/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Use the properties of logarithms... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the properties of logarithms to rewrite and simplify the logarithmic expression.$$\log _{9} 243$$.

Short Answer

Expert verified
2.5

Step by step solution

01

Express the number in the logarithm as a power of the base

We have to express the number 243 as a power of the base 9. After evaluating the powers of 9, we find that \(9^2 = 81\) and \(9^3 = 729, which are too small and too large. However, we can express 243 as \(243 = 3^5 \) and 9 can be written as \( 9 = 3^2 \). As such, we rewrite the original expression as \( log_{3^2} (3^5) \).
02

Apply the power rule of logarithms

The power rule of logarithms states that \( log_b (a^n) = n log_b (a) \). Therefore, we simplify the expression as \( 5 * log_{3^2} (3) \).
03

Simplify further using properties of logarithms

A number in a logarithm to the same base equals 1. So, \( log_{3^2} (3) = 1 \), as we are effectively asking what power we need to raise 9 to in order to get 3, the answer being 1/2. Therefore, the simplified expression becomes \( 5 * 1/2 = 2.5 \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Properties
The world of logarithms can initially seem complex, but by understanding their properties, we can make working with them much simpler. Logarithms are the inverse operations of exponentials, meaning they help us determine the power to which a number (the base) must be raised to obtain another number. One essential property is that for any number \( a \) and base \( b \), \( \log_b (b) = 1 \). This is because the base \( b \) raised to the power of 1 equals itself. Another crucial property is that if two logarithms with the same base are equal, their arguments are equal (i.e., \( \log_b (x) = \log_b (y) \Rightarrow x = y \)). By applying these properties, we can simplify and solve complex logarithmic equations more efficiently.
  • Change of Base Formula: Often helpful when calculating logs on a calculator that only allows specific bases.
  • Product and Quotient Rules: These rules assist in simplifying expressions by converting multiplication and division into addition and subtraction.
Power Rule of Logarithms
The power rule of logarithms is a fantastic tool for simplifying complex logarithmic expressions. It states that \( \log_b (a^n) = n \log_b (a) \). This rule allows us to take an exponent present on an argument and move it to the front of the log as a multiplier. This property can significantly simplify calculations, especially when dealing with higher powers. Simply put, if you see a logarithm with an exponent, you can take that exponent and multiply it by the logarithm of the base argument.

For example, consider \( \log_9 (243) \), where we rewrite 9 and 243 using the same base 3: \( \log_{3^2} (3^5) \). Applying the power rule here allows us to rewrite this as \( 5 \log_{3^2} (3) \), thus simplifying our calculations significantly. This process not only simplifies the expression but also helps in better understanding exponential relationships.
Simplifying Logarithmic Expressions
Simplifying logarithmic expressions involves using various properties and rules to rewrite a complex logarithm in its simplest form. As demonstrated in the example \( \log_9 (243) \), simplification often begins with expressing numbers using a common base. Here, we wrote 9 as \( 3^2 \) and 243 as \( 3^5 \). Once expressed in terms of a common base, the expression \( \log_{3^2} (3^5) \) can be simplified.

Following the power rule and other properties of logarithms, like \( \log_b (b) = 1 \) for any log base \( b \), we were able to deduce \( \log_{3^2} (3) = \frac{1}{2} \). This resulted in the final simplified expression of 2.5.
  • Always look for opportunities to rewrite expressions in terms of a given base.
  • Simplification can often turn a challenging problem into a manageable task.
Exponential Expressions
Understanding exponential expressions involves recognizing expressions that depict repeated multiplication of a base. For instance, \( 3^5 \) means multiplying 3 by itself 5 times. In logarithmic expressions, it is often helpful to rewrite numbers into their exponential form so they can be aligned with the base of the logarithm. When you face a problem like \( \log_9 (243) \), knowing that both can be expressed with the same base simplifies solving it.

By recognizing that \( 9 = 3^2 \) and \( 243 = 3^5 \), the problem becomes handling the equation under the same base, making the rest of the algebraic manipulation straightforward. Exponential expressions thus play a vital role in transitions between different forms of equations. By practicing expressing values exponentially, you can streamline the process of understanding and solving logarithms.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the time required for a \(\$ 1000\) investment to (a) double at interest rate \(r,\) compounded continuously, and (b) triple at interest rate \(r\), compounded continuously. Round your results to two $$r=2.5 \%$$

Solve the equation algebraically. Round the result to three decimal places. Verify your answer using a graphing utility. $$\frac{1+\ln x}{2}=0$$

Use the regression feature of a graphing utility to find a power model \(y=a x^{b}\) for the data and identify the coefficient of determination. Use the graphing utility to plot the data and graph the model in the same viewing window. $$(2,450),(4,385),(6,345),(8,332),(10,312)$$

The populations \(P\) (in thousands) of Luxembourg for the years 1999 through 2013 are shown in the table, where \(t\) represents the year, with \(t=9\) corresponding to 1999. (Source: European Commission Eurostat) $$\begin{array}{|c|c|}\hline \text { Year } & \text { Population, } P \\\\\hline 1999 & 427.4 \\\2000 & 433.6 \\\2001 & 439.0 \\\2002 & 444.1 \\\2003 & 448.3 \\\2004 & 455.0 \\\2005 & 461.2 \\\2006 & 469.1 \\\2007 & 476.2 \\\2008 & 483.8 \\\2009 & 493.5 \\\2010 & 502.1 \\\2011 & 511.8 \\\2012 & 524.9 \\\2013 & 537.0 \\\\\hline\end{array}$$ (a) Use the regression feature of a graphing utility to find a linear model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (b) Use the regression feature of the graphing utility to find a power model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (c) Use the regression feature of the graphing utility to find an exponential model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (d) Use the regression feature of the graphing utility to find a logarithmic model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (e) Which model is the best fit for the data? Explain. (f) Use each model to predict the populations of Luxembourg for the years 2014 through 2018. (g) Which model is the best choice for predicting the future population of Luxembourg? Explain. (h) Were your choices of models the same for parts (e) and \((g) ?\) If not, explain why your choices were different.

The table shows the numbers of single beds \(B\) (in thousands) on North American cruise ships from 2007 through 2012. (Source: Cruise Lines International Association) $$\begin{array}{|c|c|}\hline \text { Year } & \text { Beds, } B \\\\\hline 2007 & 260.0 \\\2008 & 270.7 \\\2009 & 284.8 \\\2010 & 307.7 \\\2011 & 321.2 \\\2012 & 333.7 \\\\\hline\end{array}$$ (a) Use the regression feature of a graphing utility to find a linear model, an exponential model, and a logarithmic model for the data and identify the coefficient of determination for each model. Let \(t\) represent the year, with \(t=7\) corresponding to 2007 (b) Which model is the best fit for the data? Explain. (c) Use the model you chose in part (b) to predict the number of beds in 2017 . Is the number reasonable?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.