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Use a graphing utility to graph the rational function. Determine the domain of the function and identify any asymptotes. $$y=\frac{12-2 x-x^{2}}{2(4+x)}$$

Short Answer

Expert verified
The domain of the function \(y=\frac{12-2x-x^2}{2(4+x)}\) is \(-\infty, -4\) union \(-4, \infty\). The function has a vertical asymptote at \(x = -4\) and does not have a horizontal asymptote.

Step by step solution

01

Understand the Function Structure

The rational function is : \(y=\frac{12-2x-x^2}{2(4+x)}\). This function is of the form \(y=\frac{f(x)}{g(x)}\), where \(f(x) = 12-2x-x^2\) is the numerator function, and \(g(x) = 2(4 + x)\) is the denominator function.
02

Determine the Domain

The domain of a function is the set of all possible input values (often denoted as \(x\) values) which will produce a valid output. Here, the only values that can't work are those that make the denominator equals zero. Hence solve for \(x\) in the equation \(2(4+x)=0\). We get \(x=-4\). So, the domain of the function is all real numbers except -4. In interval notation, this is \(-\infty, -4\) union \(-4, \infty\).
03

Find the Vertical Asymptote

Vertical asymptotes can be found by setting the denominator equals to zero and solving for \(x\). From step 2, we know that the denominator equals zero when \(x=-4\). Therefore, \(x=-4\) is a vertical asymptote.
04

Find the Horizontal Asymptote

A horizontal asymptote refers to the behavior of the graph as x approaches positive or negative infinity. The degree of the numerator function is 2 and that of the denominator function is 1. Since the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
When graphing rational functions, understanding the domain is critical. The domain of a function consists of all the possible values of x that can be plugged into the function without causing any mathematical errors. For rational functions like \(y=\frac{12-2x-x^{oindent 2}}{2(4+x)}\), we need to be careful about where the denominator equals zero since division by zero is undefined.

For our function, setting the denominator \(2(4+x)\) equal to zero and solving for \(x\) gives us \(x=-4\), indicating that \(x\) cannot take the value of -4. Consequently, the domain covers all real numbers except -4, which is expressed in interval notation as \(-(\infty, -4)\) union \((-4, \infty)\). Identifying the domain is a fundamental step in graphing as it informs us of the 'legal' inputs and helps predict the behavior of the graph.

In plotting or analyzing functions, a domain restriction like \(x eq -4\) is a vital piece of information that lays the foundation for understanding the function's behavior more comprehensively.
Vertical Asymptote
A vertical asymptote represents a value of x towards which the function grows indefinitely in either positive or negative direction. In simple terms, as the graph approaches this line, the function values either shoot up to infinity or plummet down to negative infinity. To find vertical asymptotes, we look at values where the denominator of our rational function is zero, because these are points where the function is not defined.

In our example \(y=\frac{12-2x-x^{2}}{2(4+x)}\), the denominator setting \(2(4+x)=0\) gives us the vertical asymptote at \(x=-4\). This equation tells us that as our x-values get closer and closer to -4, the y-values become larger and larger in absolute value—meaning the graph will form a near-vertical line on both sides of \(x=-4\), but will never cross this line. Understanding where the vertical asymptotes are is crucial when sketching the graph of a rational function, as it highlights important boundaries that the graph cannot cross.
Horizontal Asymptote
While vertical asymptotes are concerned with undefined x-values, horizontal asymptotes pertain to the behavior of a function as x takes on very large positive or negative values. Horizontal asymptotes indicate the value that the function approaches as x heads towards negative or positive infinity. In the case of rational functions, the horizontal asymptote is generally determined by the degrees of the numerator and the denominator polynomials.

For the function \(y=\frac{12-2x-x^{2}}{2(4+x)}\), we see that the degree of the numerator (which is 2) is higher than the degree of the denominator (which is 1). As a rule of thumb, if the numerator's degree is higher than the denominator's degree—as in our example—there will be no horizontal asymptote because the function's values will keep increasing or decreasing without leveling off. If the degrees are equal, the horizontal asymptote would be the ratio of the leading coefficients. If the numerator's degree is less, the horizontal asymptote would be the x-axis, referenced as y=0. Understanding horizontal asymptotes helps predict the end behavior of a graph and is a key element of analyzing the overall shape of rational functions.

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Most popular questions from this chapter

A real zero of the numerator of a rational function \(f\) is \(x=c .\) Must \(x=c\) also be a zero of \(f ?\) Explain.

The endpoints of the interval over which distinct vision is possible are called the near point and far point of the eye (see figure). With increasing age, these points normally change. The table shows the approximate near points \(y\) (in inches) for various ages \(x\) (in years). $$\begin{array}{|c|c|} \hline \text { Age, \(x\) } & \text { Near point, \(y\) } \\ \hline 16 & 3.0 \\ 32 & 4.7 \\ 44 & 9.8 \\ 50 & 19.7 \\ 60 & 39.7 \\ \hline \end{array}$$ (a) Find a rational model for the data. Take the reciprocals of the near points to generate the points \(\left(x, \frac{1}{y}\right).\) Use the regression feature of a graphing utility to find a linear model for the data. The resulting line has the form \(\frac{1}{y}=a x+b.\) Solve for \(y.\) (b) Use the table feature of the graphing utility to create a table showing the predicted near point based on the model for each of the ages in the original table. (c) Do you think the model can be used to predict the near point for a person who is 70 years old? Explain.

Find the zeros (if any) of the rational function. Use a graphing utility to verify your answer. $$h(x)=\frac{2 x^{2}+11 x+5}{3 x^{2}+13 x-10}$$

Consider a physics laboratory experiment designed to determine an unknown mass. A flexible metal meter stick is clamped to a table with 50 centimeters overhanging the edge (see figure). Known masses \(M\) ranging from 200 grams to 2000 grams are attached to the end of the meter stick. For each mass, the meter stick is displaced vertically and then allowed to oscillate. The average time \(t\) (in seconds) of one oscillation for each mass is recorded in the table. $$\begin{array}{|c|c|} \hline \text { Mass, \(M\) } & \text { Time, \(t\) } \\ \hline 200 & 0.450 \\ 400 & 0.597 \\ 600 & 0.712 \\ 800 & 0.831 \\ 1000 & 0.906 \\ 1200 & 1.003 \\ 1400 & 1.088 \\ 1600 & 1.126 \\ 1800 & 1.218 \\ 2000 & 1.338 \\ \hline \end{array}$$ A model for the data is given by $$t=\frac{38 M+16,965}{10(M+5000)}$$ (a) Use the table feature of a graphing utility to create a table showing the estimated time based on the model for each of the masses shown in the table. What can you conclude? (b) Use the model to approximate the mass of an object when the average time for one oscillation is 1.056 seconds.

Write the general form of the equation of the line that passes through the points. $$(-6,1),(4,-5)$$

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