Chapter 10: Problem 19
Given a geometric sequence with \(a_{4}=4\) and \(a_{7}=12\), find \(r\) and \(a_{10}\) .
Short Answer
Expert verified
The common ratio \(r\) is \(\sqrt[3]{3}\) and \(a_{10} = 36\).
Step by step solution
01
Understanding the geometric sequence formula
The general formula for the \(n\)th term of a geometric sequence is given by \(a_{n} = a_1 \cdot r^{n-1}\), where \(a_1\) is the first term and \(r\) is the common ratio.
02
Set up equations based on given terms
Given \(a_4 = 4\) and \(a_7 = 12\), we can write two equations using the formula. For \(a_4\), \(a_1 \cdot r^3 = 4\), and for \(a_7\), \(a_1 \cdot r^6 = 12\).
03
Solve for the ratio \(r\)
Divide the equation for \(a_7\) by the equation for \(a_4\) to eliminate \(a_1\): \[\frac{a_1 \cdot r^6}{a_1 \cdot r^3} = \frac{12}{4}\]. This simplifies to \(r^3 = 3\). Solving for \(r\), we have \(r = \sqrt[3]{3}\).
04
Calculate \(a_1\) using \(r\)
Substitute \(r = \sqrt[3]{3}\) back into the equation for \(a_4 = a_1 \cdot r^3 = 4\): \(a_1 \cdot 3 = 4\). Therefore, \(a_1 = \frac{4}{3}\).
05
Find \(a_{10}\)
Now, use the formula \(a_n = a_1 \cdot r^{n-1}\) to find \(a_{10}\): \(a_{10} = \frac{4}{3} \cdot (\sqrt[3]{3})^9\). Simplifying gives \(a_{10} = \frac{4}{3} \times 3^3 = \frac{4}{3} \times 27 = 36\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Ratio
In a geometric sequence, the common ratio is a crucial element that remains constant between successive terms. Think of it as the factor by which you multiply a term to get the next one.
For example, if you have a geometric sequence like 2, 4, 8, 16, the common ratio here is 2 because each term is obtained by multiplying the previous term by 2.
For example, if you have a geometric sequence like 2, 4, 8, 16, the common ratio here is 2 because each term is obtained by multiplying the previous term by 2.
- The common ratio is denoted by the letter \( r \).
- It can be found by dividing any term in the sequence by the preceding term, except the first term.
Geometric Sequence Formula
The geometric sequence formula is a powerful tool that helps you find the terms in a sequence effortlessly. It tells us that given a first term \( a_1 \) and a common ratio \( r \), the \( n \)-th term can be calculated using: \( a_n = a_1 \cdot r^{n-1} \).This formula becomes extremely handy as it allows for exact calculations without needing to list all terms of the sequence.
- \( a_1 \) represents the first term in the sequence.
- \( n \) denotes the term number you're interested in.
- \( r \) is the common ratio.
Nth Term of Geometric Sequence
Finding the \( n \)th term of a geometric sequence allows you to pinpoint any particular term without needing to build upon each preceding term. Let's say you're tasked with finding the 10th term of a sequence. You don't need terms 1 through 9 explicitly; rather, simply use the formula: \( a_n = a_1 \cdot r^{n-1} \). For our problem, after determining our initial term \( a_1 = \frac{4}{3} \) and common ratio \( r = \sqrt[3]{3} \), you compute the 10th term as follows:
- Position the values in the formula: \( a_{10} = \frac{4}{3} \cdot (\sqrt[3]{3})^9 \).
- Simplify to find \( 27 \), breaking it down as \( \frac{4}{3} \times 27 = 36 \).