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Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ x^{2}-2 x-5>3 $$

Short Answer

Expert verified
The solutions are \((-\infty, -2) \cup (4, \infty)\).

Step by step solution

01

Move all terms to one side

Begin by subtracting 3 from both sides of the inequality to move all terms to one side. This gives:\[ x^2 - 2x - 5 - 3 > 0 \]Simplify the equation:\[ x^2 - 2x - 8 > 0 \]
02

Solve the corresponding equation

To find the boundary points, we solve the corresponding equation:\[ x^2 - 2x - 8 = 0 \]Factoring the quadratic equation, we get:\[ (x - 4)(x + 2) = 0 \]This gives the solutions:\[ x = 4 \text{ or } x = -2 \]
03

Test intervals derived from roots

The solutions to the equation divide the real number line into intervals: \[ (-\infty, -2), (-2, 4), (4, \infty) \]Select a test point from each interval and substitute it into the inequality \( x^2 - 2x - 8 > 0 \) to check where it holds true:
04

Test interval (-∞, -2)

Choose a test point, for example, \( x = -3 \):\[ (-3)^2 - 2(-3) - 8 = 9 + 6 - 8 = 7 \]Since 7 is greater than 0, the inequality is satisfied in the interval \((-\infty, -2)\).
05

Test interval (-2, 4)

Choose a test point, for example, \( x = 0 \):\[ 0^2 - 2(0) - 8 = -8 \]Since -8 is not greater than 0, the inequality is not satisfied in the interval \((-2, 4)\).
06

Test interval (4, ∞)

Choose a test point, for example, \( x = 5 \):\[ 5^2 - 2(5) - 8 = 25 - 10 - 8 = 7 \]Since 7 is greater than 0, the inequality is satisfied in the interval \((4, \infty)\).
07

Determine solution and express in interval notation

Combining the intervals for which the inequality holds, the solution is:\[ (-\infty, -2) \cup (4, \infty) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Inequality
A quadratic inequality involves a quadratic expression and an inequality symbol, such as greater than, less than, or equal. In general, a quadratic expression has the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( x \) is the variable. This exercise involves solving the inequality \( x^2 - 2x - 5 > 3 \). To begin, align the inequality with zero by moving all terms to one side. This simplifies the inequality to \( x^2 - 2x - 8 > 0 \). The goal is to find the values of \( x \) that make this inequality true.

Using quadratic inequalities is crucial for describing ranges of values and real-world scenarios, such as determining outcomes influenced by these values. The process of solving them, as you will see, involves factorization and testing intervals within the inequality's domain.
Interval Notation
Once we find values of \( x \) that satisfy a quadratic inequality, we express the solution set in interval notation. Interval notation is a method of expressing an interval as a pair of numbers representing its start and end points. Parentheses \((\) or \()\) indicate that an endpoint is not included, while square brackets \([\) or \()]\) show it is included. For the inequality solution \( (-\infty, -2) \cup (4, \infty) \), two separate intervals are combined using a union symbol \(\cup\). This notation succinctly represents the ranges of \( x \) for this inequality, where \( x \) can take any value less than -2 or greater than 4.

Interval notation is efficient for illustrating continuous ranges of values and is widely used in both mathematics and applied sciences. It makes it easy to communicate which parts of the number line contain solutions to a given problem.
Factoring Quadratics
Factoring is an essential step in solving quadratic inequalities. It involves rewriting a quadratic equation in the form \( (x - r_1)(x - r_2) \), where \( r_1 \) and \( r_2 \) are the roots or solutions of the quadratic equation. For the inequality \( x^2 - 2x - 8 = 0 \), factoring gives \( (x - 4)(x + 2) = 0 \). This shows that the equation equals zero when \( x = 4 \) or \( x = -2 \). These solutions create boundary points that separate the number line into intervals.

The ability to factor quadratics effectively simplifies many algebraic problems, reducing them into more manageable parts. Factoring is a keystone skill in mathematics, enabling students to solve complex expressions more easily and to better understand the structure of equations.
Test Points
After factoring, identifying test points within each interval helps verify where the inequality holds true. For instance, the real number line is divided into the intervals \((-\infty, -2)\), \((-2, 4)\), and \((4, \infty)\) by the roots \( x = -2 \) and \( x = 4 \). Choose any value within an interval as a test point and substitute it into the inequality \( x^2 - 2x - 8 > 0 \). For example, testing \( x = -3 \) in the interval \((-\infty, -2)\) confirms it satisfies the inequality, whereas \( x = 0 \) within \((-2, 4)\) does not. Testing \( x = 5 \) shows the inequality holds in the interval \((4, \infty)\).

Utilizing test points is an indispensable method in solving quadratic inequalities, especially when determining where an inequality holds true. It helps reaffirm solutions derived through factoring and ensures accuracy in expressing final solutions.

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