/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 Find a polynomial function that ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find a polynomial function that has the given zeros. (There are many correct answers.) \(2,2+\sqrt{5}, 2-\sqrt{5}\)

Short Answer

Expert verified
The polynomial function that has the given zeros is \(x^3 - 6x^2 + 14x - 14\).

Step by step solution

01

Convert roots into factors

Since \(2, 2 + \sqrt{5}, 2 - \sqrt{5}\) are roots, it means that \(x - 2, x - (2 + \sqrt{5}), x - (2 - \sqrt{5})\) are factors of the polynomial.
02

Simplify the factors

Simplify the second and third factor to \(x - 2,\; x - 2 - \sqrt{5},\; x - 2 + \sqrt{5}\).\nThis can also be represented as \(x - 2, x - 2 - \sqrt{5} , x - 2 + \sqrt{5}\).
03

Multiply the factors together

Now, multiply these factors to get the polynomial. When you do the calculations, the polynomial will be \( (x - 2) \cdot (x - 2 - \sqrt{5}) \cdot (x - 2 + \sqrt{5}) \), which simplifies to \(x^3 - 6x^2 + 14x - 14\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finding Roots of Polynomials
To understand how to find the roots of polynomials, we first need to grasp what a polynomial is. A polynomial is an algebraic expression that involves a sum of powers in a variable, where each power has a coefficient. The roots of a polynomial are the values of the variable that make the polynomial equal to zero. For a polynomial equation like \(f(x) = 0\), the roots are the solutions, or the values of \(x\), that satisfy this equation.
Identifying the roots is vital because they represent the x-intercepts on the graph of the polynomial. If you have a polynomial and you know some of its roots, you can factor the polynomial into linear factors. This is a reverse approach from how we handle factoring in algebra.
  • Each root \(r\) of a polynomial \(f(x)\) translates into a factor \((x - r)\).
  • For example, if 2 is a root of the polynomial, then \(x-2\) is a factor.
  • Find all factors by converting every root to its linear expression.
In our specific exercise, we have roots \(2, 2 + \sqrt{5}, 2 - \sqrt{5}\). Thus, corresponding factors are \((x - 2), (x - (2 + \sqrt{5})), (x - (2 - \sqrt{5}))\). These factors are crucial for multiplying them back into a full polynomial as shown in the following sections.
Multiplying Polynomials
Multiplying polynomials can be simplified by remembering the distributive property, which states that each term in the first polynomial must be multiplied by each term in the second polynomial. This results in combining like terms in the process to simplify the expression.
In the given exercise, we have three factors derived from the roots: \( (x - 2), (x - (2 + \sqrt{5})), \) and \( (x - (2 - \sqrt{5})) \). Notice how the last two factors can be rewritten using the difference of squares identity \((a-b)(a+b) = a^2 - b^2\).
  • First, multiply \((x - (2 + \sqrt{5}))\) and \((x - (2 - \sqrt{5}))\) using the special product formula to get \( [(x-2)^2 - (\sqrt{5})^2] \).
  • This simplifies to \( (x-2)^2 - 5 \).
  • Next, expand: \((x-2)(x^2 - 4x - 1)\).
By using these strategies, you can develop the product into a simplified polynomial such as \( x^3 - 6x^2 + 14x - 14 \), which represents the polynomial function with the given roots.
Simplifying Algebraic Expressions
Simplifying algebraic expressions is an essential skill in algebra. It involves reducing expressions to their simplest form, making them easier to read and work with. This often requires combining like terms and using algebraic identities.
In the context of the problem provided, after multiplying the factors of the polynomial, you might have intermediate terms that require simplification. Similar terms are combined, and equations are rewritten in a more manageable way.
  • Combine like terms: Terms with the same variable and exponent are added or subtracted. For example, \(x^2\) terms are combined with other \(x^2\) terms.
  • Use algebraic identities: The identity \((a+b)^2 = a^2 + 2ab + b^2\) is one of the vital tools used in simplification.
  • Simplification leads to polynomials like \(x^3 - 6x^2 + 14x - 14\), where all terms are combined to achieve a clear and concise expression.
With practice, identifying and applying these rules becomes second nature, facilitating a smoother algebra-solving experience.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A graph of \(y=f(x)\) is shown, where \(f(x)=2 x^{5}-3 x^{4}+x^{3}-8 x^{2}+5 x+3\) and \(f(-x)=-2 x^{5}-3 x^{4}-x^{3}-8 x^{2}-5 x+3\). (a) How many negative real zeros does \(f\) have? Explain. (b) How many positive real zeros are possible for \(f ?\) Explain. What does this tell you about the eventual right-hand behavior of the graph? (c) Is \(x=-\frac{1}{3}\) a possible rational zero of \(f ?\) Explain. (d) Explain how to check whether \(\left(x-\frac{3}{2}\right)\) is a factor of \(f\) and whether \(x=\frac{3}{2}\) is an upper bound for the real zeros of \(f\).

The game commission introduces 100 deer into newly acquired state game lands. The population \(N\) of the herd is given by $$N=\frac{20(5+3 t)}{1+0.04 t}, \quad t \geq 0$$ where \(t\) is the time in years. (a) Use a graphing utility to graph the model. (b) Find the populations when \(t=5, t=10,\) and \(t=25.\) (c) What is the limiting size of the herd as time increases? Explain.

Use any convenient method to solve the quadratic equation. $$25 x^{2}-1=0$$

The number of parts per million of nitric oxide emissions \(y\) from a car engine is approximated by \(y=-5.05 x^{3}+3857 x-38,411.25\) \(13 \leq x \leq 18,\) where \(x\) is the air-fuel ratio. (a) Use a graphing utility to graph the model. (b) There are two air-fuel ratios that produce 2400 parts per million of nitric oxide. One is \(x=15\) Use the graph to approximate the other. (c) Find the second air-fuel ratio from part (b) algebraically. (Hint: Use the known value of \(x=15\) and synthetic division.)

Let \(f(x)=14 x-3\) and \(g(x)=8 x^{2} .\) Find the indicated value. \((f+g)(-4)\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.