/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 99 Simplify the expression. $$\le... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify the expression. $$\left(\frac{x}{8}\right)^{-3}$$

Short Answer

Expert verified
The simplified form of \( \left( \frac{x}{8} \right) ^{-3} \) is: \( \frac{512}{x^3} \).

Step by step solution

01

Understand Exponent of -1

When any number or term is raised to the power -1, it means the reciprocal of that number. \(\left( \frac{x}{8} \right) ^{-1} = \frac{8}{x} \).
02

Understand Power Law

\((a^n)^m = a^{n \cdot m}\) which indicates that when we are raising a power to another power, we multiply the exponents which also applies to negative exponents. To simplify \(\left (\frac{x}{8} \right )^{-3} \) we will take the cube of \(\frac{8}{x} \) which means \(\left( \frac{8}{x} \right) ^3\).
03

Simplify

Let's compute \(\left( \frac{8}{x} \right) ^3\). It is the same as multiplying the numerator and the denominator by themselves three times. This leads to \( \frac{8^3}{x^3} = \frac{512}{x^3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Reciprocals
When we talk about reciprocals, we're discussing numbers that, when multiplied together, yield the number 1. Essentially, the reciprocal of a fraction is achieved by flipping the numerator and the denominator.
  • For instance, the reciprocal of \( \frac{a}{b} \) is \( \frac{b}{a} \).
  • Similarly, the reciprocal of a whole number \( c \) is \( \frac{1}{c} \).
Reciprocals become particularly useful when handling expressions with negative exponents.
When you see a negative exponent, like \(-1\), it's a signal to find the reciprocal of that base. For example, \( \left( \frac{x}{8} \right)^{-1} \) results in \( \frac{8}{x} \), because you're flipping \( \frac{x}{8} \).
This simple switch makes it easier to deal with various calculations, especially when simplifying expressions or fractions with exponents.
Exploring the Power Law Concept
The power law in mathematics lets us figure out the result when raising a power to another power. This rule is crucial because it simplifies expressions with exponents.
  • The general form can be described as \((a^n)^m = a^{n\cdot m}\).
This formula advises us to multiply the exponents together.
For example, if we have \((a^2)^3\), we compute it as \(a^{2\cdot 3} = a^6\). The same principle can apply to negative exponents.
In our exercise \(\left( \frac{x}{8} \right)^{-3}\), we treat the expression as a power to another power. Using the power law helps us convert it to \(\left( \frac{8}{x} \right)^3\).
This simplifies because we already know \(\left( \frac{x}{8} \right)^{-1}\) leads to \(\frac{8}{x}\), and raising that to the third power is straightforward.
Simplifying Expressions with Exponents
Simplifying expressions with exponents can initially seem challenging, yet it's manageable with the right approach. The goal is to reduce the expression to its simplest form by applying rules for exponents and reciprocals.
  • Take each factor and simplify it using known rules, such as reciprocals and the power law.
  • Always break down complex expressions gradually, ensuring clarity at each step.
In the original exercise, simplifying \( \left( \frac{8}{x} \right)^3 \) means multiplying both the numerator and the denominator by themselves three times.
This turns into \( \frac{8 \times 8 \times 8}{x \times x \times x} \), giving us \( \frac{8^3}{x^3} \).
Hence, by computing \(8^3 = 512\), we find our expression simplifies to \( \frac{512}{x^3} \).
Remember to perform multiplication step by step, ensuring accurate results while reinforcing your understanding of exponent rules.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The endpoints of the interval over which distinct vision is possible are called the near point and far point of the eye (see figure). With increasing age, these points normally change. The table shows the approximate near points \(y\) (in inches) for various ages \(x\) (in years). $$\begin{array}{|c|c|} \hline \text { Age, \(x\) } & \text { Near point, \(y\) } \\ \hline 16 & 3.0 \\ 32 & 4.7 \\ 44 & 9.8 \\ 50 & 19.7 \\ 60 & 39.7 \\ \hline \end{array}$$ (a) Find a rational model for the data. Take the reciprocals of the near points to generate the points \(\left(x, \frac{1}{y}\right).\) Use the regression feature of a graphing utility to find a linear model for the data. The resulting line has the form \(\frac{1}{y}=a x+b.\) Solve for \(y.\) (b) Use the table feature of the graphing utility to create a table showing the predicted near point based on the model for each of the ages in the original table. (c) Do you think the model can be used to predict the near point for a person who is 70 years old? Explain.

(a) use Descartes's Rule of Signs to determine the possible numbers of positive and negative real zeros of \(f\) (b) list the possible rational zeros of \(f,\) (c) use a graphing utility to graph \(f\) so that some of the possible zeros in parts (a) and (b) can be disregarded, and (d) determine all the real zeros of \(f\). $$f(x)=-2 x^{4}+13 x^{3}-21 x^{2}+2 x+8$$

Divide using long division. $$\left(x^{2}+5 x+6\right) \div(x-4)$$

Find all real zeros of the polynomial function. $$f(x)=4 x^{3}+7 x^{2}-11 x-18$$

Assume that the function \(f(x)=a x^{2}+b x+c\) \(a \neq 0,\) has two real xeros. Show that the \(x\) -coordinate of the vertex of the graph is the average of the zeros of \(f\) (Hint: Use the Quadratic Formula.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.