Chapter 7: Problem 22
Use the dot product to find the magnitude of \(\mathbf{u}.\) $$\mathbf{u}=9 \mathbf{i}$$
Short Answer
Expert verified
The magnitude of the vector \(\mathbf{u} = 9 \mathbf{i}\) is 9.
Step by step solution
01
Identify the vector
The given vector is \(\mathbf{u}=9 \mathbf{i}\)
02
Apply the formula for magnitude using the dot product
The formula for finding the magnitude of a vector using the dot product, when the components of the vector are \(u_{1}, u_{2}, ..., u_{n}\), is \(\|u\| = \sqrt{u_{1}^2 + u_{2}^2 + \ldots + u_{n}^2}\) . In this case, the vector only has the i component, so we only have \(u_1\), which is 9.
03
Calculate
Substitute \(u_1 = 9\) into the formula to get \|u\| = \(\sqrt{9^2}\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
The dot product is a fundamental operation in vector algebra. It involves multiplying the corresponding components of two vectors and summing the results. This operation can be symbolized as \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + \ldots + a_nb_n \). The dot product is especially useful for calculating the angle between two vectors and determining the magnitude of a vector itself.
When dealing with a vector such as \( \mathbf{u} = 9 \mathbf{i} \), the dot product can help us calculate the magnitude straightforwardly, as shown in the given exercise. For a single component vector like this one (with only an \( \mathbf{i} \) component), the dot product simply becomes \( 9 \times 9 \), resulting in 81.
It's interesting how the dot product relates to magnitudes and angles:
When dealing with a vector such as \( \mathbf{u} = 9 \mathbf{i} \), the dot product can help us calculate the magnitude straightforwardly, as shown in the given exercise. For a single component vector like this one (with only an \( \mathbf{i} \) component), the dot product simply becomes \( 9 \times 9 \), resulting in 81.
It's interesting how the dot product relates to magnitudes and angles:
- For angles: \( \mathbf{a} \cdot \mathbf{b} = \|\mathbf{a}\| \|\mathbf{b}\| \cos(\theta) \), where \( \theta \) is the angle between vectors.
- A dot product of zero indicates perpendicular vectors.
Unit Vectors
Unit vectors are crucial in vector algebra as they are the building blocks for any vector directions. Essentially, a unit vector has a magnitude of 1 and is used to denote direction without regard to magnitude. They are typically symbolized using a small bold letter with a hat, like \( \mathbf{\hat{i}}, \mathbf{\hat{j}}, \) and \( \mathbf{\hat{k}} \), representing the direction along the x, y, and z axes respectively.
In our exercise, the vector \( \mathbf{u} = 9 \mathbf{i} \) signifies a vector with a direction parallel to the x-axis. The \( \mathbf{i} \) in this vector is the unit vector along the x-axis.
In our exercise, the vector \( \mathbf{u} = 9 \mathbf{i} \) signifies a vector with a direction parallel to the x-axis. The \( \mathbf{i} \) in this vector is the unit vector along the x-axis.
- To convert a vector into its unit vector form, divide the vector by its magnitude.
- Unit vectors help standardize calculations, especially in physics, where direction needs to be isolated.
Vector Components
Vector components divide a vector into parts based on different axes, which helps in simplifying many engineering and physics problems. Each component impacts the vector's behavior along a specified direction. For example, in a 2D plane, a vector \( \mathbf{v} \) could have components along the x and y axes: \( \mathbf{v} = v_x \mathbf{i} + v_y \mathbf{j} \). These components describe how much of the vector's magnitude affects each axis.
Understanding vector components is essential because:
Understanding vector components is essential because:
- They allow representation of any vector in multi-dimensional space.
- Help in breaking down forces, velocities, and other quantities in physics.