/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 154 Solve the equation. Round your a... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the equation. Round your answer to three decimal places, if necessary. $$2 x^{2}+x-4=0$$

Short Answer

Expert verified
The solutions to the equation are \(x = 0.782\) and \(x = -2.282\).

Step by step solution

01

Identify the coefficients

In the equation \(2x^2 + x - 4 = 0\), the coefficients are \(a = 2\), \(b = 1\), and \(c = -4\).
02

Apply the quadratic formula

Plug these values into the quadratic formula. So, \(x = [-1 ± sqrt((1)^2 - 4*2*(-4))] / 2*2\).
03

Calculate the square root part

The part under the square is \(1 - 4*2*(-4)=17\). Therefore, the equation becomes: \(x = [-1 ± sqrt(17)] / 4\)
04

Solve for x

Finally, this gives two possible solutions, \(x = [-1 + sqrt(17)] / 4 = 0.782\) and \(x = [-1 - sqrt(17)] / 4 = -2.282\). These are the roots of the quadratic equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
The quadratic formula is a key tool in solving quadratic equations. It provides an efficient method to find the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). The formula itself is written as:
  • \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
This formula helps calculate the solutions (or roots) by substituting the coefficients \(a\), \(b\), and \(c\) from the quadratic equation into the formula. Remember that \(\pm\) in the formula means there are always potentially two solutions. These solutions arise because of the plus and minus operation in the formula, representing possible positions of the roots in relation to the graph of the equation (a parabola).
Furthermore, the term under the square root, \(b^2 - 4ac\) is called the discriminant. It determines the nature of the roots:
  • If it's positive, there are two distinct real roots.
  • If it's zero, there's exactly one real root.
  • If it's negative, the roots are complex (not real numbers).
Roots of Equations
The roots of a quadratic equation are the values of \(x\) that make the equation true (i.e., zero). In terms of the graph of a quadratic equation, the roots represent the points where the parabola intersects the x-axis. These solutions can provide insights into the nature and direction of the parabola.
When we solve the equation \(2x^2 + x - 4 = 0\) using the quadratic formula, we found the roots to be approximately \(0.782\) and \(-2.282\). These roots tell us that the parabola crosses the x-axis at these points. It's important to note:
  • The roots are often referred to as "zeros" because they represent the x-values where the equation results in zero.
  • In some contexts, these solutions might be called solutions or x-intercepts, but they all guide us to the same understanding of the equation's graphical behavior.
Solving Quadratic Equations
Solving quadratic equations often requires a specific set of steps. Let's summarize these steps using our example equation, \(2x^2 + x - 4 = 0\):
  • First, identify the coefficients \(a\), \(b\), and \(c\). In our case, \(a=2\), \(b=1\), and \(c=-4\).
  • Next, substitute these values into the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
  • Simplify the expression under the square root (the discriminant), which for our equation is \(17\).
  • Use the resolved formula \(x = \frac{-1 \pm \sqrt{17}}{4}\) to find the precise solutions.
The solutions \(0.782\) and \(-2.282\) show where the equation equals zero. Quadratic equations present a structured way of understanding mathematical relationships that involve squares. With practice, using the quadratic formula becomes a quick and reliable method for problem-solving.

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Most popular questions from this chapter

The table shows the average daily high temperatures (in degrees Fahrenheit) for Quillayute, Washington, \(Q\) and Chicago, Illinois, \(C\) for month \(t,\) with \(t=1\) corresponding to January. $$\begin{array}{c|c|c} \text { Month, } & \text { Quillayute, } & \text { Chicago, } \\ t & Q & C \\ \hline 1 & 47.1 & 31.0 \\ 2 & 49.1 & 35.3 \\ 3 & 51.4 & 46.6 \\ 4 & 54.8 & 59.0 \\ 5 & 59.5 & 70.0 \\ 6 & 63.1 & 79.7 \\ 7 & 67.4 & 84.1 \\ 8 & 68.6 & 81.9 \\ 9 & 66.2 & 74.8 \\ 10 & 58.2 & 62.3 \\ 11 & 50.3 & 48.2 \\ 12 & 46.0 & 34.8 \end{array}$$ (a) \(\mathrm{A}\) model for the temperature in Quillayute is given by $$Q(t)=57.5+10.6 \sin (0.566 x-2.568)$$ Find a trigonometric model for Chicago. (b) Use a graphing utility to graph the data and the model for the temperatures in Quillayute in the same viewing window. How well does the model fit the data? (c) Use the graphing utility to graph the data and the model for the temperatures in Chicago in the same viewing window. How well does the model fit the data? (d) Use the models to estimate the average daily high temperature in each city. Which term of the models did you use? Explain. (e) What is the period of each model? Are the periods what you expected? Explain. (f) Which city has the greater variability in temperature throughout the year? Which factor of the models determines this variability? Explain.

Sketch the graph of \(y=\cos b x\) for \(b=\frac{1}{2}, 2\) and \(3 .\) How does the value of \(b\) affect the graph? How many complete cycles of the graph of \(y\) occur between 0 and \(2 \pi\) for each value of \(b ?\)

Aeronautics An airplane flying at an altitude of 6 miles is on a flight path that passes directly over an observer (see figure). Let \(\theta\) be the angle of elevation from the observer to the plane. Find the distance from the observer to the plane when (a) \(\theta=30^{\circ}\) (b) \(\theta=90^{\circ},\) and \((\mathrm{c}) \theta=120^{\circ}\).

Find the exact value of each function for the given angle for \(f(\theta)=\sin \theta\) and \(g(\theta)=\cos \theta .\) Do not use a calculator. (a) \((f+g)(\theta)\) (b) \((g-f)(\theta)\) (c) \([g(\theta)]^{2}\) (d) \((f g)(\theta)\) (e) \(f(2 \theta)\) (f) \(g(-\boldsymbol{\theta})\) $$\theta=-150^{\circ}$$

True or False Determine whether the statement is true or false. Justify your answer. An example of a bearing used in aviation is \(\mathrm{S} 25^{\circ} \mathrm{W}.\)

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