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Without expanding completely, find the indicated term(s) in the expansion of the expression. $$ \left(x^{1 / 2}+y^{1 / 2}\right)^{8}, \quad \text { middle term } $$

Short Answer

Expert verified
The middle term is \( 70x^2y^2 \).

Step by step solution

01

Understand the Binomial Expansion

The expression \( (x^{1/2} + y^{1/2})^8 \) is a binomial expression raised to a power. In a binomial expansion, terms take the form \( \binom{n}{k} a^{n-k} b^k \), where \( n \) is the power of the binomial.
02

Identify the Middle Term Condition

Since the power \( n = 8 \), the expansion will have \( n + 1 = 9 \) terms. For an even power, the middle term is the \( \left(\frac{n}{2} + 1\right) \)-th term. Therefore, the middle term in this expansion is the 5th term.
03

Determine Middle Term Parameters

The 5th term in the expansion is given by \( \binom{8}{4} (x^{1/2})^{8-4} (y^{1/2})^4 \). Here, \( k = 4 \) because we're calculating the 5th term \( \left(\frac{8}{2} + 1 = 5\right) \).
04

Calculate the Middle Term

Find the binomial coefficient: \( \binom{8}{4} = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} = 70 \). Now substitute into the term: \( 70 \cdot (x^{1/2})^4 \cdot (y^{1/2})^4 = 70 \cdot x^2 \cdot y^2 \).
05

Write the Middle Term

The middle term of the expansion \( (x^{1/2} + y^{1/2})^8 \) is \( 70x^2y^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Theorem
The binomial theorem is a fundamental concept in algebra that helps us expand expressions of the form \((a + b)^n\) without having to perform repetitive multiplication. It provides a formula to find each term in the expansion. According to the binomial theorem, each term in the expansion is given by the formula:
  • \( \binom{n}{k}a^{n-k}b^k \)
Here's what these symbols mean:- \( n \) is the exponent, or the power, to which the binomial is raised.- \( k \) is the specific term's number in the sequence. It starts from 0.- \( \binom{n}{k} \) is the binomial coefficient, which we'll explore further later on.- \( a \) and \( b \) are the terms inside the binomial.This theorem is immensely helpful because it allows you to figure out any term in a binomial expansion directly, making calculations with large exponents more manageable.
Middle Term
The middle term in a binomial expansion can be found by considering the number of terms produced in the expansion. For any binomial expansion with a power \( n \), the total number of terms is \( n + 1 \). This is because you start counting from \( k = 0 \) to \( k = n \).

When \( n \) is even, the middle term is located at \((\frac{n}{2} + 1)\)-th position in the sequence. If \( n \) is odd, there will be exactly two middle terms, located symmetrically around the center.
  • For \((x^{1/2} + y^{1/2})^8\), the power \( n = 8 \) is even.
  • This means there are \( 9 \) terms, making the middle term the 5th one.
The middle term plays a critical role when finding specific values or simplifying expressions.
Binomial Coefficient
The binomial coefficient is a key component in the binomial theorem. It is denoted as \( \binom{n}{k} \), a notation that comes directly from combinations. This symbol represents how many ways \( k \) items can be chosen from \( n \) items.

Mathematically, it is calculated using the formula:
  • \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]
Here's what this formula tells us:- \( n! \) (n factorial) is the product of all positive integers up to \( n \).- \( k! \) is the product of all positive integers up to \( k \).- \((n-k)!\) is the factorial of \( n-k \).In our example \((x^{1/2} + y^{1/2})^8\), to find the coefficient for the middle term, you use \( \binom{8}{4} \). Calculating this, you get \( 70 \), which is how the middle term is weighted in the entire expansion.
Algebra
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. It provides a way to solve equations and understand relationships using letters and other general symbols to represent numbers.In the context of the binomial expansion, algebra allows us:
  • To use the binomial theorem as a tool for making expansions manageable.
  • To compute and reason with the middle terms and coefficients.
  • To manipulate and simplify expressions like \((x^{1/2} + y^{1/2})^8\) without exhaustive multiplication.
Algebra is not just limited to expanding expressions; it also enhances our ability to think logically and solve complex problems, all by applying simple rules systematically. It's a powerful language in mathematics that helps us articulate and solve real-world problems.

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