Chapter 7: Problem 108
Use DeMoivre's Theorem to find the indicated power of the complex number. Write the result in standard form. $$(2+2 i)^{6}$$
Short Answer
Expert verified
The sixth power of the complex number (2+2i) is equal to \(0 - 64i\).
Step by step solution
01
Convert to Polar Form
The complex number \(2+2i\) can be converted into polar form using the equations \(r = \sqrt{a^2 + b^2}\) and \(\theta = \arctan{\left(\frac{b}{a}\right)}\), where \(r\) and \(\theta\) are the magnitude and argument of the complex number respectively. For this complex number, \(a = 2\) and \(b = 2\), so \(r = \sqrt{2^2+2^2} = 2\sqrt{2}\) and \(\theta = \arctan{\left(\frac{2}{2}\right)} = \frac{\pi}{4}\). Hence, \(2+2i = 2\sqrt{2}(\cos{\frac{\pi}{4}} + i \sin{\frac{\pi}{4}})\).
02
Apply DeMoivre's Theorem
DeMoivre's Theorem states that \((r(\cos{\theta} + i \sin{\theta}))^n = r^n(\cos{n\theta} + i \sin{n\theta})\). Applying the theorem to our complex number gives \((2\sqrt{2}(\cos{\frac{\pi}{4}} + i \sin{\frac{\pi}{4}}))^6 = (2\sqrt{2})^6(\cos{6 \cdot \frac{\pi}{4}} + i \sin{6 \cdot \frac{\pi}{4}}) = 64(\cos{\frac{3\pi}{2}} + i \sin{\frac{3\pi}{2}}).\)
03
Convert to Standard Form
Converting back to standard form is done by evaluating the real and imaginary parts separately. Here we have \(64(\cos{\frac{3\pi}{2}} + i \sin{\frac{3\pi}{2}}) = 64(0 + i(-1)) = 0 - 64i.\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are numbers that have both a real and an imaginary part, of the form:
- The real part, often denoted by 'a', represents a number on the standard number line.
- The imaginary part, denoted by 'b', includes the imaginary unit 'i', where 'i' is defined as the square root of -1.
- Here, the real part 'a' is 2.
- The imaginary part 'b' is also 2.
Polar Form
The polar form of a complex number provides a different way to express it, based on magnitude and angle:
- Magnitude (or modulus), denoted as 'r', is the distance of the complex number from the origin in a complex plane. It's calculated with: \( r = \sqrt{a^2 + b^2} \).
- Argument (or angle), denoted as '\( \theta \)', is the angle formed with the positive real axis. It is found using: \( \theta = \arctan{(\frac{b}{a})} \).
Standard Form
In many instances, it's helpful or necessary to convert complex numbers back into their standard form (a + bi):
In our example, after raising the polar form of 2 + 2i to the sixth power using DeMoivre's Theorem, we find that \(64(\cos{\frac{3\pi}{2}} + i \sin{\frac{3\pi}{2}})\) equals \(0 - 64i\). This solution is expressed in standard form as simply -64i, where the real part is 0 and the imaginary part is -64.
- This format separates the real and imaginary parts, making certain mathematical manipulations and interpretations easier.
In our example, after raising the polar form of 2 + 2i to the sixth power using DeMoivre's Theorem, we find that \(64(\cos{\frac{3\pi}{2}} + i \sin{\frac{3\pi}{2}})\) equals \(0 - 64i\). This solution is expressed in standard form as simply -64i, where the real part is 0 and the imaginary part is -64.
Magnitude and Argument
The magnitude and argument are vital components of a complex number when expressed in polar form:
- The magnitude or modulus (r) measures the size or absolute value of the complex number. It's computed with \( r = \sqrt{a^2 + b^2} \), showing how far the number is from the origin.
- The argument (\( \theta \)) tells us the direction of the number from the positive real axis, typically calculated by \( \theta = \arctan{(\frac{b}{a})} \).