Chapter 5: Problem 16
Sketch the graph of \(f\). $$f(x)=8(4)^{-x}-2$$
Short Answer
Expert verified
The graph is an exponential decay with horizontal asymptote at \(y = -2\) and passes through points \((0, 6), (1, 0),\) and \((2, -0.5)\).
Step by step solution
01
Identify the Function Type
The given function is an exponential function because it has the form \( a \cdot b^{-x} \), where \( a = 8 \) and \( b = 4 \). The function represents exponential decay since the base \( b = 4 \) with a negative exponent \(-x\).
02
Determine the Horizontal Asymptote
In exponential functions of the form \( a \cdot b^{-x} + c \), the horizontal asymptote is given by \( y = c \). Thus, for the function \( f(x) = 8(4)^{-x} - 2 \), the horizontal asymptote is \( y = -2 \).
03
Find Key Points
To sketch the graph, find some key points. Start by substituting a few values of \( x \) into \( f(x) = 8(4)^{-x} - 2 \):- When \( x = 0 \), \( f(x) = 8(4)^0 - 2 = 6 \). Thus, the point is \( (0, 6) \).- When \( x = 1 \), \( f(x) = 8(4)^{-1} - 2 = 0 \). Thus, the point is \( (1, 0) \).- When \( x = 2 \), \( f(x) = 8(4)^{-2} - 2 = -0.5 \). Thus, the point is \( (2, -0.5) \).
04
Sketch the Graph
Plot the key points \((0, 6), (1, 0), (2, -0.5)\) on a coordinate plane. Since the base \( b = 4\) is being raised to negative exponents, the function's values will continue to approach the horizontal asymptote \(y = -2\), but not cross it. The graph should show a decay from the point \((0, 6)\), decreasing and approaching but not reaching \( y = -2 \) as \( x \) increases.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Decay
Exponential decay describes a mathematical process where quantities decrease over time at a rate proportional to their current value. In the formula for exponential decay, such as \( f(x) = a \, b^{-x} \), "\( a \)" is the initial value and "\( b \)" is the decay factor's base. When the exponent of the base is negative, the function exhibits decay. This means as \( x \) increases, the function's value decreases. In our function \( f(x) = 8(4)^{-x} - 2 \), the coefficient and the negative exponent of the base \( b = 4 \) cause the output to shrink as \( x \) goes up. Functions experiencing decay are prevalent in real-world scenarios like radioactive decay, depreciation of asset values, and population declines. Exponential decay is often visualized as a rapid drop initially, that then slows as it approaches a boundary or limit, known as the horizontal asymptote.
Graphing Exponential Functions
Sketching an exponential function graph involves a few simple steps. The function \( f(x) = 8(4)^{-x} - 2 \) is adapted from the basic exponential model \( a \times b^{-x} \) by a vertical shift. To graph such a function:
- Identify the initial value from the expression. Here, \( a = 8 \). This suggests the point \( (0, a+c) = (0, 6) \) when \( x \) is zero.
- Next, find the base \( b \), here \( b = 4 \). With a negative exponent, this signifies a decay pattern with the curve approaching the horizontal line \( y = c = -2 \).
- Calculate a few strategic points, like using 1 or 2 for \( x \), which yield points like \( (1,0) \) and \( (2,-0.5) \).
Horizontal Asymptote
The horizontal asymptote in the context of exponential functions represents a line that the graph approaches but never quite touches or crosses as the input value \( x \) moves towards positive or negative infinity. For a function given by \( f(x) = a \times b^{-x} + c \), the asymptote is at \( y = c \). In our example \( f(x) = 8(4)^{-x} - 2 \), the horizontal asymptote is at \( y = -2 \). This implies that no matter how large \( x \) becomes, the value of \( f(x) \) will close in on \( -2 \) but will never actually become \( -2 \) itself. This property is significant because it helps in predicting the long-term behavior of the function. Understanding horizontal asymptotes can assist students in visualizing how graphs behave at extreme ends and determining limits in calculus.