Chapter 3: Problem 21
Exer. 21-22: Prove that \(C\) is on the perpendicular bisector of segment \(A B\). $$ A(-4,-3), \quad B(6,1), \quad C(5,-11) $$
Short Answer
Expert verified
Point C is on the perpendicular bisector of AB.
Step by step solution
01
Find the Midpoint of Segment AB
The midpoint of a segment can be found using the formula for the midpoint between two points, \( M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \). Substitute the coordinates of points \( A(-4, -3) \) and \( B(6, 1) \) into this formula:\[ M_{AB} = \left( \frac{-4 + 6}{2}, \frac{-3 + 1}{2} \right) = (1, -1) \].
02
Calculate the Slope of AB
The slope \( m \) of a line through two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Using points \( A(-4, -3) \) and \( B(6, 1) \):\[ m_{AB} = \frac{1 - (-3)}{6 - (-4)} = \frac{4}{10} = 0.4 \].
03
Determine the Slope of the Perpendicular Bisector
The perpendicular slope to a line is the negative reciprocal of the original slope. Therefore, the slope of the perpendicular bisector for line segment \( AB \) is:\[ m_{perpendicular} = -\frac{1}{m_{AB}} = -\frac{1}{0.4} = -2.5 \].
04
Equation of Perpendicular Bisector
The equation of a line with slope \( m \) through a point \( (x_1, y_1) \) is:\[ y - y_1 = m(x - x_1) \]. Using the midpoint \((1, -1)\) and the perpendicular slope \(-2.5\):\[ y + 1 = -2.5(x - 1) \]Simplify this to:\[ y = -2.5x + 2.5 - 1 = -2.5x + 1.5 \].
05
Check if C Lies on the Perpendicular Bisector
Substitute point \( C(5, -11) \) into the equation derived for the perpendicular bisector:\[ y = -2.5x + 1.5 \]Substitute and simplify:\[ -11 = -2.5(5) + 1.5 \]\[ -11 = -12.5 + 1.5 \]\[ -11 = -11 \].The equation holds true, which means point \( C \) lies on the perpendicular bisector of segment \( AB \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Midpoint Formula
The midpoint formula is a simple yet powerful tool in geometry, used to find the exact middle point between two endpoints of a line segment. Imagine you have two points, say \((x_1, y_1)\) and \((x_2, y_2)\). The midpoint \(M\) is calculated with the formula:\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)\]This midpoint represents the average of the \(x\)-coordinates and \(y\)-coordinates of the two endpoints.
- It's like finding the center of a line segment.
- Very useful in proving lines bisect each other or in various geometric constructions.
Slope of a Line
Understanding the slope of a line helps unravel the incline or steepness between two points on a graph. The slope of a line is defined by the difference in the \(y\)-coordinates over the difference in the \(x\)-coordinates, given by:\[m = \frac{y_2 - y_1}{x_2 - x_1}\]The slope not only indicates whether the line rises or falls, but here’s a brief breakdown of what it means:
- If \(m > 0\), the line ascends as you move left to right.
- If \(m < 0\), the line descends.
- If \(m = 0\), you have a horizontal line.
- When the slope is undefined, the line is vertical.
Equation of a Line
When you know the slope of a line and have a point on that line, you can find its equation. This equation describes each point on the line as a set of \(x\) and \(y\) coordinates. The equation of a line with slope \(m\) going through a point \((x_1, y_1)\) is:\[y - y_1 = m(x - x_1)\]With some rearrangement and simplification, you'll often see it in the slope-intercept form: \[y = mx + b\]where \(b\) is the y-intercept.
- This form allows easy plotting by identifying slope \(m\) and intercept \(b\).
- Useful in determining whether a certain point lies on the line.