Chapter 7: Problem 111
Use DeMoivre's Theorem to find the indicated power of the complex number. Write the result in standard form. $$2(\sqrt{3}-i)^{5}$$
Short Answer
Expert verified
The fifth power of the complex number \(2(\sqrt{3}-i)\) is \(32\sqrt{3} - 32i\).
Step by step solution
01
Convert to trigonometric form
A complex number can be written in the form \( r(\cos\theta + i\sin\theta)\), where \( r\) is the modulus of the complex number and \( \theta\) is the argument. The modulus, \( r\), is calculated as \(\sqrt{a^2 + b^2}\), where a and b are the real and imaginary parts of the complex number respectively. The argument, \( \theta\), can be found using the formula \( \tan^{-1} (b/a)\). Thus, for the complex number \(\sqrt{3} - i\), we have \( r = \sqrt{(\sqrt{3})^2 + (-1)^2} = 2\) and \( \theta = \tan^{-1}(-1/\sqrt{3}) = -\pi/6\). So the complex number in trigonometric form is \( 2(\cos(-\pi/6) + i\sin(-\pi/6))\).
02
Apply DeMoivre's Theorem
According to DeMoivre's Theorem, to find the 5th power of this complex number, simply multiply the angle by 5 and raise \( r\) to the fifth power: \( 2^5(\cos 5(-\pi/6) + i\sin 5(-\pi/6)) = 32(\cos(-5\pi/6) + i\sin(-5\pi/6))\).
03
Convert back to standard form
To convert back to standard form, evaluate the trigonometric functions: \( 32(\cos(-5\pi/6) + i\sin(-5\pi/6)) = 32((\sqrt{3}/2) - i/2) = 16\sqrt{3} - 16i\).
04
Multiply by given constant
Finally, multiply this result by the original given constant 2, getting \(2(16\sqrt{3} - 16i) = 32\sqrt{3} - 32i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are a fundamental concept in mathematics, which extend the idea of one-dimensional real numbers to two dimensions. They can be expressed in the form of \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part multiplied by the imaginary unit \(i\). Here, \(i\) is defined such that \(i^2 = -1\), allowing for the representation of all numbers.
- Real Part: The component \(a\) of the complex number that lies on the horizontal axis (real axis).
- Imaginary Part: The component \(b\), which includes \(i\), plotted on the vertical axis (imaginary axis).
- Imaginary Unit: \(i\), where \(i^2 = -1\).
Trigonometric Form
Trigonometric form is a way to represent complex numbers using polar coordinates. This is incredibly useful for multiplying, dividing, and raising complex numbers to powers, due to the relationship with angles. A complex number \(z = a + bi\) can be expressed as \(r(\cos \theta + i\sin \theta)\), where \(r\) is the modulus and \(\theta\) is the argument.
- Modulus \(r\): Represents the distance of the complex number from the origin in the complex plane.
- Argument \(\theta\): Represents the angle the complex number makes with the positive real axis.
Standard Form
The standard form of a complex number is the Cartesian form given as \(a + bi\). This form is straightforward, allowing easy addition, subtraction, and interpretation. It's easily related to graphing, as it directly reflects operations in a standard xy-plane.
- Addition and Subtraction: Performed component-wise, combining like terms.
- Graphical Representation: Easier to visualize as points or vectors on the complex plane.
- Simplification: Helpful for presenting the final results, like in the given problem where \(2(16\sqrt{3} - 16i)\) becomes \(32\sqrt{3} - 32i\).
Modulus and Argument
The modulus and argument are crucial components when dealing with complex numbers, especially in their trigonometric form. They help in rewriting the complex number in a way that is optimal for exponentiation and root calculations.
Modulus \(r\)
- Calculated as \(\sqrt{a^2 + b^2}\).
- Represents the "size" of the complex number.
Argument \(\theta\)
- Found using the formula \(\theta = \tan^{-1}(b/a)\).
- Indicates the direction or angle of the complex number in the plane.