Chapter 10: Problem 8
Exer. 1-8: Find the number. $$ C(5,5) $$
Short Answer
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Step by step solution
01
Understand the Combination Formula
The combination formula is used to find the number of ways to choose a subset of items from a larger set, without considering the order of selection. It is given by \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of items, \( r \) is the number of items to choose, and \( n! \) (n factorial) is the product of all positive integers up to \( n \).
02
Identify Parameters in the Formula
For the given problem, we have \( n = 5 \) and \( r = 5 \). We need to plug these values into the combination formula to find \( C(5, 5) \).
03
Substitute Values into the Formula
Using the formula \( C(5, 5) = \frac{5!}{5!(5-5)!} \), we substitute \( n = 5 \) and \( r = 5 \) into the formula.
04
Simplify the Factorials
Calculate each factorial:\[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] and \[ 0! = 1 \] (by definition). Substituting these into our expression, we have: \[ C(5,5) = \frac{120}{120 \times 1} \]
05
Perform Final Calculation
Simplify the expression \( \frac{120}{120 \times 1} \) to get \( 1 \). Therefore, \( C(5, 5) = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Factorials
In mathematics, a factorial is a simple yet crucial concept which you may often encounter, especially in permutations and combinations. A factorial is represented by an exclamation mark (!). It means that you multiply a sequence of descending natural numbers. For instance, the factorial of 5, written as 5!, is the product of all positive integers up to 5:
\[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]
Notably, the factorial of 0 is defined as 1 (\( 0! = 1 \)), which is an important identity in mathematics. This small but significant detail simplifies calculations involving 0 factorial, as you can see in the combination formula. Using factorials helps us calculate the number of possible arrangements or selections in many mathematical problems.
\[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \]
Notably, the factorial of 0 is defined as 1 (\( 0! = 1 \)), which is an important identity in mathematics. This small but significant detail simplifies calculations involving 0 factorial, as you can see in the combination formula. Using factorials helps us calculate the number of possible arrangements or selections in many mathematical problems.
- Factorials grow quickly: for large numbers, factorials become extremely large.
- An essential property of factorials is their recursive nature: \( n! = n \times (n-1)! \)
Introduction to Combinatorics
Combinatorics is an exciting branch of mathematics that deals with counting, arranging, and combining objects. It's like playing a puzzle where you explore different possibilities and outcomes. In our everyday life, combinatorics can help us figure out problems of selection and arrangement such as:
- Finding how many ways you can choose your clothes from a wardrobe without caring about which you wear first.
- Determining the number of possible combinations to unlock a password lock.
- Permutations consider the order of arrangement. For example, arranging books on a shelf.
- Combinations, used in our exercise here, ignore the order. The focus is solely on the selection of items, such as choosing committees from a larger group.
Exploring the Binomial Coefficient
The binomial coefficient, often represented by \( C(n, r) \) or \( \binom{n}{r} \), is a fundamental idea in combinatorics. It tells us how many ways we can choose \( r \) items from a total of \( n \) items where the order does not matter.
The formula for calculating the binomial coefficient is: \[ C(n, r) = \frac{n!}{r!(n-r)!} \]This is derived using factorials, which simplifies the process of finding our desired combinations. For example, using this formula, \( C(5, 5) \) calculates to:
The formula for calculating the binomial coefficient is: \[ C(n, r) = \frac{n!}{r!(n-r)!} \]This is derived using factorials, which simplifies the process of finding our desired combinations. For example, using this formula, \( C(5, 5) \) calculates to:
- The numerator, \( 5! = 120 \), represents the number of ways to arrange all items.
- The denominator, \( 5! \times 0! \), accounts for overcounting arrangements where the selection order doesn’t matter. Here \( 0! = 1 \), as defined, so the equation \( C(5, 5) = \frac{120}{120 \times 1} = 1 \).