/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 $$ \text { Use the remainder t... [FREE SOLUTION] | 91Ó°ÊÓ

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$$ \text { Use the remainder theorem to find } f(c) \text {. } $$ $$ f(x)=x^{4}+3 x^{2}-12 ; \quad c=-2 $$

Short Answer

Expert verified
The value of \( f(-2) \) is 16.

Step by step solution

01

Understand the Polynomial Function

The given polynomial function is \( f(x) = x^4 + 3x^2 - 12 \). We are supposed to find the value \( f(c) \) where \( c = -2 \).
02

Apply the Remainder Theorem

The remainder theorem states that the remainder of the division of a polynomial by \( x - c \) is \( f(c) \). This means that to find \( f(-2) \), we need to evaluate the polynomial at \( x = -2 \).
03

Substitute and Compute \( f(-2) \)

Substitute \(-2\) into the function: \[f(-2) = (-2)^4 + 3(-2)^2 - 12 \]Calculate each term:- \((-2)^4 = 16\)- \(3(-2)^2 = 3 \times 4 = 12\)Subtracting \(12\) gives us:\[f(-2) = 16 + 12 - 12 = 16\]
04

Conclude the Calculation

After evaluating, we find that \( f(-2) = 16 \). This result is the remainder when the polynomial is divided by \( x + 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Functions
Polynomial functions are mathematical expressions made up of variables, coefficients, and constant terms combined using addition, subtraction, multiplication, and non-negative integer exponents. For example, the polynomial function given in our problem is \( f(x) = x^4 + 3x^2 - 12 \). This function consists of four terms: the highest degree term \( x^4 \), the middle term \( 3x^2 \), and the constant term \( -12 \).

Polynomials can be classified by degree (the highest power of the variable) and the number of terms. This function is a degree 4 polynomial due to the variable raised to the power of 4. Understanding the structure of polynomial functions helps in solving them using various algebraic tools like factoring or evaluating at specific values.

These functions are central to algebra because they form the foundation for more complex mathematics. They appear in equations, graphs, and real-life models where predicting outcomes or reactions is needed.
Evaluating Polynomials
Evaluating a polynomial means finding its value at a certain point, which in this problem zone is determined by the Remainder Theorem. To evaluate \( f(x) \) at \( x = -2 \), we substitute the value into the polynomial equation. This evaluation transforms our mathematical expression into numerical terms.

Here’s how it works step-by-step:
  • Replace every occurrence of \( x \) in the polynomial with \( -2 \).
  • Compute each term separately: \( (-2)^4 = 16 \) and \( 3(-2)^2 = 12 \).
  • Sum these values: \( 16 + 12 \), then subtract any constant term included, which is \( 12 \) in this instance.
Evaluating polynomials can be approached with techniques like this because it simplifies potentially complex algebra into straightforward arithmetic.
Algebraic Substitution
Algebraic substitution is a fundamental technique used often in evaluating polynomials, solving equations, and simplifying expressions. It involves replacing a variable with a given number or another expression. In our exercise, substitution is key for applying the Remainder Theorem to find \( f(-2) \).

To perform substitution accurately:
  • Identify the variable(s) that need substitution. In this case, \( x \) is replaced by \( -2 \).
  • Ensure each occurrence of the variable throughout the polynomial is correctly substituted.
  • Complete the arithmetic operations as per regular order of operations like parentheses and exponents first.
This method not only simplifies solving polynomials but also plays a crucial role in more advanced math, especially in calculus where functions are evaluated for limits, derivatives, and integrals.

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Most popular questions from this chapter

It is known from physics that the range \(R\) of a projectile is directly proportional to the square of its velocity \(v\). (a) Express \(R\) as a function of \(v\) by means of a formula that involves a constant of proportionality \(k\). (b) A motorcycle daredevil has made a jump of 150 feet. If the speed coming off the ramp was \(70 \mathrm{mi} / \mathrm{hr}\), find the value of \(k\) in part (a). (c) If the daredevil can reach a speed of \(80 \mathrm{mi} / \mathrm{hr}\) coming off the ramp and maintain proper balance, estimate the possible length of the jump.

Express the statement as a formula that involves the given variables and a constant of proportionality \(k\), and then determine the value of \(k\) from the given conditions. \(q\) is inversely proportional to the sum of \(x\) and \(y\). If \(x=0.5\) and \(y=0.7\), then \(q=1.4\).

Express the statement as a formula that involves the given variables and a constant of proportionality \(k\), and then determine the value of \(k\) from the given conditions. \(r\) is directly proportional to the product of \(s\) and \(v\) and inversely proportional to the cube of \(p\). If \(s=2, v=3\), and \(p=5\), then \(r=40\).

Kepler's third law states that the period \(T\) of a planet (the time needed to make one complete revolution about the sun) is directly proportional to the \(\frac{3}{2}\) power of its average distance \(d\) from the sun. (a) Express \(T\) as a function of \(d\) by means of a formula that involves a constant of proportionality \(k\). (b) For the planet Earth, \(T=365\) days and \(d=93\) million miles. Find the value of \(k\) in part (a). (c) Estimate the period of Venus if its average distance from the sun is 67 million miles.

Simplify \(f(x)\), and sketch the graph of \(f\). $$ f(x)=\frac{x-1}{1-x^{2}} $$

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