Chapter 4: Problem 63
Can the graph of a Gaussian model ever have an \(x\) -intercept? Explain.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 4: Problem 63
Can the graph of a Gaussian model ever have an \(x\) -intercept? Explain.
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
(a) use a graphing utility to graph the function, (b) find the domain, (c) use the graph to find the open intervals on which the function is increasing and decreasing, and (d) approximate any relative maximum or minimum values of the function. Round your results to three decimal places. $$f(x)=(\ln x)^{2}$$
Use the zero or root feature of a graphing utility to approximate the solution of the logarithmic equation. $$\ln x^{2}-e^{x}=-3-\ln x^{2}$$
Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. Approximate the point of intersection of the graphs of \(f\) and \(g .\) Then solve the equation \(f(x)=g(x)\) algebraically. $$\begin{aligned}&f(x)=3 \log _{5} x\\\&g(x)=6\end{aligned}$$
The number \(Y\) of yeast organisms in a culture is given by the model $$Y=\frac{663}{1+72 e^{-0.547 t}}$$ where \(t\) represents the time (in hours). (a) Use a graphing utility to graph the model. (b) Use the model to predict the populations for the 19th hour and the 30 th hour. (c) According to this model, what is the limiting value of the population? (d) Why do you think this population of yeast follows a logistic growth model instead of an exponential growth model?
You take a five-pound package of steaks out of a freezer at 11 A.M. and place it in a refrigerator. Will the steaks be thawed in time to be grilled at 6 P.M.? Assume that the refrigerator temperature is \(40^{\circ} \mathrm{F}\) and the freezer temperature is \(0^{\circ} \mathrm{F}\). Use the formula (derived from Newton's Law of Cooling) $$t=-5.05 \ln \frac{T-40}{0-40}$$ where \(t\) is the time in hours (with \(t=0\) corresponding to 11 A.M.) and \(T\) is the temperature of the package of steaks (in degrees Fahrenheit).
What do you think about this solution?
We value your feedback to improve our textbook solutions.