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Express in terms of logarithms of \(x, y, z\), or \(w\). $$ \log \frac{\sqrt{y}}{x^{4} \sqrt[3]{z}} $$

Short Answer

Expert verified
\(\frac{1}{2} \log(y) - 4 \log(x) - \frac{1}{3} \log(z)\)

Step by step solution

01

Apply the Quotient Rule for Logarithms

The logarithm of a quotient is the difference of the logarithms. So, begin by expressing the original expression as the difference between the logarithm of the numerator and the logarithm of the denominator: \[ \log \frac{\sqrt{y}}{x^4 \sqrt[3]{z}} = \log(\sqrt{y}) - \log(x^4 \sqrt[3]{z}) \]
02

Simplify the Logarithm of the Numerator

We apply the power rule for logarithms, which states that \( \log(a^b) = b \log(a) \). For the square root \( \sqrt{y} = y^{1/2} \), the logarithm becomes: \[ \log(\sqrt{y}) = \log(y^{1/2}) = \frac{1}{2} \log(y) \]
03

Simplify the Logarithm of the Denominator

Using the product rule \( \log(ab) = \log(a) + \log(b) \) and the power rule, decompose the expression further for the denominator: \[ \log(x^4 \sqrt[3]{z}) = \log(x^4) + \log(\sqrt[3]{z}) \]Apply the power rule to each term: \[ \log(x^4) = 4 \log(x), \quad \log(\sqrt[3]{z}) = \log(z^{1/3}) = \frac{1}{3} \log(z) \]
04

Combine the Expressions

Substitute the simplified terms back into the original expanded expression and compute:\[ \log \frac{\sqrt{y}}{x^4 \sqrt[3]{z}} = \frac{1}{2} \log(y) - (4 \log(x) + \frac{1}{3} \log(z)) \]Distribute the negative sign:\[ = \frac{1}{2} \log(y) - 4 \log(x) - \frac{1}{3} \log(z) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Identities
Understanding logarithmic identities is fundamental when simplifying complex logarithmic expressions. These identities help you manipulate and transform logarithmic expressions into more manageable forms.
One of the main identities includes the log of a quotient, log of a product, and the power rule.
These are helpful especially when dealing with expressions involving roots and exponents, as they allow you to break them down into smaller, simpler pieces.
  • The identity for the logarithm of a product states that the log of a product is equal to the sum of the logs: \( \log(AB) = \log(A) + \log(B) \).
  • For a quotient, the identity is: \( \log\left(\frac{A}{B}\right) = \log(A) - \log(B) \).
  • The power rule asserts that \( \log(A^b) = b \cdot \log(A) \), meaning we can move exponents in front of the log as a multiplier.
These identities are the backbone of simplifying any logarithmic expression, helping us convert complicated expressions into something easier to handle.
Quotient Rule for Logarithms
The quotient rule for logarithms helps us deal with the logarithm of a division of two numbers. According to this rule, the log of a quotient is the difference between the log of the numerator and the log of the denominator.
In the exercise above, we started by applying this rule to break the expression into two simpler parts. For example, given an expression \( \log\left(\frac{A}{B}\right) \), we express it as:
  • \( \log\left(\frac{A}{B}\right) = \log(A) - \log(B) \)
This way, we separate the components of the fraction into smaller parts, which can be simplified individually using other rules like the power and product rules. This step is especially crucial in handling exponents and roots as seen in this problem.
Power Rule for Logarithms
The power rule for logarithms is a powerful tool allowing us to simplify log expressions that involve exponents. It states that the log of a number raised to an exponent is the exponent times the log of the base number.
For instance, if you have \( \log(A^b) \), this can be simplified to:
  • \( \log(A^b) = b \cdot \log(A) \)
In the context of the exercise, we applied this rule twice: once to the square root \( \sqrt{y} \), which is expressed as \( y^{1/2} \), becoming \( \frac{1}{2} \log(y) \).
Additionally, it was applied to the cube root \( \sqrt[3]{z} \) expressed as \( z^{1/3} \), resulting in \( \frac{1}{3} \log(z) \).
This rule allows us to handle expressions with roots and powers systematically, making it easier to work through complex logarithmic expressions.
Product Rule for Logarithms
The product rule for logarithms assists with understanding logs of products and breaking them into sums of logs. According to this rule, the log of a product is the sum of the logs of its factors.
In mathematical terms, \( \log(AB) \) becomes
  • \( \log(A) + \log(B) \).
In our problem, the product rule helps us manage the expression \( \log(x^4 \sqrt[3]{z}) \) by breaking it into two parts as \( \log(x^4) + \log\sqrt[3]{z} \).
This was pivotal for further simplification with the power rule.
Using the product rule correctly allows for step-by-step simplification of expressions that contain multiple multiplicative terms, streamlining the process and making complex expressions more approachable.

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Most popular questions from this chapter

Exer. 65-66: It is suspected that the following data points lie on the graph of \(y=c \log (k x+10)\), where \(c\) and \(k\) are constants. If the data points have three-decimal-place accuracy, is this suspicion correct? $$ (0,0.7),(1,0.782),(2,0.847),(3,0.900),(4,0.945) $$

Exer. 47-50: Chemists use a number denoted by \(\mathrm{pH}\) to describe quantitatively the acidity or basicity of solutions. By definition, \(\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]\), where \(\left[\mathrm{H}^{+}\right]\)is the hydrogen ion concentration in moles per liter. Approximate the hydrogen ion concentration \(\left[\mathrm{H}^{+}\right]\)of each substance. (a) apples: \(\mathrm{pH} \approx 3.0\) (b) beer: \(\mathrm{pH} \approx 4.2\) (c) milk: \(\mathrm{pH} \approx 6.6\)

Growth of children The Jenss model is generally regarded as the most accurate formula for predicting the height of preschool children. If \(y\) is height (in centimeters) and \(x\) is age (in years), then $$ y=79.041+6.39 x-e^{3.261-0.993 x} $$ for \(\frac{1}{4} \leq x \leq 6\). From calculus, the rate of growth \(R\) (in \(\mathrm{cm} /\) year) is given by \(R=6.39+0.993 e^{3261-0.993 x}\). Find the height and rate of growth of a typical 1-year-old child.

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Change \(f(x)=100\left(\frac{1}{2}\right)^{x}\) to an exponential function with base \(e\) and approximate the decay rate of \(f\).

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