/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Operations with Matrices Find, i... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Operations with Matrices Find, if possible, \((a) A+B,(b) A-B,(c) 3 A,\) and \((d) 3 A-2 B.\) Use the matrix capabilities of a graphing utility to verify your results. $$A=\left[\begin{array}{ll} 1 & 2 \\ 2 & 1 \end{array}\right], \quad B=\left[\begin{array}{rr} -3 & -2 \\ 4 & 2 \end{array}\right]$$

Short Answer

Expert verified
The result for \(A+B\) is \(\left[\begin{array}{ll} -2 & 0 \ 6 & 3 \ \end{array}\right]\), \(A-B\) is \(\left[\begin{array}{ll} 4 & 4 \ -2 & -1 \ \end{array}\right]\), \(3A\) is \(\left[\begin{array}{ll} 3 & 6 \ 6 & 3 \ \end{array}\right]\), and \(3A-2B\) is \(\left[\begin{array}{ll} 9 & 10 \ 2 & -1 \ \end{array}\right]\). Compare with the results from a graphing utility to verify.

Step by step solution

01

(a) Addition of Matrices

To add two matrices, their dimensions must be identical. Then add corresponding elements from each matrix to get the sum. Given: \(A=\left[\begin{array}{ll} 1 & 2 \ 2 & 1 \ \end{array}\right], \quad B=\left[\begin{array}{rr} -3 & -2 \ 4 & 2 \ \end{array}\right] \), The sum of A and B is, \(A+B = \left[\begin{array}{ll} 1+(-3) & 2+(-2) \ 2+4 & 1+2 \ \end{array}\right] = \left[\begin{array}{ll} -2 & 0 \ 6 & 3 \ \end{array}\right]\)
02

(b) Subtraction of Matrices

For subtracting two matrices, similar to addition, their dimensions should be the same. Subtract corresponding elements from each matrix. The difference of A and B is, \(A-B = \left[\begin{array}{ll} 1-(-3) & 2-(-2) \ 2-4 & 1-2 \ \end{array}\right] = \left[\begin{array}{ll} 4 & 4 \ -2 & -1 \ \end{array}\right]\)
03

(c) Multiplication of Matrix by a Scalar

The multiplication of a scalar with a matrix means that each element of the matrix is multiplied by the scalar. The multiplication of A by 3 is, \(3A = 3*\left[\begin{array}{ll} 1 & 2 \ 2 & 1 \ \end{array}\right] = \left[\begin{array}{ll} 3*1 & 3*2 \ 3*2 & 3*1 \ \end{array}\right] = \left[\begin{array}{ll} 3 & 6 \ 6 & 3 \ \end{array}\right]\)
04

(d) Combination of Matrix Operations

Combining matrix operations require the same approach. Multiply the matrices A and B by scalars 3 and 2 respectively, then subtract. \(3A-2B = 3*\left[\begin{array}{ll} 1 & 2 \ 2 & 1 \ \end{array}\right] - 2*\left[\begin{array}{rr} -3 & -2 \ 4 & 2 \ \end{array}\right] = \left[\begin{array}{ll} 3*1-2*(-3) & 3*2-2*(-2) \ 3*2-2*4 & 3*1-2*2 \ \end{array}\right] = \left[\begin{array}{ll} 9 & 10 \ 2 & -1 \ \end{array}\right]\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Addition
Matrix addition is the simplest binary operation that can be performed with two matrices. To add two matrices, they must be of the same size, meaning they have the same number of rows and columns. The process then involves adding each corresponding element from the two matrices to find the sum.

For example, given two matrices:
A = \(\left[\begin{array}{cc} a & b \ c & d \end{array}\right]\) and B = \(\left[\begin{array}{cc} e & f \ g & h \end{array}\right]\),the matrix sum A + B is given by \(\left[\begin{array}{cc} a+e & b+f \ c+g & d+h \end{array}\right]\).

Adding matrices is straightforward when you focus on each element at a time, always matching the row and column positions. It is often helpful to visualize this operation as overlaying one matrix on top of another and then combining the numbers.
Matrix Subtraction
Matrix subtraction is quite similar to matrix addition and follows the same rules for size compatibility. Just as with addition, the two matrices in question must have identical dimensions, meaning they should have the same number of rows and columns.

For instance, if we consider the same matrices A and B as before, the result of matrix subtraction, A - B, will be formed by subtracting the corresponding elements:
\( A - B = \left[\begin{array}{cc} a-e & b-f \ c-g & d-h \end{array}\right]\).

The key here is to take each element pair and simply perform a subtraction, element by element. Subtraction often helps in representing the difference or change between two sets of data points reflected by the matrices.
Scalar Multiplication of Matrices
Scalar multiplication involves the multiplication of a matrix by a single number, known as a scalar. In this operation, each element of the matrix is multiplied by the scalar to yield a new matrix.

For example, if we have a scalar k and matrix A as before, the result of the scalar multiplication kA is obtained by multiplying each element of A by k:
\( kA = k\cdot\left[\begin{array}{cc} a & b \ c & d \end{array}\right] = \left[\begin{array}{cc} ka & kb \ kc & kd \end{array}\right]\).

This operation is useful in situations where we need to rescale a dataset or adjust the weighting of a matrix's elements. Remembering to multiply every single element by the scalar is critical in correctly performing this operation.
Combining Matrix Operations
Combining matrix operations often involves performing more than one type of operation sequentially. This could mean adding and then multiplying, or subtracting and then taking a scalar multiple, among other combinations. It's essential to follow the rules of each operation and to conduct them in the given order.

For instance, if you are given the operation 3A - 2B, you need to first perform scalar multiplication on both matrices A and B, respectively, and then subtract the resultant matrices. It's a step by step process.
  1. Multiply matrix A by 3.
  2. Multiply matrix B by 2.
  3. Subtract the matrix resulting from 2 from the matrix resulting from 1.

Being attentive to the order of operations is crucial, as reversing the steps can lead to an entirely different result.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sales The projected sales \(S\) (in millions of dollars) of two clothing retailers from 2015 through 2020 can be modeled by \(\left\\{\begin{array}{ll}S-149.9 t=415.5 & \text { Retailer } \mathrm{A} \\\ S-183.1 t=117.3 & \text { Retailer } \mathrm{B}\end{array}\right.\) where \(t\) is the year, with \(t=5\) corresponding to 2015 (a) Solve the system of equations using the method of your choice. Explain why you chose that method. (b) Interpret the meaning of the solution in the context of the problem. (c) Interpret the meaning of the coefficient of the \(t\) -term in each model. (d) Suppose the coefficients of \(t\) were equal and the models remained the same otherwise. How would this affect your answers in parts (a) and (b)?

(A) find the determinant of \(A,\) (b) find \(A^{-1},\) (c) find \(\operatorname{det}\left(A^{-1}\right),\) and (d) compare your results from parts (a) and (c). Make a conjecture based on your results. $$A=\left[\begin{array}{rrr} -1 & 3 & 2 \\ 1 & 3 & -1 \\ 1 & 1 & -2 \end{array}\right]$$

Determine whether the statement is true or false. Justify your answer. Writing Briefly explain whether or not it is possible for a consistent system of linear equations to have exactly two solutions.

Consider the system of equations. $$\left\\{\begin{array}{l} y=b^{x} \\ y=x^{b} \end{array}\right.$$ (a) Use a graphing utility to graph the system of equations for \(b=2\) and \(b=4\) (b) For a fixed value of \(b > 1,\) make a conjecture about the number of points of intersection of the graphs in part (a).

Write the matrix in row-echelon form. Remember that the row-echelon form of a matrix is not unique. $$\left[\begin{array}{rrrr} 1 & 2 & -1 & 3 \\ 3 & 7 & -5 & 14 \\ -2 & -1 & -3 & 8 \end{array}\right]$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.