Chapter 5: Problem 10
Exer. 5-16: Determine whether the function \(f\) is one-to-one. $$ f(x)=\sqrt[3]{x} $$
Short Answer
Expert verified
Yes, the function is one-to-one.
Step by step solution
01
Understand the Concept of a One-to-One Function
A function is one-to-one if different inputs produce different outputs. Mathematically, if \(f(x_1) = f(x_2)\) implies \(x_1 = x_2\), then the function is one-to-one.
02
Analyze the Given Function
The given function is \(f(x) = \sqrt[3]{x}\). This is the cube root function, which is one of the standard even functions.
03
Determine Injectivity through Algebraic Manipulation
Assume \(f(x_1) = f(x_2)\), which means \(\sqrt[3]{x_1} = \sqrt[3]{x_2}\). To eliminate the radicals, raise both sides to the power of 3, resulting in \(x_1 = x_2\). This confirms the function's injectivity.
04
Conclude the Analysis
Since \(x_1 = x_2\) whenever \(f(x_1) = f(x_2)\), the function \(f(x) = \sqrt[3]{x}\) is indeed a one-to-one function according to its algebraic property.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Injectivity
The concept of injectivity is crucial in understanding one-to-one functions. A function is said to be injective, or one-to-one, if every element of the function's range is mapped by a unique element from its domain. In simpler terms, no two different inputs produce the same output. For a function \(f(x)\) to be one-to-one:
- If \(f(x_1) = f(x_2)\), then it must be true that \(x_1 = x_2\).
Cube Root Function
The cube root function is represented as \(f(x) = \sqrt[3]{x}\). It is a straightforward yet powerful mathematical function. The cube root of a number \(x\) is a value that, when cubed, gives back \(x\). This operation is inherently different from a square root due to its ability to handle all real numbers, including negatives.In the cube root function:
- Both positive and negative inputs are valid, as negatives have real cube roots.
- The function is symmetric around the origin, meaning the behavior for negative inputs mirrors that for positive inputs.
- It passes through the point (0, 0), as \(\sqrt[3]{0} = 0\).
Algebraic Manipulation
Algebraic manipulation is often used to demonstrate the properties of functions, including injectivity. For instance, with the given cube root function \(f(x) = \sqrt[3]{x}\), we can show it is injective via algebraic steps:To test injectivity algebraically, assume:
- \(f(x_1) = f(x_2)\)
- This translates mathematically to \(\sqrt[3]{x_1} = \sqrt[3]{x_2}\).
- \(x_1 = x_2\)