Chapter 3: Problem 20
Exer. 13-22: (a) Use the quadratic formula to find the zeros of \(f\). (b) Find the maximum or minimum value of \(f(x)\). (c) Sketch the graph of \(f\). $$ f(x)=-3 x^{2}-6 x-6 $$
Short Answer
Expert verified
The zeros are complex. The maximum value is -3 at \(x = -1\).
Step by step solution
01
Identify Coefficients
The given quadratic function is \(f(x) = -3x^2 - 6x - 6\). Identify the coefficients from the standard form \(ax^2 + bx + c\), where \(a = -3\), \(b = -6\), and \(c = -6\).
02
Apply the Quadratic Formula
The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Substitute the values of \(a\), \(b\), and \(c\) to find the zeros: \(x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(-3)(-6)}}{2(-3)}\).
03
Calculate the Discriminant
Calculate the discriminant \(b^2 - 4ac\): \((-6)^2 - 4(-3)(-6) = 36 - 72 = -36\). The discriminant is negative, which means the quadratic has no real zeros.
04
Find Vertex to determine Max/Min
The vertex form provides the minimum or maximum value of the quadratic function. Since \(a < 0\), the parabola opens downwards, meaning the vertex gives the maximum value. The vertex \(x\)-coordinate is \(x = \frac{-b}{2a} = \frac{-(-6)}{2(-3)} = -1\).
05
Evaluate Function at Vertex
Substitute \(x = -1\) back into \(f(x)\) to find the function value at the vertex: \(f(-1) = -3(-1)^2 - 6(-1) - 6 = -3 + 6 - 6 = -3\). So, the maximum value is \(-3\).
06
Sketch the Graph
The graph is a downward-opening parabola with a vertex at \((-1, -3)\) and no real zeros because the discriminant is negative. Sketch the graph, indicating the vertex and shape.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool to find the zeros, or solutions, of a quadratic equation. Every quadratic equation can be written in the standard form: \[ ax^2 + bx + c = 0. \]Here, the quadratic formula helps solve for \( x \), when you plug in the values of \( a \), \( b \), and \( c \):\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. \]This equation might seem a little intimidating at first, but it's essentially a handy and universal method for tackling all quadratic problems. The formula utilizes three primary pieces:
- The opposite of \( b \) (i.e., \(-b\)), which moves the term \( b \) across the equal sign.
- The discriminant \( b^2 - 4ac \) under a square root. This part significantly influences the nature of the roots.
- The division by \( 2a \), which scales the equation appropriately.
Vertex of Parabola
The vertex of a parabola is a crucial point representing either its peak or its trough, commonly known as a maximum or minimum value. For a quadratic function written in the form \( ax^2 + bx + c \), the vertex can be found using the formula for the \( x \)-coordinate:\[ x = \frac{-b}{2a}. \]Once you have the \( x \)-coordinate, substitute it back into the original quadratic equation to find the \( y \)-coordinate of the vertex. This coordinate pair \((x, f(x))\) gives the precise location of the vertex on a graph. Knowing whether the parabola opens upwards or downwards is also essential. If \( a > 0 \), the parabola opens upwards and the vertex is a minimum. Conversely, if \( a < 0 \), as in the exercise function \( f(x) = -3x^2 - 6x - 6 \), the parabola opens downwards, making the vertex a maximum point.
Discriminant
The discriminant of a quadratic equation, denoted as \( b^2 - 4ac \), is the key to understanding the nature of the equation's roots. It’s housed under the square root in the quadratic formula and dramatically impacts the solutions:
- If the discriminant is positive, there are two distinct real solutions, indicating that the parabola crosses the x-axis twice.
- If the discriminant is zero, there is exactly one real solution, meaning the parabola just touches the x-axis, forming a perfect square.
- If the discriminant is negative, as in this exercise with a value of \(-36\), the quadratic has no real solutions. This implies that the parabola does not cross the x-axis at all, indicating complex or imaginary roots.
Graphing Parabolas
Graphing a parabola is an engaging way to visualize quadratic functions. A well-drawn graph shows the shape, vertex, axis of symmetry, and roots (if any) of the quadratic equation. To graph a parabola, follow these steps:
- Identify the vertex using the formula mentioned above \( x = \frac{-b}{2a} \).
- Determine the direction the parabola opens based on the sign of \( a \). If \( a > 0 \), it opens upwards; if \( a < 0 \), like in \( f(x) = -3x^2 - 6x - 6 \), it opens downwards.
- Evaluate the discriminant to understand if the parabola intersects the x-axis.
- Sketch the curve, ensuring it is symmetric about the axis of symmetry, which passes vertically through the vertex.