/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Simplify the expression. $$5-e... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify the expression. $$5-e^{\ln \left(x^{2}+1\right)}$$

Short Answer

Expert verified
The simplified form of the given expression \(5-e^{\ln \left(x^{2}+1\right)}\) is \(4 - x^{2}\).

Step by step solution

01

Start

Consider the expression \(5-e^{\ln \left(x^{2}+1\right)}\).
02

Apply the rule \(e^{ln(a)} = a\).

Here we can apply the rule that says: if you have \(e^{\ln(a)}\), that just equals to \(a\). Using this rule we can simplify: \(5-e^{\ln \left(x^{2}+1\right)} = 5 - (x^{2}+1)\).
03

Simplify

Simplifying the expression we have \(5 - x^{2} - 1 -> 4 - x^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential and Logarithmic Functions
Exponential and logarithmic functions are mathematical operations that are intricately related. These functions work as inverses of each other, meaning they can effectively 'undo' each other's operations. In simpler terms, if you apply an exponential function to a variable and then apply a logarithm to the result (or vice versa), you will end up back with the original variable.

When dealing with natural logarithms, denoted by \( \ln \), coupled with the base of natural logarithms \( e \), we often encounter the rule: \( e^{\ln(a)} = a \). This tells us when the exponential function has a logarithm in its exponent, they cancel out, simplifying to just \( a \).
  • Example: \( e^{\ln(x^{2}+1)} = x^{2} + 1 \)
  • This rule is essential in reducing complex-looking algebraic expressions to simpler forms.
Simplification Rules
Simplification rules in algebra help break down complex expressions into simpler, more manageable forms. These rules involve mathematical operations like addition, subtraction, multiplication, and division. Simplification rules are based on properties of numbers and their operations.

A core principle is to systematically replace complex components with simpler equivalents through standard algebraic transformations, such as:
  • Combining like terms: Grouping and simplifying terms that have the same variable or exponent.
  • Applying operation rules: For example, simplifying \( e^{\ln(a)} \) using the property \( e^{\ln(a)} = a \).
  • Following the order of operations: Ensuring calculations are done in the correct sequence (PEMDAS/BODMAS).
In the provided exercise, the expression \( 5-e^{\ln(x^{2}+1)} \) seems complex initially, but by applying the simplification rule of \(e^{\ln(a)} = a\), it reduces to \( x^{2} + 1 \). Afterward, the expression further simplifies to \( 4 - x^{2} \) as you combine like terms.
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and operation symbols. They are the backbone of algebra, allowing us to represent general quantities and relationships.

In an expression like \(5 - e^{\ln(x^{2}+1)}\), each component has a role. The constants (\(5\), the numerical parts) are stable elements, while the variable components (\(x^2\), \(e^{ln(...)}\)) introduce flexibility by allowing to represent a range of values.
  • Constants: These are fixed values that do not change.
  • Variables: Symbols representing numbers that can vary, e.g., \(x\).
  • Operations: Mathematical symbols that show relationships or operations between terms, e.g., addition \(+\), subtraction \(-\).
When simplifying algebraic expressions, our goal is to make them as straightforward as possible by utilizing known mathematical properties and identities. This often involves reducing complexity by combining like terms or using properties of numbers and operations.

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Most popular questions from this chapter

Solve the logarithmic equation algebraically. Round the result to three decimal places. Verify your answer(s) using a graphing utility. $$\log _{9}(4+x)=\log _{9} 2 x$$

The populations \(P\) (in thousands) of Luxembourg for the years 1999 through 2013 are shown in the table, where \(t\) represents the year, with \(t=9\) corresponding to 1999. (Source: European Commission Eurostat) $$\begin{array}{|c|c|}\hline \text { Year } & \text { Population, } P \\\\\hline 1999 & 427.4 \\\2000 & 433.6 \\\2001 & 439.0 \\\2002 & 444.1 \\\2003 & 448.3 \\\2004 & 455.0 \\\2005 & 461.2 \\\2006 & 469.1 \\\2007 & 476.2 \\\2008 & 483.8 \\\2009 & 493.5 \\\2010 & 502.1 \\\2011 & 511.8 \\\2012 & 524.9 \\\2013 & 537.0 \\\\\hline\end{array}$$ (a) Use the regression feature of a graphing utility to find a linear model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (b) Use the regression feature of the graphing utility to find a power model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (c) Use the regression feature of the graphing utility to find an exponential model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (d) Use the regression feature of the graphing utility to find a logarithmic model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (e) Which model is the best fit for the data? Explain. (f) Use each model to predict the populations of Luxembourg for the years 2014 through 2018. (g) Which model is the best choice for predicting the future population of Luxembourg? Explain. (h) Were your choices of models the same for parts (e) and \((g) ?\) If not, explain why your choices were different.

The table shows the annual sales \(S\) (in billions of dollars) of Starbucks for the years from 2009 through 2013. (Source: Starbucks Corp.) $$\begin{array}{|c|c|}\hline \text { Year } & \text { Sales, } S \\\\\hline 2009 & 9.77 \\\\\hline 2010 & 10.71 \\\\\hline 2011 & 11.70 \\\\\hline 2012 & 13.30 \\\\\hline 2013 & 14.89 \\\\\hline\end{array}$$ (a) Use the regression feature of a graphing utility to find an exponential model for the data. Let \(t\) represent the year, with \(t=9\) corresponding to 2009. (b) Rewrite the model from part (a) as a natural exponential model. (c) Use the natural exponential model to predict the annual sales of Starbucks in \(2018 .\) Is the value reasonable?

Use the zero or root feature of a graphing utility to approximate the solution of the logarithmic equation. $$\ln x^{2}-e^{x}=-3-\ln x^{2}$$

Let \(f(x)=\log _{a} x\) and \(g(x)=a^{x},\) where \(a>1.\) (a) Let \(a=1.2\) and use a graphing utility to graph the two functions in the same viewing window. What do you observe? Approximate any points of intersection of the two graphs. (b) Determine the value(s) of \(a\) for which the two graphs have one point of intersection. (c) Determine the value(s) of \(a\) for which the two graphs have two points of intersection.

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