/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Solve the system graphically. Ve... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the system graphically. Verify your solutions algebraically. $$\left\\{\begin{array}{r} -5 x+2 y=-2 \\ x-2 y=6 \end{array}\right.$$

Short Answer

Expert verified
The solution for the system of equations is \(x = 2\) and \(y = 6\).

Step by step solution

01

Graphing the Equations

First, convert the equations into slope-intercept form \(y = mx + b\).For the first equation \(-5x + 2y = -2\), rewrite it to get \(y = 2.5x + 1\). For the second equation \(x - 2y = 6\), rewrite it to get \(y = 0.5x - 3\). Plot these two equations on a graph to find the intersection point.
02

Find the Intersection

The intersection point of the two lines is the solution to the system of equations. For the equations \(y = 2.5x + 1\) and \(y = 0.5x - 3\), they intersect at \((2, 6)\). Therefore, the solution to the system of equations is \(x = 2\) and \(y = 6\).
03

Verify the Solution

Insert the values for \(x\), which is 2, and \(y\), which is 6, into the original equations to verify. The original equations are \(-5x + 2y = -2\) and \(x - 2y = 6\). Substituting the values for \(x\) and \(y\) into these equations verifies that the two equations hold true, showing that \((2, 6)\) is indeed the solution to the system of equations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope-Intercept Form
The slope-intercept form is one of the most common ways to express linear equations. It is written as \(y = mx + b\), where \(m\) represents the slope and \(b\) indicates the y-intercept of the line. This format is very helpful because it makes graphing straightforward. Knowing the slope tells you how steep the line is and which direction it goes.
Slope \(m\) tells us how the line rises or falls as we move from left to right. For instance, a positive slope means the line will rise, while a negative slope means the line will fall. The y-intercept \(b\) is the point where the line crosses the y-axis, which helps in quickly plotting the line on a graph.
When solving equations, converting equations into slope-intercept form allows for easier graphing and comparison between different lines. In this exercise, the equations were transformed into this form so they could be easily graphed to find their intersection.
System of Equations
A system of equations involves two or more equations with the same set of variables. These systems can have one solution, no solution, or infinitely many solutions. When you graph the equations from a system, you are essentially plotting lines on the same graph to see how they interact.
To solve a system graphically, as in this exercise, you draw each equation on a graph. Each line represents one equation. The goal is to find if, and where, these lines cross each other. If they intersect at a single point, that point is the unique solution for the system, indicating the values of the variables that satisfy both equations.
  • If the lines are parallel, they have no intersection and therefore no solution.
  • If the lines coincide completely, there are infinitely many solutions, as the lines share all points.
  • In this example, the lines intersect at one point, providing a unique solution.
Intersection of Lines
Finding the intersection of lines is the key to solving a system of equations graphically. The intersection point is where the lines representing the equations meet on the graph. This point provides the solution to the system of equations, revealing the values of the variables that satisfy all equations simultaneously.
To determine the intersection:
  • Begin by graphing each equation on the same set of axes using their slope-intercept forms.
  • Carefully identify the point where the lines cross.
  • This intersection is the solution \((x, y)\). In our exercise, this was found to be \((2, 6)\).
Verifying this solution algebraically confirms it fits both original equations, ensuring accuracy. This step reinforces that the graphical approach yielded a correct solution.

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Most popular questions from this chapter

The sums have been evaluated. Solve the given system for \(a\) and \(b\) to find the least squares regression line for the points. Use a graphing utility to confirm the results. $$\left\\{\begin{aligned} 6 b+15 a &=23.6 \\ 15 b+55 a &=48.8 \end{aligned}\right.$$

Solve for \(x\) $$\left|\begin{array}{rr} x & 4 \\ -1 & x \end{array}\right|=20$$

Business \(A\) minor league baseball team had a total attendance one evening of \(1175 .\) The tickets for adults and children sold for \(\$ 15\) and \(\$ 12,\) respectively. The ticket revenue that night was \(\$ 16,275\) (a) Create a system of linear equations to find the numbers of adults \(A\) and children \(C\) at the game. (b) Solve your system of equations by elimination or by substitution. Explain your choice. (c) Use the intersect feature or the zoom and trace features of a graphing utility to solve your system.

(A) find the determinant of \(A,\) (b) find \(A^{-1},\) (c) find \(\operatorname{det}\left(A^{-1}\right),\) and (d) compare your results from parts (a) and (c). Make a conjecture based on your results. $$A=\left[\begin{array}{rr} 1 & 2 \\ -2 & 2 \end{array}\right]$$

Consider the circuit in the figure. The currents \(I_{1}, I_{2},\) and \(I_{3},\) in amperes, are given by the solution of the system of linear equations \(\left\\{\begin{aligned} 2 I_{1} &+4 I_{3}=E_{1} \\ I_{2}+4 I_{3} &=E_{2} \\\ I_{1}+I_{2}-I_{3} &=0 \end{aligned}\right.\) where \(E_{1}\) and \(E_{2}\) are voltages. Use the inverse of the coefficient matrix of this system to find the unknown currents for the given voltages. \(E_{1}=10\) volts, \(E_{2}=10\) volts

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