/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Perform the operation and write ... [FREE SOLUTION] | 91Ó°ÊÓ

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Perform the operation and write the result in standard form. $$\frac{i}{3-2 i}+\frac{2 i}{3+8 i}$$

Short Answer

Expert verified
The result in standard form of the given operation \(\frac{i}{3-2 i}+\frac{2 i}{3+8i}\) is \(0.15 - 0.14i\)

Step by step solution

01

Rationalize the denominators

In order to rationalize the denominator, multiply both the numerator and denominator by the conjugate of the denominator of the fractions. \nThe conjugate of \(3 - 2i\) is \(3 + 2i\) and of \(3 + 8i\) is \(3 - 8i\). Hence, \(\frac{i}{3-2 i} \times \frac{3+2i}{3+2i} + \frac{2 i}{3+8 i} \times \frac{3-8i}{3-8i}\)
02

Simplify the expressions

Now, simplify the expressions obtained in step 1 using the rule \(i^2=-1\) and the property \((a + bi)(a - bi)=a^2 + b^2\).\nAfter simplification, you will get \(\frac{3i+2}{13} + \frac{6-16i}{73}\)
03

Combine the fractions

Next, write these complex numbers in standard form: \(\frac{2}{13} + \frac{3i}{13} +\frac{6}{73} -\frac{16i}{73}\)
04

Combine Like Terms

After simplifying, combine like terms.\nThe answer will be: \(0.15 - 0.14i\) which is the standard form of the result.

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