/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Does the graph of the quadratic ... [FREE SOLUTION] | 91Ó°ÊÓ

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Does the graph of the quadratic function \(f(x)=-3 x^{2}+5 x+2\) have a relative minimum value at its vertex?

Short Answer

Expert verified
No, the graph of the function \(f(x)=-3 x^{2}+5 x+2\) does not have a relative minimum value at its vertex.

Step by step solution

01

Determine the direction of the parabola

Look at the coefficient of the \(x^{2}\) term in the quadratic function \(f(x)=-3 x^{2}+5 x+2\). In this case, the coefficient is -3 which is less than 0. So our function will be an upside down parabola or downward-facing parabola.
02

Conclusion

Because our function \(f(x)=-3 x^{2}+5 x+2\) is a downward-facing parabola, it opens 'downwards’. Therefore, the vertex of the parabola is the 'highest' point and represents a relative maximum, not a relative minimum of the function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Maximum and Minimum
Understanding the concepts of relative maximum and minimum in quadratic functions is crucial for analyzing the behavior of their graphs. In a quadratic function, such as our example function, the highest or lowest point is known as the vertex. The term 'relative' signifies that we are looking at the function within a specific interval and not necessarily the entire set of real numbers.

The relative maximum is the highest point within that interval, and conversely, the relative minimum is the lowest point. As we know, a quadratic function's graph is shaped like a parabola, and this parabola can either open upwards or downwards. When the parabola opens upwards, the vertex is at the bottom, indicating a relative minimum. If the parabola opens downwards, like in the case of the function \(f(x)=-3x^2+5x+2\), the vertex is at the top, representing a relative maximum. This is counter-intuitive to some as they associate 'maximum' with a positive coefficient of \(x^2\), but it's the direction of the parabola's opening that truly matters.
Vertex of a Parabola
Determination of the vertex of a parabola is a foundational component of analyzing quadratic functions. The vertex represents a pivotal point on the graph as it is the location at which the function's rate of change switches direction. The vertex can be found using the formula \( h = -\frac{b}{2a} \) where \(a\) and \(b\) represent the coefficients in the standard form \(ax^2 + bx + c\) of the quadratic equation.

For our exercise function \(f(x)=-3x^2+5x+2\), applying the vertex formula yields the \(x\)-coordinate of the vertex. Once \( h \) is determined, one can plug it back into the function to find the \(y\)-coordinate, \( k \), completing the vertex as \( (h, k) \). The vertex is not only the highest or lowest point on the graph but also reflects the axis of symmetry for the parabola, thereby serving as a crucial aspect of understanding the shape and characteristics of the function's graph.
Direction of a Parabola
The direction in which a parabola opens – upward or downward – is pivotal in understanding the nature of a quadratic function's graph. This direction is determined by the sign of the coefficient of the \(x^2\) term. If this coefficient is positive, the parabola opens upwards, like a regular 'U' shape. Conversely, if the coefficient is negative, the parabola opens downwards, resembling an upside-down 'U'.

In our example, the function \(f(x)=-3x^2+5x+2\) has a negative coefficient of \(x^2\), which is -3. This indicates that the parabola opens downwards. Thus, any point on the graph is either on the same level or below the vertex, marking the vertex as a relative maximum. The direction of the parabola is not only essential for identifying the vertex and its relative maximum or minimum but also affects the range of the function and assists in graphing the function accurately.

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Most popular questions from this chapter

The height \(y\) (in feet) of a punted football is approximated by \(y=-\frac{16}{2025} x^{2}+\frac{9}{5} x+\frac{3}{2}\) where \(x\) is the horizontal distance (in feet) from where the football is punted. (See figure.) (a) Use a graphing utility to graph the path of the football. (b) How high is the football when it is punted? (Hint: Find \(y\) when \(x=0 .\) ) (c) What is the maximum height of the football? (d) How far from the punter does the football strike the ground?

(a) use Descartes's Rule of Signs to determine the possible numbers of positive and negative real zeros of \(f\) (b) list the possible rational zeros of \(f,\) (c) use a graphing utility to graph \(f\) so that some of the possible zeros in parts (a) and (b) can be disregarded, and (d) determine all the real zeros of \(f\). $$f(x)=-2 x^{4}+13 x^{3}-21 x^{2}+2 x+8$$

Use a graphing utility to graph the function. Explain why there is no vertical asymptote when a superficial examination of the function might indicate that there should be one. $$g(x)=\frac{x^{2}+x-2}{x-1}$$

Write the standard form of the quadratic function that has the indicated vertex and whose graph passes through the given point. Use a graphing utility to verify your result. Vertex: (-2,5) Point: (0,9)

Find all the zeros of the function and write the polynomial as a product of linear factors. Use a graphing utility to verify your results graphically. (If possible, use the graphing utility to verify the imaginary zeros.) $$f(x)=x^{2}-12 x+26$$

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