Chapter 2: Problem 13
Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. $$ (3+4 i)(3-4 i) $$
Short Answer
Expert verified
The expression simplifies to 25 + 0i.
Step by step solution
01
Understand the Identity
Recognize that the expression \((3+4i)(3-4i)\) follows the pattern of the difference of squares, which is \((a+bi)(a-bi) = a^2 + b^2\). This identity simplifies the multiplication of complex conjugates.
02
Identify the Parts
Here, the real part \(a\) is 3 and the imaginary part \(b\) is 4. Notice that \((3+4i)\) and \((3-4i)\) are complex conjugates.
03
Apply the Formula
Substitute the values into the difference of squares formula: \[(3+4i)(3-4i) = 3^2 + 4^2 = 9 + 16\]
04
Simplify the Result
Add together the results from the previous calculation: \[9 + 16 = 25\]
05
Write in the Form a + bi
Since \(25\) is a real number, we can write this in the form \(a + bi\) where \(a = 25\) and \(b = 0\), so the expression is simply \(25 + 0i\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Conjugates
Complex conjugates play a crucial role in simplifying complex number expressions. When dealing with complex numbers, especially in multiplication, using complex conjugates can simplify calculations immensely. A complex number is typically expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit. A complex conjugate takes the form \(a - bi\).
- The original complex number: \(3 + 4i\)
- The conjugate: \(3 - 4i\)
Difference of Squares
The difference of squares is an algebraic identity that states \((a+b)(a-b) = a^2 - b^2\). This principle extends to complex numbers, becoming \((a+bi)(a-bi) = a^2 + b^2\). This adaptation helps simplify products of complex conjugates.Here is how it works step by step:
- Identify \(a\) and \(b\) from the complex numbers. In our exercise, \(a = 3\) and \(b = 4\).
- Plug these values into the difference of squares formula for complex numbers: \(a^2 + b^2 = 3^2 + 4^2\)
- Calculate \(a^2\) and \(b^2\):
- \(3^2 = 9\)
- \(4^2 = 16\)
- Add these results: \(9 + 16 = 25\)
Imaginary Numbers
Imaginary numbers are fundamental to complex numbers and involve the unit \(i\), which is defined as the square root of \(-1\). Real numbers are expanded by incorporating \(i\), forming complex numbers.
- The concept: \(i = \sqrt{-1}\).
- Allows real numbers to extend into the complex plane.
- Expressed as: \(a + bi\) where \(a\) is the real part and \(bi\) is the imaginary part.