/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 What are the dimensions of a rec... [FREE SOLUTION] | 91Ó°ÊÓ

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What are the dimensions of a rectangular tract of land with a perimeter of 40 miles and an area of 96 square miles?

Short Answer

Expert verified
The dimensions of the rectangular tract of land are 12 miles by 8 miles or 8 miles by 12 miles.

Step by step solution

01

Set Up Perimeter Equation

The perimeter \( P \) of a rectangle is given by \( P = 2l + 2w \), where \( l \) is the length and \( w \) is the width. In the problem, it's stated that \( P = 40 \) miles. Substituting these values into the equation gives: \( 40 = 2l + 2w \)
02

Simplify Perimeter Equation

Let's simplify Equation 1: \( 2l + 2w = 40 \), by dividing the entire equation by 2. This gives: \( l + w = 20 \)
03

Set Up Area Equation

The area \( A \) of a rectangle is given by \( A = l × w \). The problem states that \( A = 96 \) square miles. This can be written as: \( l × w = 96 \)
04

Solve the Equations

Now we have a system of two equations: \( l + w = 20 \) and \( l × w = 96 \). To solve these, select \( w = 20 - l \) from the first equation, and substitute into the second one. This gives a quadratic equation: \( l × (20 - l) = 96 \), which simplifies to \( l² - 20l + 96 = 0 \). Solving this quadratic equation for \( l \), we get \( l = 12, 8 \). Thus the lengths of the rectangular tract can be either 12 miles and 8 miles. The width will correspondingly be 8 miles and 12 miles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Perimeter of a Rectangle
Perimeter is an important concept in geometry, especially when dealing with rectangles. It refers to the total distance around the boundary of a rectangle. To calculate it, we simply add up the lengths of all four sides. For a rectangle, the opposite sides are equal in length, which gives us the formula: \( P = 2l + 2w \) where \( P \) stands for perimeter, \( l \) for length, and \( w \) for width.

When solving problems involving the perimeter of a rectangle, it's common to be given the perimeter and one other variable—either the length or the width—and be asked to solve for the remaining dimension. This problem-solving task often requires algebraic manipulation, such as simplifying equations and isolating variables, to find the dimensions that satisfy the given perimeter.
Calculating the Area of a Rectangle
The area of a rectangle is a measure of the space contained within its boundaries. It can be found by multiplying the length by the width of the rectangle. The formula is quite straightforward: \( A = l \times w \) where \( A \) represents the area, \( l \) represents the length, and \( w \) represents the width.

When approached with a problem that provides the area and one dimension, the goal is to use these given values to calculate the missing dimension. This task often involves setting up an equation and finding a value that, when multiplied by the known dimension, results in the given area. Understanding how to manipulate these formulae allows us to tackle more complex problems, such as those that also involve the rectangle's perimeter.
Solving Quadratic Equations
Quadratic equations are a fundamental part of algebra and they frequently appear in various mathematical problems including geometric ones. These equations can be identified by the highest power of the variable being two, and they have the general form \( ax^2 + bx + c = 0 \). Solving quadratic equations can be done using different methods, such as factoring, completing the square, or using the quadratic formula.

To solve these types of equations in the context of geometry problems, like finding the dimensions of a rectangle when given the area and perimeter, we often substitute one variable in terms of another. This leads to a quadratic equation that we can solve for the remaining unknown value. In our example, we derived \( l^2 - 20l + 96 = 0 \) and solved it to find the possible lengths of the rectangle, which then allowed us to determine the corresponding widths.

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