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Find the exact value of each expression, if possible, without using a calculator. (a) arctan 1 (b) \(\arccos (-1)\)

Short Answer

Expert verified
(a) The exact value of arctan 1 is \(\pi/4\). (b) The exact value of \(\arccos (-1)\) is \(\pi\).

Step by step solution

01

Calculate arctan 1

The arctan function is the inverse of the tangent function. Therefore, we're looking for an angle whose tangent is 1. From the unit circle, we know that \(\tan(\pi/4) = 1\). Therefore, \(\arctan 1 = \pi/4\).
02

Calculate \(\arccos (-1)\)

The arccos function is the inverse of the cosine function. Therefore, we're looking for an angle whose cosine is -1. From the unit circle, we know that \(\cos(\pi) = -1\). Therefore, \(\arccos -1 = \pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

arctan
The term 'arctan' refers to the inverse of the tangent function in trigonometry. When you see \(\arctan x\), it represents the angle whose tangent is \('x'\). For instance, when asked to find \(\arctan 1\), you need to determine the angle at which the tangent is equal to 1.

To solve problems involving arctan, it is essential to understand the function of tangent. The tangent of an angle in the unit circle is defined as the ratio of the length of the opposite side to the adjacent side in a right triangle (opposite/adjacent).

One of the well-known angles in the unit circle is \(\pi/4\) (or 45 degrees), where \(\tan(\pi/4) = 1\). This means that the tangent of \(\pi/4\) is 1, so \(\arctan 1 = \pi/4\).

It's important to note that like other inverse trigonometric functions, arctan helps us find the angle given the value of the trigonometric function, which can be very helpful in various mathematical calculations and real-world applications.
arccos
Arccos, or arccosine, is the inverse function of the cosine. It assists in finding the angle whose cosine value equals the input. When dealing with \(\arccos x\), you are essentially identifying which angle gives a cosine value of 'x'.

To comprehend arccos, a basic understanding of cosine is necessary. The cosine of an angle in the unit circle is the ratio of the adjacent side to the hypotenuse in a right-angled triangle (adjacent/hypotenuse).

For instance, if you need to find \(\arccos(-1)\), you search for an angle whose cosine equals \(-1\). On the unit circle, at an angle of \(\pi\) (or 180 degrees), the cosine value is \(-1\). Therefore, \(\arccos(-1) = \pi\).

Inverse trigonometric functions like arccos are incredibly beneficial when solving equations involving angles and precise values, making them indispensable in trigonometry.
unit circle
The unit circle is a vital concept in trigonometry, beloved for its simplicity and usefulness. A unit circle is a circle with a radius of precisely one unit centered at the origin of a coordinate plane. This makes calculating the trigonometric values of various angles straightforward.

In the unit circle:
  • The x-coordinates of points on the circle correspond to cosine values of angles.
  • The y-coordinates represent sine values.
  • Tangent can be seen as the ratio of sine over cosine (y/x).
Some noteworthy angles on the unit circle include \(\pi/4\) (or 45 degrees), \(\pi/2\) (or 90 degrees), and \(\pi\) (or 180 degrees), among others. These angles produce mathematically tidy values for sine, cosine, and tangent functions, making them convenient for solving trigonometric equations such as arctan and arccos.

By understanding the unit circle, you can more easily interpret angles and trigonometric functions, offering a visual and conceptual framework that clarifies and simplifies many complex mathematical problems.

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Most popular questions from this chapter

Write a study sheet that will help you remember how to evaluate the six trigonometric functions of any angle \(\theta\) in standard position. Include figures and diagrams as needed.

Sketch the graph of \(y=\cos b x\) for \(b=\frac{1}{2}, 2\) and \(3 .\) How does the value of \(b\) affect the graph? How many complete cycles of the graph of \(y\) occur between 0 and \(2 \pi\) for each value of \(b ?\)

(a) Use a graphing utility to complete the table. $$\begin{array}{|l|l|l|l|l|l|l|} \hline \theta & 0 & 0.3 & 0.6 & 0.9 & 1.2 & 1.5 \\ \hline \cos \left(\frac{3 \pi}{2}-\theta\right) & & & & & & \\ \hline-\sin \theta & & & & & & \\ \hline \end{array}$$ (b) Make a conjecture about the relationship between \(\cos \left(\frac{3 \pi}{2}-\theta\right)\) and \(-\sin \theta\).

(a) Use a graphing utility to complete the table. Round your results to four decimal places. $$\begin{array}{|l|l|l|l|l|l|}\hline \theta & 0^{\circ} & 20^{\circ} & 40^{\circ} & 60^{\circ} & 80^{\circ} \\\\\hline \sin \theta & & & & & \\\\\hline \cos \theta & & & & & \\\\\hline \tan \theta & & & & & \\\\\hline\end{array}$$ (b) Classify each of the three trigonometric functions as increasing or decreasing for the table values. (c) From the values in the table, verify that the tangent function is the quotient of the sine and cosine functions.

Use a graphing utility to create a table of values to compare tan \(t\) with \(\tan (t+2 \pi), \tan (t+\pi)\) and \(\tan (t+\pi / 2)\) for \(t=0,0.3,0.6,0.9,1.2,\) and 1.5 Use your results to make a conjecture about the period of the tangent function. Explain your reasoning.

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