Chapter 3: Problem 13
Exer. 13-22: (a) Use the quadratic formula to find the zeros of \(f\). (b) Find the maximum or minimum value of \(f(x)\). (c) Sketch the graph of \(f\). $$ f(x)=x^{2}-4 x $$
Short Answer
Expert verified
Zeros at \(x = 0\) and \(x = 4\); minimum value of \(f(x)\) is \(-4\) at \(x = 2\).
Step by step solution
01
Identify the coefficients
For a quadratic equation in the standard form \(ax^2 + bx + c\), identify the coefficients: \(a = 1\), \(b = -4\), and \(c = 0\) from the given \(f(x) = x^2 - 4x\).
02
Apply the quadratic formula
The quadratic formula is \(x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}\). Substitute the identified coefficients into the formula: \[ x = \frac{{-(-4) \pm \sqrt{{(-4)^2 - 4 \cdot 1 \cdot 0}}}}{2 \cdot 1} \]Simplify the expression: \[ x = \frac{{4 \pm \sqrt{16}}}{2} \]This further simplifies to \[ x = \frac{{4 \pm 4}}{2} \]
03
Solve for the zeros
Calculate the two possible values for \(x\) from the expression in Step 2:\[ x = \frac{{4 + 4}}{2} = 4 \quad \text{and} \quad x = \frac{{4 - 4}}{2} = 0 \]Thus, the zeros of \(f(x)\) are \(x = 4\) and \(x = 0\).
04
Determine the vertex of the parabola
The vertex of a parabola given by \(y = ax^2 + bx + c\) occurs at \(x = -\frac{b}{2a}\). Substitute \(b = -4\) and \(a = 1\) into the formula:\[ x = -\frac{-4}{2 \cdot 1} = 2 \]Then, substitute \(x = 2\) into \(f(x)\) to find the \(y\)-value:\[ f(2) = 2^2 - 4 \times 2 = 4 - 8 = -4 \]Thus, the vertex is \((2, -4)\), indicating a minimum point.
05
Plot and sketch the graph
To sketch the graph, note the following:- The zeros (x-intercepts) are at \(x = 0\) and \(x = 4\).- The vertex is at \((2, -4)\) and is a minimum point.- Since the coefficient of \(x^2\) is positive, the parabola opens upward.- Plot these key points and draw a smooth curve through them to complete the sketch.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a U-shaped curve that represents the graph of a quadratic function. Quadratic functions have the form \(f(x) = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants.
- The direction the parabola opens (upward or downward) is determined by the sign of the coefficient \(a\).
- If \(a\) is positive, the parabola opens upwards, forming a 'U' shape.
- If \(a\) is negative, the parabola opens downwards, forming an inverted 'U'.
Quadratic Formula
The quadratic formula is an essential tool for solving quadratic equations. A quadratic equation is typically written as \(ax^2 + bx + c = 0\). The quadratic formula is given by:\[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}\]To use this formula, it's important to identify the coefficients \(a\), \(b\), and \(c\) from the quadratic equation.
In our example \(f(x) = x^2 - 4x\) rewritten as \(x^2 - 4x + 0 = 0\), we found \(a = 1\), \(b = -4\), and \(c = 0\). These coefficients are substituted into the quadratic formula to find the values of \(x\) that make the function zero.
The formula involves:
In our example \(f(x) = x^2 - 4x\) rewritten as \(x^2 - 4x + 0 = 0\), we found \(a = 1\), \(b = -4\), and \(c = 0\). These coefficients are substituted into the quadratic formula to find the values of \(x\) that make the function zero.
The formula involves:
- Calculating the discriminant \(b^2 - 4ac\), which determines the nature of the roots (real or complex).
- Using the '+' and '-' symbols in the formula to find two possible solutions for \(x\).
Zeros of a Function
The zeros of a function are the points where the graph crosses the x-axis. At these points, the value of the function is zero. Finding the zeros of a quadratic function is crucial as they show where the parabola intersects the x-axis.
To find the zeros, use the quadratic formula to solve \(ax^2 + bx + c = 0\). In our example, after substituting in the values, we simplified:\[x = \frac{{4 \pm 4}}{2}\]This resulted in two zeros: \(x = 4\) and \(x = 0\).
To find the zeros, use the quadratic formula to solve \(ax^2 + bx + c = 0\). In our example, after substituting in the values, we simplified:\[x = \frac{{4 \pm 4}}{2}\]This resulted in two zeros: \(x = 4\) and \(x = 0\).
- The zeros can be considered as solutions of the quadratic equation.
- They are also called roots or x-intercepts.
Vertex of a Parabola
The vertex of a parabola represents the highest or lowest point on the graph. It occurs at the axis of symmetry, a vertical line that passes through the vertex. For a parabola given by the equation \(y = ax^2 + bx + c\), the x-coordinate of the vertex can be found using:\[x = -\frac{b}{2a}\]
In our quadratic function \(f(x) = x^2 - 4x\), we calculated:\[x = -\frac{-4}{2 \cdot 1} = 2\]By substituting \(x = 2\) back into the function, we found the y-coordinate to be \(-4\), making the vertex \((2, -4)\).
The vertex provides important information about the parabola:
In our quadratic function \(f(x) = x^2 - 4x\), we calculated:\[x = -\frac{-4}{2 \cdot 1} = 2\]By substituting \(x = 2\) back into the function, we found the y-coordinate to be \(-4\), making the vertex \((2, -4)\).
The vertex provides important information about the parabola:
- If the parabola opens upwards, the vertex represents the minimum value of the function.
- If the parabola opens downwards, the vertex represents the maximum value.
- The vertex is a critical point for analyzing the function's properties, such as its range and domain.