Chapter 1: Problem 44
Find the solutions of the equation $$ x^{2}+3 x+6=0 $$
Short Answer
Expert verified
The solutions are \( x = \frac{-3 \pm i\sqrt{15}}{2} \).
Step by step solution
01
Identify the Equation Type
The given equation is a quadratic equation in the form \( ax^2 + bx + c = 0 \), where \( a = 1 \), \( b = 3 \), and \( c = 6 \). We need to use the quadratic formula to find the roots.
02
Recall the Quadratic Formula
The quadratic formula for solving \( ax^2 + bx + c = 0 \) is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). We will apply this formula using our values of \( a \), \( b \), and \( c \).
03
Calculate the Discriminant
The discriminant of a quadratic equation is given by \( b^2 - 4ac \). For our equation, substitute \( b = 3 \), \( a = 1 \), and \( c = 6 \) into the expression: \( (3)^2 - 4 \times 1 \times 6 = 9 - 24 = -15 \).
04
Determine the Nature of the Roots
Since the discriminant is \(-15\), which is less than zero, the equation does not have real roots. Instead, it has two complex roots.
05
Solve for the Imaginary Roots
Using the quadratic formula, substitute \( a = 1 \), \( b = 3 \), and the discriminant of \(-15\). The solutions are \( x = \frac{-3 \pm \sqrt{-15}}{2} = \frac{-3 \pm i\sqrt{15}}{2} \).
06
Final Roots
The final solutions for the equation are \( x = \frac{-3 + i\sqrt{15}}{2} \) and \( x = \frac{-3 - i\sqrt{15}}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to find solutions to quadratic equations, which are equations of the form \( ax^2 + bx + c = 0 \). To find the roots of such equations, you can use the quadratic formula:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Complex Roots
Complex roots occur when the solutions to a quadratic equation are not real numbers. This happens when the discriminant (the value inside the square root in the quadratic formula) is negative.
In our problem, the discriminant was \(-15\), which indicates the presence of complex roots. Complex numbers are numbers that have both a real and an imaginary component. They are expressed in the form \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. The letter 'i' stands for the imaginary unit, which is the square root of \(-1\).
For the exercise, our solution turned out to be:
In our problem, the discriminant was \(-15\), which indicates the presence of complex roots. Complex numbers are numbers that have both a real and an imaginary component. They are expressed in the form \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. The letter 'i' stands for the imaginary unit, which is the square root of \(-1\).
For the exercise, our solution turned out to be:
- \( x = \frac{-3 \pm i\sqrt{15}}{2} \)
Discriminant Calculation
Calculating the discriminant is a crucial step to understanding the nature of the roots of a quadratic equation. The discriminant is determined using the formula:
When these values are plugged into the formula, we calculate:
- \( b^2 - 4ac \)
When these values are plugged into the formula, we calculate:
- \( (3)^2 - 4 \times 1 \times 6 = 9 - 24 = -15 \)
Nature of Roots
Understanding the nature of roots is essential for interpreting the solutions of a quadratic equation. The nature is determined primarily by the discriminant:
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root, or a repeated root.
- If the discriminant is negative, as in our exercise, the roots are complex.