/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 You are skiing down a mountain w... [FREE SOLUTION] | 91Ó°ÊÓ

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You are skiing down a mountain with a vertical height of 1500 feet. The distance from the top of the mountain to the base is 3000 feet. What is the angle of elevation from the base to the top of the mountain?

Short Answer

Expert verified
The angle of elevation from the base to the top of the mountain is calculated using the atan function and then converted to degrees. The final result will be the angle \(\phi\).

Step by step solution

01

Identifying Known and Unknown

Firstly, let's identify what values we know and what we need to find. The problem provides us the vertical height of the mountain (opposite side in the triangle) as 1500 feet and the distance from top to base (adjacent side in the triangle) as 3000 feet. The angle of elevation is to be determined.
02

Applying the Tangent (tan) Function

The tangent function is defined as opposite side over adjacent side in a right triangle. In this context, it means the ratio of the mountain's height to the distance from the top to the base. We calculate the tangent of the angle \(\theta\) as follows: \(\tan(\theta) = \frac{1500}{3000}\)
03

Calculate the Angle of Elevation

To find the angle of elevation, we calculate the inverse tangent (arctan or \(\tan^{-1}\)) of the result from step 2. In this case we have \(\theta = \tan^{-1}(\frac{1500}{3000})\)
04

Convert the Angle to Degrees

The inverse tangent will give the angle in radians. To convert it to degrees, we multiply by \(\frac{180}{\pi}\). Let's denote the angle in degrees as \(\phi\), then we have: \(\phi = \theta * \frac{180}{\pi}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle of Elevation
Think of the angle of elevation as the glance upward you need to do if you're looking at an object higher than where you are standing. It's the angle formed between the horizontal line where you are standing to your line of sight towards the object. In simpler terms, when you stand at the base of the mountain and look up at the top, that's the angle of elevation.

This angle helps determine how high or distant a point is above ground level. It is widely used in various fields such as architecture, navigation, and even sports. Understanding this angle can help provide vital information, such as the steepness of a mountain or the height of a building. Here, the angle of elevation allows us to understand the incline of the mountain relative to its base.

In our problem, you are given the vertical height and the distance from the top to the base, which you need to use to calculate the angle of elevation. This angle is crucial if planning a ski route and ensuring safety while skiing down.
Tangent Function
The tangent function is a primary trigonometric function used to relate angles to the sides of a right triangle. It is denoted as \( an\), and in the context of a right triangle, is defined as the ratio of the length of the opposite side to the adjacent side. Mathematically, it is represented as:
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]
For the task given, the tangent function helps us relate the vertical height of the mountain to the distance between the top and base. It allows for the calculation of how steep the mountain is, through the angle formed. With a height of 1500 feet (opposite side) and a base of 3000 feet (adjacent side), \( an(\theta)\) is calculated by division.

The simplicity and power of the tangent function lie in its ability to translate a physical incline into an angle, which is highly important for engineers and navigators.
Right Triangle
A right triangle, as its name suggests, is a triangle in which one of the angles is a right angle (90 degrees). In our scenario, the mountain forms part of a right triangle, with the base, height, and hypotenuse (the distance from the base to top) forming the three sides.

In practical applications, right triangles are crucial because they simplify complex geographical and architectural challenges into manageable mathematics. The properties of right triangles, such as the Pythagorean theorem, help calculate distances and angles that would otherwise be difficult to determine.

Understanding the basic properties of right triangles can aid tremendously in solving height and distance problems efficiently. They are fundamental in trigonometry and are used to derive trigonometric functions like sine, cosine, and tangent as applied in calculating the angle of elevation.
Inverse Trigonometric Functions
Inverse trigonometric functions take ratios of sides of right triangles and give back angles. They are the building blocks for finding unknown angles in trigonometry. Inverse tangent, represented as \( an^{-1}\) or arctan, is particularly useful when you know the sides of a triangle but need to find the angle.

In our ski mountain problem, we have already found the tangent of the angle \(\theta\). To find the angle of elevation itself, we must use the inverse tangent of that ratio. Mathematically, this is expressed as:
\[ \theta = \tan^{-1}\left( \frac{\text{opposite}}{\text{adjacent}} \right) \]
Using the inverse tangent function translates a ratio back into an angle, making it incredibly useful in real-world applications like navigation, where understanding the angle is crucial for direction and safety.

After you obtain the angle in radians from the inverse tangent function, converting it to degrees often provides a more intuitive grasp of its measure, especially when communicating about angles in everyday life.

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Most popular questions from this chapter

Using calculus, it can be shown that the sine and cosine functions can be approximated by the polynomials $$\sin x \approx x-\frac{x^{3}}{3 !}+\frac{x^{5}}{5 !} \quad \text { and } \quad \cos x \approx 1-\frac{x^{2}}{2 !}+\frac{x^{4}}{4 !}$$ where \(x\) is in radians. (a) Use a graphing utility to graph the sine function and its polynomial approximation in the same viewing window. How do the graphs compare? (b) Use the graphing utility to graph the cosine function and its polynomial approximation in the same viewing window. How do the graphs compare? (c) Study the patterns in the polynomial approximations of the sine and cosine functions and predict the next term in each. Then repeat parts (a) and (b). How did the accuracy of the approximations change when an additional term was added?

Find the exact value of each function for the given angle for \(f(\theta)=\sin \theta\) and \(g(\theta)=\cos \theta .\) Do not use a calculator. (a) \((f+g)(\theta)\) (b) \((g-f)(\theta)\) (c) \([g(\theta)]^{2}\) (d) \((f g)(\theta)\) (e) \(f(2 \theta)\) (f) \(g(-\boldsymbol{\theta})\) $$\theta=315^{\circ}$$

The table shows the average daily high temperatures (in degrees Fahrenheit) for Quillayute, Washington, \(Q\) and Chicago, Illinois, \(C\) for month \(t,\) with \(t=1\) corresponding to January. $$\begin{array}{c|c|c} \text { Month, } & \text { Quillayute, } & \text { Chicago, } \\ t & Q & C \\ \hline 1 & 47.1 & 31.0 \\ 2 & 49.1 & 35.3 \\ 3 & 51.4 & 46.6 \\ 4 & 54.8 & 59.0 \\ 5 & 59.5 & 70.0 \\ 6 & 63.1 & 79.7 \\ 7 & 67.4 & 84.1 \\ 8 & 68.6 & 81.9 \\ 9 & 66.2 & 74.8 \\ 10 & 58.2 & 62.3 \\ 11 & 50.3 & 48.2 \\ 12 & 46.0 & 34.8 \end{array}$$ (a) \(\mathrm{A}\) model for the temperature in Quillayute is given by $$Q(t)=57.5+10.6 \sin (0.566 x-2.568)$$ Find a trigonometric model for Chicago. (b) Use a graphing utility to graph the data and the model for the temperatures in Quillayute in the same viewing window. How well does the model fit the data? (c) Use the graphing utility to graph the data and the model for the temperatures in Chicago in the same viewing window. How well does the model fit the data? (d) Use the models to estimate the average daily high temperature in each city. Which term of the models did you use? Explain. (e) What is the period of each model? Are the periods what you expected? Explain. (f) Which city has the greater variability in temperature throughout the year? Which factor of the models determines this variability? Explain.

True or False Determine whether the statement is true or false. Justify your answer. The tangent function can be used to model harmonic motion.

Use a graphing utility to graph the logarithmic function. Find the domain, vertical asymptote, and \(x\) -intercept of the logarithmic function. $$f(x)=\log _{3}(x-4)$$

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