/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 109 Students in a mathematics class ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Students in a mathematics class were given an exam and then tested monthly with an equivalent exam. The average scores for the class are given by the human memory model $$f(t)=80-17 \log _{10}(t+1), \quad 0 \leq t \leq 12$$ where \(t\) is the time in months. (a) What was the average score on the original exam \((t=0) ?\) (b) What was the average score after 2 months? (c) What was the average score after 11 months? Verify your answers in parts (a), (b), and (c) using a graphing utility.

Short Answer

Expert verified
The average score on the original exam is 80, after 2 months it can be found by calculating \(80-17 \log _{10}(3)\), and after 11 months it can be found by calculating \(80-17 \log _{10}(12)\). After getting these values, they can be verified using a graphing utility by comparing the points at \(t=0, t=2, t=11\) and checking that they match with their calculated values.

Step by step solution

01

Calculation of the average score on the original exam (t=0)

Substitute \(t=0\) in the human memory model function. So it will be: \(f(0)=80-17 \log _{10}(0+1)=80-17 \log _{10}(1)\). As the logarithm of 1 in any base is 0, the equation becomes \(f(0)=80-17*0=80\). Hence, the average score on the original exam (t=0) is 80.
02

Calculation of the average score after 2 months

Substitute \(t=2\) into the human memory model. So it will turn into: \(f(2)=80-17 \log _{10}(2+1)=80-17 \log _{10}(3)\). Calculate the value of the log base 10 of 3 and multiply it by 17, then subtract this from 80. This will give you the average score after 2 months.
03

Calculation of the average score after 11 months

Substitute \(t=11\) into the human memory model function. It will turn into \(f(11)=80-17 \log _{10}(11+1)=80-17 \log _{10}(12)\). Calculate the log base 10 of 12 and multiply it by 17, this value will be subtracted from 80 which will be the average score after 11 months.
04

Verification using a graphing utility

Plot the human memory model function against time \(t\) on the x-axis and \(f(t)\) on the y-axis using any graphing utility. Make sure to extend \(t\) from 0 to 12 and mark the points where \(t=0, t=2, t=11\) on the graph. Carefully observe these points and their corresponding function values. The values from the graph at these points should match with the calculated values to verify your answers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm in Base 10
Logarithms are mathematical tools that help us understand exponential relationships. The logarithm in base 10, often written as \( \log_{10}\), tells us what power of 10 gives us a particular number. For example, \( \log_{10}(100) = 2 \) because 10 raised to the power of 2 is 100. In simpler terms, it's about finding out how many times we need to multiply 10 to get our targeted number.

In the context of the Human Memory Model, the logarithm helps illustrate how memory scores change over time. When you see expressions like \( \log_{10}(t+1) \), it means we're looking at how scores change as time progresses, by considering the logarithmic decline. Knowing that the logarithm of 1 is always 0 (since 10 to the power of 0 is 1), you can understand why the initial score at \( t = 0 \) is not influenced by the logarithmic term.
Mathematics Class Exam Analysis
Analyzing exam scores over time gives insights into how information retention decreases. In this particular exercise, we have a model depicting the average score temporal changes for a class through a function, \( f(t) = 80 - 17 \log_{10}(t+1) \). This function considers the decline in scores as students are re-evaluated monthly.
  • At \( t = 0 \), the function starts with the initial value of 80, indicating the average score when the exam was first taken.

  • As \( t \) increases, the logarithmic component \( 17 \log_{10}(t+1) \) begins to subtract from this 80, illustrating a score decline.
Such an analysis supports teachers in understanding long-term memory retention in students. Additionally, it can aid in forming strategies for better long-term retention in learning material. Students tend to perform better if revision becomes a consistent habit, countering the score drop due to time.
Graphing Utility Usage
Graphing utilities are powerful tools that enable us to visualize mathematical functions. When analyzing a mathematical representation like the human memory model, a graphing utility helps to see how scores fluctuate over time.

In this scenario:
  • The x-axis represents time, \( t \), spanning from 0 to 12 months.

  • The y-axis depicts the average score, \( f(t) \), computed from the human memory model function.
When using a graphing utility, you plot the function, and it smoothly shows how time affects scores. By marking key points, such as \( t=0 \), \( t=2 \), and \( t=11 \), you can visually verify the calculations done before plotting. The graph should reflect a gradual decline in scores, as compounding over a year results in memory fading, offering a clear perspective on learning dynamics.
Calculation of Average Scores
Calculating average scores from a model like \( f(t) = 80 - 17 \log_{10}(t+1) \) helps understand how memory retention erodes over time.
Here's how to compute it:
  • Start with \( t=0 \): Set \( t \) to zero, simplifying to \( f(0) = 80 \). This indicates a perfect recall immediately after learning.

  • Next, at \( t=2 \): Substitute 2 into the formula: \( f(2) = 80 - 17 \log_{10}(3) \). Calculate \( \log_{10}(3) \) and subtract to find a value slightly lower than 80, representing decline.

  • Finally, for \( t=11 \): Plug in \( t=11 \): \( f(11) = 80 - 17 \log_{10}(12) \). This results in a more significant decrease, illustrating further memory degradation.
These calculations highlight how exam scores provide a measure of retention over time, helping educators and students evaluate learning effectiveness.

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Most popular questions from this chapter

(a) complete the table to find an interval containing the solution of the equation, (b) use a graphing utility to graph both sides of the equation to estimate the solution, and (c) solve the equation algebraically. Round your results to three decimal places. $$\ln 2 x=2.4$$ $$\begin{array}{|l|l|l|l|l|l|}\hline x & 2 & 3 & 4 & 5 & 6 \\\\\hline \ln 2 x & & & & & \\\\\hline\end{array}$$

Solve the equation algebraically. Round the result to three decimal places. Verify your answer using a graphing utility. $$\frac{1-\ln x}{x^{2}}=0$$

Use a graphing utility to create a scatter plot of the data. Decide whether the data could best be modeled by a linear model, an exponential model, or a logarithmic model. $$(1,4.4),(1.5,4.7),(2,5.5),(4,9.9),(6,18.1),(8,33.0)$$

In your own words, explain how to fit a model to a set of data using a graphing utility.

The populations \(P\) (in thousands) of Luxembourg for the years 1999 through 2013 are shown in the table, where \(t\) represents the year, with \(t=9\) corresponding to 1999. (Source: European Commission Eurostat) $$\begin{array}{|c|c|}\hline \text { Year } & \text { Population, } P \\\\\hline 1999 & 427.4 \\\2000 & 433.6 \\\2001 & 439.0 \\\2002 & 444.1 \\\2003 & 448.3 \\\2004 & 455.0 \\\2005 & 461.2 \\\2006 & 469.1 \\\2007 & 476.2 \\\2008 & 483.8 \\\2009 & 493.5 \\\2010 & 502.1 \\\2011 & 511.8 \\\2012 & 524.9 \\\2013 & 537.0 \\\\\hline\end{array}$$ (a) Use the regression feature of a graphing utility to find a linear model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (b) Use the regression feature of the graphing utility to find a power model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (c) Use the regression feature of the graphing utility to find an exponential model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (d) Use the regression feature of the graphing utility to find a logarithmic model for the data and to identify the coefficient of determination. Plot the model and the data in the same viewing window. (e) Which model is the best fit for the data? Explain. (f) Use each model to predict the populations of Luxembourg for the years 2014 through 2018. (g) Which model is the best choice for predicting the future population of Luxembourg? Explain. (h) Were your choices of models the same for parts (e) and \((g) ?\) If not, explain why your choices were different.

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