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Find the exact value of each expression, if possible, without using a calculator. (a) \(\arcsin (-1)\) (b) arccos 1

Short Answer

Expert verified
\(\arcsin(-1) = - \pi /2\), \(\arccos(1) = 0\)

Step by step solution

01

Calculate \(\arcsin(-1)\)

Sine function achieves its minimum value of -1 at \(- \pi /2\), so \(\arcsin(-1) = - \pi /2\).
02

Calculate \(\arccos(1)\)

Cosine function achieves its maximum value of 1 at \(0\), so \(\arccos(1) = 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Trigonometric Functions
Inverse trigonometric functions play an essential role in connecting angles to ratios of sides in right-angled triangles. Whenever you have a ratio from a trigonometric function and you need to find out what angle created it, inverse trigonometric functions come into play. They are essentially the "reverse" operations of the usual sine, cosine, and tangent functions.
It's like trying to find out the mystery angle that produces a specific sine, cosine, or tangent value.
These functions include arcsine, arccosine, and arctangent, which are denoted by \( \arcsin \), \( \arccos \), and \( \arctan \). For these inverse functions,
  • The input is usually a value between -1 and 1, because that's the range of sine and cosine functions.
  • The output is an angle, often measured in radians.
This capability allows us to determine angles, even when you cannot use a calculator, by relying on known function values and properties.
Arcsine
Arcsine, denoted as \( \arcsin \), is the inverse of the sine function. Its task is to return the angle whose sine is a given number, within specific limits. The arcsine function is limited to the range \(-\pi/2 \) to \(\pi/2 \), making sure it returns a single unique result for every valid input.

This limitation works because within \(-\pi/2\) to \(\pi/2\), the sine function covers all possible values from -1 to 1 which are the limits for a sine wave.
For example, \( \arcsin(-1) \) returns \(-\pi/2 \). This is because at \(-\pi/2 \), the sine of the angle is -1.
  • The primary domain range for \(\text{arcsin}()\) is \(-1 \leq x \leq 1\).
  • The range as angles is \(-\pi/2 \leq y \leq \pi/2\).
Understanding arcsine means knowing these limits and being able to visualize how the function behaves for the different values of sine.
Arccosine
Arccosine, written as \( \arccos \), deals with finding the angle whose cosine is a specified number. This function limits its output to the range \(0\) to \(\pi\), which ensures that each value of cosine produces exactly one angle result.

Just as arcsine, the restriction on the range of the values is necessary to produce meaningful single angle outputs.
For example, in the exercise given, \( \arccos(1)\) returns \(0 \). That's because at \(0\) degrees or radians, the cosine value is exactly 1.
  • For \(\text{arccos}()\), the input must be between \(-1\) and \(1\).
  • The resulting angle is from \(0\) to \(\pi\).
This controlled range for angles means it becomes easy to identify the exact angle once you know your cosine value.
Exact Values
Finding exact values in trigonometry means identifying specific angles whose trigonometric values (like sine, cosine, and tangent) are well-known, typically without needing a calculator. These angles often include \(0\), \(\pi/2\), \(\pi\), and \(-\pi/2\), or in degrees, \(0\), \(90\), \(180\), and \(-90\).

These are critical because they help find solutions to trigonometric equations quickly and with precision.
Any angle resulting in a neat, rational multiple or integral form is considered an exact value.
  • Angles like \(0\), \(\pi\), and their equivalents are frequently encountered.
  • Knowing the exact sine and cosine values at those angles helps solve many trigonometric problems quickly.
Ultimately, understanding these exact values allows for effective and reliable decision­-making when involved with trigonometric calculations.

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Most popular questions from this chapter

Irrigation Engineering The cross sections of an irrigation canal are isosceles trapezoids, where the lengths of three of the sides are 8 feet (see figure). The objective is to find the angle \(\theta\) that maximizes the area of the cross sections. [Hint: The area of a trapezoid is given by \(\left.(h / 2)\left(b_{1}+b_{2}\right) .\right]\) (a) Complete seven rows of the table. $$\begin{array}{|c|c|c|c|} \hline \text {Base } I & \text {Base 2} & \text {Altitude} & \text {Area} \\ \hline 8 & 8+16 \cos 10^{\circ} & 8 \sin 10^{\circ} & 22.06 \\ \hline 8 & 8+16 \cos 20^{\circ} & 8 \sin 20^{\circ} & 42.46 \\ \hline \end{array}$$ (b) Use the table feature of a graphing utility to generate additional rows of the table. Use the table to estimate the maximum cross-sectional area. (c) Write the area \(A\) as a function of \(\theta.\) (d) Use the graphing utility to graph the function. Use the graph to estimate the maximum cross-sectional area. How does your estimate compare with that in part (b)?

Use a graphing utility to graph the logarithmic function. Find the domain, vertical asymptote, and \(x\) -intercept of the logarithmic function. $$f(x)=\log _{3}(x-4)$$

Determine whether the statement is true or false. Justify your answer. $$\cos \theta=-\sqrt{1-\sin ^{2} \theta} \text { for } 90^{\circ} < \theta < 180^{\circ}$$

Define the inverse secant function by restricting the domain of the secant function to the intervals \([0, \pi / 2)\) and \((\pi / 2, \pi],\) and sketch the graph of the inverse function.

Prove the identity \(\arctan (-x)=-\arctan x\)

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