/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 87 Find the sum. $$\sum_{i=1}^{5}... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the sum. $$\sum_{i=1}^{5}(2 i+1)$$

Short Answer

Expert verified
The sum of the series from i=1 to i=5 for the function \(2i+1\) is 35.

Step by step solution

01

Calculate the term for i=1

Substitute i=1 into equation \(2i+1\). This equals \(2*1+1 = 3\)
02

Calculate the term for i=2

Substitute i=2 into equation \(2i+1\). This equals \(2*2+1 = 5\)
03

Calculate the term for i=3

Substitute i=3 into equation \(2i+1\). This equals \(2*3+1 = 7\)
04

Calculate the term for i=4

Substitute i=4 into equation \(2i+1\). This equals \(2*4+1 = 9\)
05

Calculate the term for i=5

Substitute i=5 into equation \(2i+1\). This equals \(2*5+1 = 11\)
06

Add the calculated results

Add together all the calculated results from i=1 to i=5. This equals \(3+5+7+9+11 = 35\)

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