Chapter 5: Problem 22
Exer. 21-24: Determine the domain and range of \(f^{-1}\) for the given function without actually finding \(f^{-1}\). Hint: First find the domain and range of \(f\). $$ f(x)=\frac{5}{x+3} $$
Short Answer
Expert verified
Domain of \(f^{-1}\): all real numbers except 0; Range of \(f^{-1}\): all real numbers except -3.
Step by step solution
01
Understand the function
The given function is \( f(x) = \frac{5}{x+3} \). This is a rational function, which indicates that the value in the denominator \( x+3 \) cannot be zero.
02
Determine the domain of \( f \)
To find the domain of \( f(x) = \frac{5}{x+3} \), set the denominator equal to zero and solve for \( x \). This gives \( x+3=0 \rightarrow x=-3 \). Therefore, \( x eq -3 \), leading to a domain of all real numbers except \(-3\).
03
Determine the range of \( f \)
The range is determined by the potential outputs of the function \( f(x) = \frac{5}{x+3} \). As \( x \) approaches \(-3\), the function trends towards positive or negative infinity, covering all real values except zero. Thus, the range is all real numbers except zero.
04
Relate domain and range of \( f \) to \( f^{-1} \)
For an inverse function \( f^{-1} \), the domain of \( f \) becomes the range of \( f^{-1} \), and the range of \( f \) becomes the domain of \( f^{-1} \).
05
State the domain of \( f^{-1} \)
The domain of \( f^{-1} \) is the range of \( f \), which is all real numbers except zero.
06
State the range of \( f^{-1} \)
The range of \( f^{-1} \) is the domain of \( f \), which is all real numbers except \(-3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
When we talk about the 'domain of a function', we are looking at all the possible input values that a function can accept. These inputs are often the values through which you can navigate on the x-axis of a graph. For rational functions like the one in our example, this involves particularly checking the denominator since division by zero is undefined.
Given the function \( f(x) = \frac{5}{x+3} \), the expression \( x+3 \) in the denominator cannot be zero. Solving for when \( x+3=0 \) gives \( x=-3 \). This tells us that \(-3\) is not part of the domain.
Given the function \( f(x) = \frac{5}{x+3} \), the expression \( x+3 \) in the denominator cannot be zero. Solving for when \( x+3=0 \) gives \( x=-3 \). This tells us that \(-3\) is not part of the domain.
- Therefore, the domain of \( f(x) \) is all real numbers except \(-3\).
- It is often written as: \( (-\infty, -3) \cup (-3, \infty) \), meaning all numbers except -3.
Range of a Function
Understanding the 'range of a function' is about recognizing all possible output values the function can produce. These correspond to the y-values on a graph. In the case of our rational function \( f(x) = \frac{5}{x+3} \), the range requires us to see which outputs are excluded.
As \( x \) approaches the point where the function is undefined, at \( x = -3 \), the value \( f(x) \) rises towards positive or negative infinity. This behavior creates outputs for almost all numbers except zero, which the function can’t reach.
As \( x \) approaches the point where the function is undefined, at \( x = -3 \), the value \( f(x) \) rises towards positive or negative infinity. This behavior creates outputs for almost all numbers except zero, which the function can’t reach.
- This means the range of \( f(x) \) is: all real numbers except zero.
- Mathematically, it's written as: \( (-\infty, 0) \cup (0, \infty) \).
Rational Functions
Rational functions involve ratios of polynomials, where one polynomial is divided by another. The general form looks like \( \frac{P(x)}{Q(x)} \), where both \( P(x) \) and \( Q(x) \) are polynomials and \( Q(x) eq 0 \). The power of rational functions lies in their flexibility and coverage, showing a wide range of behaviors.
For our specific function \( f(x) = \frac{5}{x+3} \), here is how it plays out:
These points mark complex behaviors like asymptotic behavior where \( x \) gets very large or closer to a value that makes the denominator zero. As \( x \) approaches such values, the output can skyrocket to positive or plummet to negative infinity.
Rational functions form a key part of high school mathematics due to their intricate properties and how they model real-world scenarios, such as rates and ratios. Understanding them is essential across various applications, from predicting trends to solving everyday mathematical problems.
For our specific function \( f(x) = \frac{5}{x+3} \), here is how it plays out:
- Numerator \( 5 \) is simple, with a constant polynomial.
- Denominator \( x+3 \), ensures that \( x\) cannot be \(-3\) as it would make the denominator zero.
These points mark complex behaviors like asymptotic behavior where \( x \) gets very large or closer to a value that makes the denominator zero. As \( x \) approaches such values, the output can skyrocket to positive or plummet to negative infinity.
Rational functions form a key part of high school mathematics due to their intricate properties and how they model real-world scenarios, such as rates and ratios. Understanding them is essential across various applications, from predicting trends to solving everyday mathematical problems.