/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Find the exact value of each exp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the exact value of each expression, if possible, without using a calculator. (a) \(\arcsin \frac{1}{2}\) (b) arcsin 0

Short Answer

Expert verified
(a) \(\arcsin(1/2) = \pi/6\), (b) \(\arcsin(0) = 0\).

Step by step solution

01

Understand the problem

The exercise asks to find the exact value of two arcsine expressions without a calculator. Why arcsine? Because arcsine of x is the angle whose sine is x. For instance, arcsin of 0.5 will yield an angle whose sine is 0.5.
02

Find arcsin(1/2)

What angle \(θ\) in the range of \([- \pi/2, \pi/2]\) has a sine of 1/2? This angle is \( \pi/6 \) or 30°, since \(\sin(\pi/6)=1/2\). So, \(\arcsin(1/2) = \pi/6\)
03

Find arcsin(0)

What angle \(θ\) in the range of \([- \pi/2, \pi/2]\) has a sine of 0? This angle is 0, because \(\sin(0)=0\). So, \(\arcsin(0)=0\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Identities
Understanding trigonometric identities can be incredibly helpful in solving problems requiring the calculation of exact trigonometric function values, like the arcsine problems presented in the exercise.

Trigonometric identities are equations involving trigonometric functions that are true for all values within their domains. Some of the most fundamental identities are the Pythagorean identities, which express the intrinsic relationship between the sine, cosine, and tangent functions. These identities, for example, tell us that for any angle \[ \theta \], the equation \(\sin^{2}\theta + \cos^{2}\theta = 1\) always holds true.

Role of Identities in Finding Arcsine Values

When seeking the arcsine of a number, we are essentially reversing the sine function. Understanding how sine values relate to angles through identities allows us to pinpoint the exact angle that corresponds to a given sine value. This concept is particularly important for solving the exercise, as it provides the basis for understanding why \( \arcsin \frac{1}{2} = \frac{\pi}{6} \) and \( \arcsin 0 = 0 \).
Inverse Trigonometric Functions
Inverse trigonometric functions are the reverse operations of trigonometric functions, and they are essential for solving angles when the value of the trigonometric function is known.

For example, the arcsine function — denoted as \(\arcsin\) or \(\sin^{-1}\) — gives us the angle whose sine is a specific number. It's crucial to remember that the output of \(\arcsin\) is an angle and it will always fall within a certain range. For \(\arcsin\), this range is \( [-\frac{\pi}{2}, \frac{\pi}{2}] \), meaning the output angle will be between -90° and 90° (or \( -\frac{\pi}{2} \) and \( \frac{\pi}{2} \) in radians).

Significance in Our Exercise

The value of \( \arcsin \frac{1}{2} \) derives from the common angle whose sine is 1/2, which is found using the range of the \(\arcsin\) function as a guideline. This is similar for the value of \(\arcsin 0\), where the angle with a sine of 0, within the specified range, is 0.
Exact Values of Trigonometric Functions
To find the exact values of trigonometric functions without a calculator, one must often rely on memorization of the unit circle or the use of special triangles, such as the 45-45-90 or the 30-60-90 triangle.

These methods provide exact values for the sine, cosine, and tangent functions at commonly encountered angles. For example, in a 30-60-90 triangle, we know the sides are in the ratio 1:2:\(\sqrt{3}\), and thus, the sine of 30° (or \(\frac{\pi}{6}\)) is exactly 1/2. These exact values are critical when solving problems like our exercise, as they allow for precise computation of trigonometric expressions without numerical approximation.

Application to Arcsine Problems

When the exercise prompts to find \(\arcsin \frac{1}{2}\), we utilize our knowledge of the exact value of the sine at 30° to understand that the corresponding angle is \(\frac{\pi}{6}\). The same is true for \(\arcsin 0\); as the sine of 0° is 0, we immediately know that the angle we are seeking is also 0°.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Define the inverse cotangent function by restricting the domain of the cotangent function to the interval \((0, \pi),\) and sketch the graph of the inverse function.

Because \(f(t)=\sin t\) is an odd function and \(g(t)=\cos t\) is an even function, what can be said about the function \(h(t)=f(t) g(t) ?\)

Find the exact value of each function for the given angle for \(f(\theta)=\sin \theta\) and \(g(\theta)=\cos \theta .\) Do not use a calculator. (a) \((f+g)(\theta)\) (b) \((g-f)(\theta)\) (c) \([g(\theta)]^{2}\) (d) \((f g)(\theta)\) (e) \(f(2 \theta)\) (f) \(g(-\boldsymbol{\theta})\) $$\theta=-270^{\circ}$$

Equation of a Line in Standard Write the standard form of the equation of the line that has the specified characteristics. Passes through (-2,6) and (3,2)

The table shows the average daily high temperatures (in degrees Fahrenheit) for Quillayute, Washington, \(Q\) and Chicago, Illinois, \(C\) for month \(t,\) with \(t=1\) corresponding to January. $$\begin{array}{c|c|c} \text { Month, } & \text { Quillayute, } & \text { Chicago, } \\ t & Q & C \\ \hline 1 & 47.1 & 31.0 \\ 2 & 49.1 & 35.3 \\ 3 & 51.4 & 46.6 \\ 4 & 54.8 & 59.0 \\ 5 & 59.5 & 70.0 \\ 6 & 63.1 & 79.7 \\ 7 & 67.4 & 84.1 \\ 8 & 68.6 & 81.9 \\ 9 & 66.2 & 74.8 \\ 10 & 58.2 & 62.3 \\ 11 & 50.3 & 48.2 \\ 12 & 46.0 & 34.8 \end{array}$$ (a) \(\mathrm{A}\) model for the temperature in Quillayute is given by $$Q(t)=57.5+10.6 \sin (0.566 x-2.568)$$ Find a trigonometric model for Chicago. (b) Use a graphing utility to graph the data and the model for the temperatures in Quillayute in the same viewing window. How well does the model fit the data? (c) Use the graphing utility to graph the data and the model for the temperatures in Chicago in the same viewing window. How well does the model fit the data? (d) Use the models to estimate the average daily high temperature in each city. Which term of the models did you use? Explain. (e) What is the period of each model? Are the periods what you expected? Explain. (f) Which city has the greater variability in temperature throughout the year? Which factor of the models determines this variability? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.