be appropriate for many large U.S. cities. For the city of Atlanta in \(1970, a=5.5\) and \(b=0.10\). At approximately what distance was the population density 2000 per square mile?

Studies relating serum cholesterol level to coronary heart disease suggest that a risk factor is the ratio \(x\) of the total amount \(C\) of cholesterol in the blood to the amount \(H\) of high-density lipoprotein cholesterol in the blood. For a female, the lifetime risk \(R\) of having a heart attack can be approximated by the formula $$ R=2.07 \ln x-2.04 \text { provided } 0 \leq R \leq 1 . $$ For example, if \(R=0.65\), then there is a \(65 \%\) chance that a woman will have a heart attack over an average lifetime. Calculate \(R\) for a female with \(C=242\) and \(H=78\).

Exer. 67-68: Approximate the function at the value of \(x\) to four decimal places. $$ h(x)=\log _{4} x-2 \log _{8} 1.2 x ; \quad x=5.3 $$

Exer. 47-50: Chemists use a number denoted by \(\mathrm{pH}\) to describe quantitatively the acidity or basicity of solutions. By definition, \(\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]\), where \(\left[\mathrm{H}^{+}\right]\)is the hydrogen ion concentration in moles per liter. A solution is considered basic if \(\left[\mathrm{H}^{+}\right]<10^{-7}\) or acidic if \(\left[\mathrm{H}^{+}\right]>10^{-7}\). Find the corresponding inequalities involving pH.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.